php wont return json data from db - php

Question

I've seen a few similar questions and tried the fixes and they are not working. Any help would be greatly appreciated.
I'm trying to return some data from the database as JSON.
Here is my code:
<?php
$db = "signup";
$servername = "localhost";
$username = "username";
$password = "password";
$fetch = ("SELECT * FROM bookings");
$return_arr = array();
$conn = new mysqli($servername, $username, $password, $db); // working
$query_result = mysqli_query($conn, $fetch);
mysqli_select_db("bookings",$db);
while ($row = mysqli_fetch_array($query_result, MYSQL_ASSOC)) {
$return_arr[] = array(
'TIMESLOT' => $row['TIMESLOT'],
'USERPIN' => $row['USERPIN'],
'PLAYERS' => $row['PLAYERS'],
'ACCEPTED' => $row['ACCEPTED'],
'EMAIL' => $row['EMAIL'],
'TOTAL BOOKINGS' => $row['TOTALBOOKINGS'],
'BOOKING ID' => $row['BOOKINGID'],
'LAST BOOKING' => $row['LASTBOOKING'],
'DATE' => $row['DATE']
);
}
$user = json_encode($return_arr);
echo "<pre>";
print_r($return_arr);
echo "</pre>";
mysqli_close($conn);
?>
Now I'm getting this information back from the database:
Array
(
[0] => Array
(
[TIMESLOT] => 12:00-14:00
[USERPIN] => 25225649
[PLAYERS] => 4
[ACCEPTED] => 0
[EMAIL] => email#address.com
[TOTAL BOOKINGS] => 0
[BOOKING ID] => 1
[LAST BOOKING] => 0000,00,00
[DATE] => 0000,00,00
)
)

Answer 1

I would change the while to this:
//...
$conn = new mysqli($servername, $username, $password, $db); // working
$query_result = mysqli_query($conn, "SELECT * FROM bookings");
//...
// Option 1 : Change MYSQL_ASSOC to MYSQLI_ASSOC
while ($row = mysqli_fetch_array($query_result, MYSQLI_ASSOC)) {
// Option 2 : Change to mysqli_fetch_assoc
// while ($row = mysqli_fetch_assoc($query_result)) {
// Debug
echo "<pre>";
print_r($row);
echo "</pre>";
$return_arr[] = array($row['BOOKINGID'],
$row['USERPIN'],
$row['TIMESLOT'],
$row['PLAYERS'],
$row['ACCEPTED'],
$row['EMAIL'],
$row['TOTALBOOKINGS'],
$row['LASTBOOKING'],
$row['DATE']
);
}
See that I added brackets to $return_arr, otherwise you'll be changing the value of the array and you'll get only the last one.
After that remove the "[0]" from the $return_arr[0]. This way you'll have the entire array encoded to json.

Answer 2

Try this code
$conn = new mysqli($servername, $username, $password, $db); // working
$sql = ""; // your query
$result = $conn->query($sql);
while($row = $result->fetch_array()) {
// Create results array
$rows[] = array(
'BOOKINGID' => $row['BOOKINGID'],
'USERPIN' => $row['USERPIN'],
// and go on....
);
}
mysqli_close($conn);
echo json_encode($rows[0]);