php get today tomorrow and next day but ignore weekends - php

Question

How can I get the current day, tomorrow and next day in PHP but ignore weekends?
I have already tried this code, but it will include Saturday and Sunday.
array(
'todayDate' => date('d/m/Y')
'tomorrowDate' => date('d/m/Y', strtotime(' +1 day')),
'nextDay' => date('l', strtotime(' +2 day'))
)
Thanks.

Answer 1

Use Weekday(s) with strtotime
date('l', strtotime(' +2 Weekdays'));
Fiddle

Answer 2

This finds the next weekday from a specific date (not including Saturday or Sunday):
echo date('Y-m-d', strtotime('2011-04-05 +2 Weekday'));
You could also do it with a date variable of course:
$myDate = '2011-04-05';
echo date('Y-m-d', strtotime($myDate . ' +2 Weekday'));

Answer 3

Try this, Get date between two date without weekdays(Saturday and Sunday).
$startdate = '10-06-2015';
$endDate = '17-06-2015' ;
$Workingdays = getdateBettwoDate($startdate,$endDate);
print_r($Workingdays);
function getdateBettwoDate($startdate,$enddate)
{
$start = new DateTime($startdate);
$end = new DateTime($enddate);
$interval = DateInterval::createFromDateString('1 day');
$period = new DatePeriod($start, $interval, $end);
$x=0;
$a=array();
foreach ($period as $dt)
{
$temp=$dt->format("l d-m-Y");
$ArTemp=explode(' ',$temp);
if($ArTemp[0]=='Saturday' || $ArTemp[0]=='Sunday'){
}else{
$a[$x]=$ArTemp[1];
$x++ ;
}
}
$a[$x]=date('l', strtotime( $enddate))." ".$enddate;
return $a ;
}