PHP - Dynamic FORM > MySQL Insert - php

Question

I'm new here and I have one question.
I have one PHP-HTML Dynamic Form with this code:
<form class="insert" method="POST" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>?CategoryName=<?php echo $CategoryName; ?>">
<br/><label><?php echo $lang['CATEGORY_NAME']; ?>:</label>
<?php
$conn = new mysqli($SERVERNAME, $USERNAME, $PASSWORD, $DBNAME);
if ($conn->connect_error) {
die("Greska: " . $conn->connect_error);
}
$sql = "SELECT CategoryName FROM Categories WHERE ForUser = '$User_Check' ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<select style='text-transform: uppercase;' onchange='location = this.options[this.selectedIndex].value;' class='form-control' name='CategoryName'>";
while($row = $result->fetch_assoc()) {
echo "<option value='?CategoryName=".$row['CategoryName']."'>".$row['CategoryName']."</option>";
}
echo "</select>";
}
else {
echo "<div style='margin-top: 18px;' class='alert alert-danger'><b>$lang[MANAGE_CATEGORY_ALERT]</b></div>";
}
$conn->close();
?>
<?php
$conn = new mysqli($SERVERNAME, $USERNAME, $PASSWORD, $DBNAME);
if ($conn->connect_error) {
die("Greska: " . $conn->connect_error);
}
$sql = "SELECT FieldName FROM Fields WHERE ForUser = '$User_Check' AND ForCategory = '$CategoryName' ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "<label>".$row['FieldName'].":</label>";
echo "<input class='form-control' id='focusedInput' required type='text' placeholder='".$row['FieldName']."' name='".$row['FieldName']."'>";
}
}
else {
echo "<div style='margin-top: 18px;' class='alert alert-danger'><b>$lang[MANAGE_CATEGORY_ALERT]</b></div>";
}
$conn->close();
?>
<input class="btn btn-primary" type="submit" value="<?php echo $lang['CREATE_CATEGORY_BUTTON']; ?>">
</form>
Now I have problem when I want to insert posted data into MySQL tables because PHP don't know where to insert posted data, and doesn't know where to enter which data.
Can anyone help me?

Answer 1

Your Question is not much clear but as i can understand from the code
you have 2 tables, categories and fields . and you are rendering the form using it . when u will submit the form, u will get all the fields and 'CategoryName' which you can fetch using a $_POST variable .
I dont know in which table u want to save the data but u can easily save it like any other form .
more over u can open once in browser and save the generated file for debugging saving process so that u don't need to render again.
u can always var_dump $_POST to check the data u receive after submitting form.