I have a file manager website running and some users said they'd like to be able to embed the image preview page directly into img tags (on forums etc).
Lets take this page as an example: http://push.anukthewolf.com/a/Screenshot_2015-06-03-08-29-03.png
Even though it has an image extension, it's still a html (well, php) page. Could this script somehow detect if its requesting client is a browser parsing an img tag where its url has been used as source?
If that's the case I would output the image directly instead of the website. In every other case, the website should be sent.
Related
So I have an img that, when clicked, takes the user to another page (via surrounding anchor tag). The img gets its src from a PHP script that returns the image data and logs it. Before redirecting the user to the desired page, they are directed to a PHP script that logs the redirect then serves the redirection.
I'd like to be able to associate the served image with the served click when Javascript is disabled. Cookies don't seem to work because say for instance the user has multiple tabs or windows opened with the same served image, and clicks one of them. Which one got clicked?
PHP doesn't work because we have no control over the page that hosts the anchor and the img tags.
I'd like to have this information for analytics purposes.
Is it possible and if so how? Thanks!
Now, I am encountering some difficulties when I have to scan or crawl a video URL link. This web page is using the Flash-based technology to embed the video and stream video.
In order to understand more clearly, this is a link example:
http://vnexpress.net/gl/the-gioi/tu-lieu/2012/11/bai-phat-bieu-thua-nhan-that-bai-cua-romney/
The above link has below content (HTML code for Flash embedded video):
<div id="flashContent" style="text-align:center;width:100%;">
<span id="FlashPlayer79237" class="Normal" align="center">Bạn cần cài Flash Player để xem được Clip này.</span>
</div>
In this above article, there is a above video. However, when I tried to scan or crawl the content, the video could not run properly (because it could not load correct video link) and only show Install Flash Player plugin words (Certainly, the real web page needs to run some Javascript script or Flash script to obtain the real video link and stream this video for users)
Therefore, how can I render Flash and Javascript script through PHP or ASP.NET or Java? How can I get the correct video link when I crawl the web page? In this case, how can I obtain the correct Flash embedded video (HTML code)?
Thank you so much.
Before I answer, I want to make a note that if you need this information to do anything shady... please don't.
Disclaimer aside, for that particular site it is relatively easy.
The flashvars param (which is probably put there by Javascript) contains a value called xmlPath, which is a url encoded path (relative to their domain name). If you grab that and decode it, you get something like:
/Service/FlashVideo/PlayListVideoPage.asp?id=79237&f=108&t=1
which points to
http://vnexpress.net/Service/FlashVideo/PlayListVideoPage.asp?id=79237&f=108&t=1
If you read that, it's an XML file which contains the URL of the actual video.
I'm not quite sure where that value is generated from. If you needed to do this fully server-side, you could use a headless browser to process it.
I want to get FLV file url of the webpage with automation, is it possible? because that site has no autoplay, when i use GetFLV i get the url on when i press play button, i need to get url in php code'automatically, How to do it?
Retrieve the HTML of the page (using a library such as cURL)
Parse the retrieved HTML (using a library such as the PHP DOM)
Extract the relevant URL from the DOM tree
It is possible the URL was generated via JavaScript, in which case you'll also need to run a JS interpreter or close facsimile thereof.
P.S. - remember to check that doing this does not violate the web site's terms of service.
I am looking for some help in downloading pics from a website. Here is the problem detail.
URL is basvandenbroek dot com,
suppose when we visit the following page http://www.basvandenbroek.com/nl/product/27341/704/snaarinstrumenten/boston/snarenset_elektrisch.html
we have a thumbnail pic here which when click bring its larger version. I would like to capture the larger image using a php script and download it onto my pc.
Problem is when we inspect the HTML we see the following code for images
../../../../../../../jpg/27000/27341.jpg
../../../../../../../jpg/cache/27000/220_220_27341.jpg
Based on the above code i assume that if i append website address at the start of the
jpg/27000/27341.jpg I could access the pic but its not working it that.
I believe URL is hidden or I might not understanding things properly. I am new to PHP and Scripting and I would like somebody to help me through it situation.
Thank you
For the website you mentioned, if the thumbnail is
http://www.basvandenbroek.com/jpg/cache/27000/220_220_27341.jpg
then the
http://www.basvandenbroek.com/jpg/27000/27341.jpg
So the thumbnail is basically the dimensions (220 x 220) added as a prefix to the original in a different folder. Also, there is nothing like hidden URL. Any link that is valid on a web-page is sure to appear in the source of the html. In chrome and firefox, atleat, you can find this link by right-clicking the link and copying the link address.
In your case you can find the thumbnail's url by right-clicking the thumbnail and the original's url by right-clicking it.
However, if you want to do this automatically using PHP, you will have to write code that can parse the html for the page to determine the urls.
In your example, here would be the larger image:
http://www.basvandenbroek.com/jpg/27000/27341.jpg
The smaller image is at:
http://www.basvandenbroek.com/jpg/cache/27000/220_220_27341.jpg
This means you would need to scrape out the first two underscored parts of the name (220_220) using string manipulation. You would also want to string replace "cache/" with an empty string.
relative urls are relative to the url of the containing document. so if the document you're scraping is located at http://example.com/foo/bar/baz/doc.html, and the image is referenced as
../../omg/wtf/lol/cat.jpeg, its full url is http://example.com/foo/bar/baz/../../omg/wtf/lol/cat.jpeg, or http://example.com/foo/omg/wtf/lol/cat.jpeg.
btw, this has nothing to do with PHP or scripting in general, and is instead firmly a HTTP thing. and there are no "hidden" URLs in HTTP, that would be a contradiction.
edit: your comment makes it look like the problem is with the Referer header or session id sent (or not) in your request.
How should i create a preview of image to be uploaded before it is actually submitted using AJAX in PHP?
Without uploading the image, this is going to be impossible in JavaScript as far as I can see, because security limitations are going to prevent you from determining the selected file in the file upload, and embedding that file in an img tag (as it used to be possible five years ago.)
You will be more lucky with Flash-based uploaders. I have seen some that offer the kind of functionality you want.
Update: Here's one that offers a preview function. From what I can see, it base64 encodes the local image and serves it to the surrounding HTML page as a inline data <img> tag. This is great because it might integrate well into your site. It does not work with any version of Internet Explorer, though.
Here's a fully Flash based solution that does previews in all browsers.
you first have to upload the document to server. Than you can show like.
<img src="uploads/file1_12224.jpg" />
The "file" input type doesn't expose the local file location of the file to be uploaded. It does "appear" to because as a user you can see the location, but the web page never knows this value. Without the local file address, you can't show a preview of the image on the web page using plain HTML or JavaScript.