PHP in_array not working with current array structure - php

Question

I am using a custom method to return a query as an array.
This is being used to check if a discount code posted is in the DB.
The array ends up as example:
Array
(
[0] => stdClass Object
(
[code] => SS2015
)
[1] => stdClass Object
(
[code] => SS2016
)
)
So when I am trying to do:
if ( ! in_array($discount_code, $valid_codes)) {
}
Its not working. Is there a way I can still use the function for query to array I am using and check if its in the array?
No issues, I can make a plain array of the codes but just wanted to keep things consistent.

Answer 1

Read about json_encode (serialize data to json) and json_decode (return associative array from serialized json, if secondary param is true). Also array_column gets values by field name. so we have array of values in 1 dimensional array, then let's check with in_array.
function isInCodes($code, $codes) {
$codes = json_encode($codes); // serialize array of objects to json
$codes = json_decode($codes, true); // unserialize json to associative array
$codes = array_column($codes, 'code'); // build 1 dimensional array of code fields
return in_array($code, $codes); // check if exists
}
if(!isInCodes($discount_code, $valid_codes)) {
// do something
}

Answer 2

Use array_filter() to identify the objects having property code equal with $discount_code:
$in_array = array_filter(
$valid_codes,
function ($item) use ($discount_code) {
return $item->code == $discount_code;
}
);
if (! count($in_array)) {
// $discount_code is not in $valid_codes
}
If you need to do the same check many times, in different files, you can convert the above code snippet to a function:
function code_in_array($code, array $array)
{
return count(
array_filter(
$array,
function ($item) use ($code) {
return $item->code == $code;
}
)
) != 0;
}
if (! code_in_array($discount_code, $valid_codes)) {
// ...
}

Answer 3

try this
function in_array_r($needle, $haystack, $strict = false) {
foreach ($haystack as $item) {
if (($strict ? $item === $needle : $item == $needle) || (is_array($item) && in_array_r($needle, $item, $strict))) {
return true;
}
}
return false;
}
then
echo in_array_r("SS2015", $array) ? 'found' : 'not found';

Answer 4

why not solve it as a school task - fast and easy:
for($i = 0; $i < count($valid_codes); $i++) if ($valid_codes[$]->code == $discount_code) break;
if ( ! ($i < count($valid_codes))) { // not in array
}