JSON object passed in the php script [closed] - php

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I have a PHP script and JSON object with some values is being passed in the the PHP get function. I have tried different ways to decode JSON but failed.
The code I have tried is :
$get_order_info = $_GET['orderInfo'];
$order_json = json_decode($get_order_info, true);
echo $order_json->{'mealsInfo'};
The JSON string is :
{
"mealsInfo" : [
{
"DrinkSize" : 1,
"MealQuantity" : 1,
"MealId" : "57",
"addons" : [
{
"addOnID" : 1,
"addonTitle" : "spicy"
},
{
"addOnID" : 3,
"addonTitle" : "Thin Base"
}
],
"FriesSize" : 2
}
],
"TransactionID" : "56",
"OrerType" : "PickUp",
"frenchiseInfo" : {
"storeName" : "Dubai Downtown Franchise",
"OrderCollectionTime" : "06:12:50 PM",
"FranchiseId" : "4"
},
"customerinfo" : {
"Instructions" : "Test instruction",
"CustomerName’" : "Talat",
"Area" : "al Riga",
"City" : "Dubai",
"Phone" : "0559467800",
"Email" : "test#test.com",
"Address" : "al nouf tower"
},
"status" : "pending",
"totalPrice" : 51
}
Can somebody please help me to decode it in a correct way?
Thanks in advance !

Answer 1

You are passing true as second parameter to json_decode, it will return and array not object. Try with -
$order_json = json_decode($get_order_info, true);
echo $order_json['mealsInfo'][0]['DrinkSize'];

Answer 2

$get_order_info = $_POST['orderInfo'];
$order_json = json_decode($get_order_info, true);
echo $order_json->{'mealsInfo'};

Answer 3

Try this.
$order_json = json_decode($get_order_info, true);
var_dump($order_json->{'mealsInfo'});