Show result in a UITextField - php

Question

I am facing a problem with fill (text field) with result which requested from MySql via a PHP file. I did change the PHP file to a different ways but I still have the same problem.
Her is my PHP file:
<?php
$host="localhost"; // Host name
$username="UserName"; // Mysql username
$password="PassWord"; // Mysql password
$db_name="DataBase"; // Database name
$tbl_name="Table"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
mysql_set_charset('utf8');
// To protect MySQL injection (more detail about MySQL injection)
$userName = $_REQUEST['userName'];
$userName = stripslashes($userName);
$userName = mysql_real_escape_string($userName);
$userName = html_entity_decode($_REQUEST['userName'], ENT_QUOTES, "UTF-8");
$sql="SELECT * FROM $tbl_name WHERE userName = '$userName'";
mysql_query("SET NAMES 'utf8'"); //5
$result = mysql_query($sql);
// Mysql_num_row is counting table row
$count = mysql_num_rows($result);
$count = 1;
$items;
while($row = mysql_fetch_array($result)) {
$item['userName'] = $row['userName'];
$item['emailAddress'] = $row['emailAddress'];
$items[$count] = $item;
}
//echo json_encode($items);
echo json_encode($items, JSON_UNESCAPED_UNICODE);
?>
Her is the Objective-c code (in Xcode):
- (id)makeURLRequestWithString:(NSString *)url {
[UIApplication sharedApplication].networkActivityIndicatorVisible = YES;
NSURLRequest *urlRequest = [NSURLRequest requestWithURL:[NSURL URLWithString:url]
cachePolicy:NSURLRequestReloadIgnoringCacheData
timeoutInterval:10];
NSURLResponse *response;
NSError *error;
// Make synchronous request
NSData *urlData = [NSURLConnection sendSynchronousRequest:urlRequest
returningResponse:&response
error:&error];
[UIApplication sharedApplication].networkActivityIndicatorVisible = NO;
if (urlData) {
NSDictionary *dict = [NSJSONSerialization
JSONObjectWithData:urlData
options:kNilOptions
error:&error];
return dict;
} else return error;
}
Her is the code when I press the button:
- (IBAction)callJson:(id)sender {
dispatch_queue_t jsonParsingQueue = dispatch_queue_create("jsonParsingQueue", NULL);
dispatch_async(jsonParsingQueue, ^{ //Do request on another queue to prevent it from blocking UI
id result = [self makeURLRequestWithString:#"http:/MyWebSite.com/PHPFile.php?userName=123"];
NSLog(#"%#", result);
// Her where I need to fill my text with info from the above url
// self.emailAddress.text = ...............What to do her?
});
}
Her is the result from Xcode:
{
1 = {
emailAddress = "123#hotmail.com";
userName = "123";
};
}
The request shows the data, but I don't no how to fill the text with it.
I hope my question is clear.
Thanks

Answer 1

You can parse the results into an NSDictionary/NSArray with NSJSONSerialization. If your result is a data object, you could call
NSError *err;
NSDictionary *results = [NSJSONSerialization JSONObjectWithData:data options:0 error:&err];
NSString *email = [[results objectForKey:#"1"] objectForKey:#"emailAddress"];
Then to stick it in the textbox you would just use the normal code
textbox.text = email;
EDIT:
Ok, I see now you have already thrown in the Parsing JSON in the above method. So when you are calling self.emailAddress.text You are still in a background thread with your dispatch_async() call. So in order to make it actually update the text box you would do the following right after you get id result =...
dispatch_async(dispatch_get_main_queue(), $^{
self.emailAddress.text = [[result objectForKey:#"1"] objectForKey:#"emailAddress"];
});
Another tip, it's a little weird that your JSON data starts at index 1, if it is going to be an ordered list (eg. 1, 2, 3, 4..) you should format it like an array. I think I see the problem in your PHP, it should look more like this (assuming I understand what you are trying to do):
...
while($row = mysql_fetch_array($result)) {
var $tmp = [];
$tmp['userName'] = $row['userName'];
$tmp['emailAddress'] = $row['emailAddress'];
$items[] = $tmp;
}
...
That will output an array of Items from the database with dictionaries containing the emails and usernames like so
[
{'email1', 'user1'},
{'email2', 'user2'}
]
But if you do it that way, you'd have to change your code above in the makeUrlrequestwithstring method to return an array like this:
if (urlData) {
NSArray *arr = [NSJSONSerialization
JSONObjectWithData:urlData
options:kNilOptions
error:&error];
return arr;
} else return error;
Then your output code would look like this (assuming you wanted the first item in the query result)
dispatch_async(dispatch_get_main_queue(), $^{
self.emailAddress.text = [result[0] objectForKey:#"emailAddress"];
});