I need to compile the php code on HTML Button click and display the compilation output on browser.I am using the following code to display the output on browser,it works well in terminal but doesn't give anything on browser.I am using XAMPP server on windows machine.
<?php
if(isset($_POST['compile'])){
$cmd="php php_part.php";
$var=system($cmd);
echo $var;
}
?>
<input type="submit" class="button" name="compile" value="Compile Code" />
First you are not compiling the php_part.php script, you are running it. Yes I realise that running a php script requires that it first be compiled or rather interpreted but that statement will execute the php_part.php script.
There are 2 likely reasons why it is not running.
When run from the browser i.e via Apache it does not know where to find php.exe
Depending on where the php_part.php script is kept it may not be able to find that either.
Try changing this statement
$cmd="php php_part.php";
to
$cmd="C:/path/to/php/php.exe C:/path/to/script/php_part.php";
If that works then that above was the problem.
I have to also say that there must be a better way of running this script. As you are in a PHP section of code would not a simple include or require not be a better solution. Something like this
<?php
if(isset($_POST['compile'])){
require "php php_part.php";
echo $var;
}
?>
Of course this depend on how you have written that php_part.php script. If you wrote it as a function then this would be a better solution
The php_part.php script
function xxx() {
// do whatever coding
return $the_result;
}
The main code
<?php
if(isset($_POST['compile'])){
require "php php_part.php";
$var = xxx();
}
?>
Related
I'm looking to run a program, and for every output line it generates, execute a PHP script and pass the line content to it.
I know, pretty hard to understand. Here's an example:
Execute script -> script outputs 'Initializing script on 127.0.0.1'. Now it needs to execute a command like php5 input.php 'Initializing script on 127.0.0.1'.
Is this doable? If so, how would I go about doing this?
Edit: to clarify; I basically want command > log.txt but in stead of writing the output to that file, writing it to a PHP script as an argument
PHP is an interpreter much like Bash, Python, etc, so you can do "normal" scripting with it. For example:
#!/usr/bin/php5
<?php
echo "Hello, world!\n";
while($line = fgets(STDIN)) {
echo "> " . $line;
}
?>
Mark the file as executable, then run:
$ /program/that/generates/lines | /path/to/your/php/script
However, contrary to your original question, it sounds to me like you actually want to use JavaScript and possibly AJAX for web purposes. Sane web applications will have the said script run in the background and safely write the results to a file or stream, using AJAX to read it and update the information on the current page.
Basically I'd like to know of a very simple method for making a php script check if a specific program is running on my nix box.
Something like :
<?php
#some detection function here.
if($detectprogram == 1){
echo("It's running.");
}
else{
echo("It's not running.");
}
?>
Or even if I had to execute the program via a .sh (as I already do) and an -outputphp /path/to/htdocs/. Or similar. Thanks.
Maybe you need this?
exec("ps auxwww|grep sample.php|grep -v grep", $output);
Source: How to get list of running php scripts using PHP exec()?
I am very new to php and I tried to write this function. Now it seems like the function is not Defined. Nothing happens when I open the php file and if I try to use console to run it. It gives an error --
contentcheck('ex1.php','Bajestani')
ReferenceError: contentcheck is not defined
The Code is below.
<?php
if(contentcheck('ex1.php','Bajestani')===true)
echo 'Got it';
function contentcheck($filename,$phrase)
{
$content = shell_exec('C:\xampp\htdocs\docman\pdftotext '.$filename.' -');
if (strpos($content,$phrase) !== false)
{
return true;
}
else
return false;
}
if(contentcheck('ex1.php','Bajestani')===true)
echo 'Got it';
?>
Thanks In advance
You state that you try to run the function from the console.
In addition, ReferenceError: contentcheck is not defined is a Javascript error, not a PHP error.
Both of these facts lead me to the conclusion that you are trying to run the PHP code from inside the browser.
Please note that PHP code is not available from within the browser -- the function will indeed be undefined if you run it in the console, because PHP is run on the web server, not in the browser. The browser will never see your PHP functions; it simply sees the output of the PHP program (eg the HTML code, etc that is printed from by your PHP program). The PHP code itself is never seen by the browser.
It's not entirely clear what your program is supposed to be doing but what is clear is that the way you're trying to run it is not going to work. You're going to have to re-think this one completely, and possibly learn a bit more about how client/server systems work, and PHP in particular.
how do you issue commands to the shell and then forget it's output and such? for example:
<?php
echo `sleep 2;echo hi`;
echo "foo";
?>
the result for this is hifoo. i would want a result that gives me foohi. why? i want the command issued to the shell simply issued and forgotten, i am confused about why PHP will wait for the result. is such a result possible?
(the idea behind this is setting up the correct number of selenium grid RC instances programatically. currently, it will stop after the first process is opened)
From php.net exec()
If a program is started with this
function, in order for it to continue
running in the background, the output
of the program must be redirected to a
file or another output stream. Failing
to do so will cause PHP to hang until
the execution of the program ends.
The same applies for all shell commands.
It's like anything you do at the command prompt, unless you take measures to put the new command in the background, the shell (and PHP ) will block until the command exits. Try this:
<?php
echo `(sleep 2; echo hi) &`;
echo 'foo';
?>
Note the brackets around your command, without that, the & woulud apply only to the echo , and you'd still have the 2 second pause.
I have a Python script I recently wrote that I call using the command line with some options. I now want a very thin web interface to call this script locally on my Mac.
I don't want to go through the minor trouble of installing mod_python or mod_wsgi on my Mac, so I was just going to do a system() or popen() from PHP to call the Python script.
Any better ideas?
Depending on what you are doing, system() or popen() may be perfect. Use system() if the Python script has no output, or if you want the Python script's output to go directly to the browser. Use popen() if you want to write data to the Python script's standard input, or read data from the Python script's standard output in php. popen() will only let you read or write, but not both. If you want both, check out proc_open(), but with two way communication between programs you need to be careful to avoid deadlocks, where each program is waiting for the other to do something.
If you want to pass user supplied data to the Python script, then the big thing to be careful about is command injection. If you aren't careful, your user could send you data like "; evilcommand ;" and make your program execute arbitrary commands against your will.
escapeshellarg() and escapeshellcmd() can help with this, but personally I like to remove everything that isn't a known good character, using something like
preg_replace('/[^a-zA-Z0-9]/', '', $str)
The shell_exec() operator will also allow you to run python scripts using similar syntax to above
In a python file called python.py:
hello = "hello"
world = "world"
print hello + " " + world
In a php file called python.php:
$python = shell_exec(python python.py);
echo $python;
You can run a python script via php, and outputs on browser.
Basically you have to call the python script this way:
$command = "python /path/to/python_script.py 2>&1";
$pid = popen( $command,"r");
while( !feof( $pid ) )
{
echo fread($pid, 256);
flush();
ob_flush();
usleep(100000);
}
pclose($pid);
Note: if you run any time.sleep() in you python code, it will not outputs the results on browser.
For full codes working, visit How to execute python script from php and show output on browser
I do this kind of thing all the time for quick-and-dirty scripts. It's quite common to have a CGI or PHP script that just uses system/popen to call some external program.
Just be extra careful if your web server is open to the internet at large. Be sure to sanitize your GET/POST input in this case so as to not allow attackers to run arbitrary commands on your machine.
Your call_python_file.php should look like this:
<?php
$item='Everything is awesome!!';
$tmp = exec("py.py $item");
echo $tmp;
?>
This executes the python script and outputs the result to the browser.
While in your python script the (sys.argv[1:]) variable will bring in all your arguments. To display the argv as a string for wherever your php is pulling from so if you want to do a text area:
import sys
list1 = ' '.join(sys.argv[1:])
def main():
print list1
if __name__ == '__main__':
main()
The above methods seems to be complex. Use my method as a reference.
I have this two files
run.php
mkdir.py
Here, I've created a html page which contains GO button. Whenever you press this button a new folder will be created in directory whose path you have mentioned.
run.php
<html>
<body>
<head>
<title>
run
</title>
</head>
<form method="post">
<input type="submit" value="GO" name="GO">
</form>
</body>
</html>
<?php
if(isset($_POST['GO']))
{
shell_exec("python /var/www/html/lab/mkdir.py");
echo"success";
}
?>
mkdir.py
#!/usr/bin/env python
import os
os.makedirs("thisfolder");
Note that if you are using a virtual environment (as in shared hosting) then you must adjust your path to python, e.g: /home/user/mypython/bin/python ./cgi-bin/test.py
is so easy 😁
You can use [phpy - library for php][1]
php file
<?php
require_once "vendor/autoload.php";
use app\core\App;
$app = new App();
$python = $app->python;
$output = $python->set(your python path)->send(data..)->gen();
var_dump($ouput);
python file:
import include.library.phpy as phpy
print(phpy.get_data(number of data , first = 1 , two =2 ...))
you can see also example in github page
[1]: https://github.com/Raeen123/phpy
If you want to execute your Python script in PHP, it's necessary to do this command in your php script:
exec('your script python.py')