I am new in php and mysql,want to file upload with three input and also move upload file in my project folder. this is my code.
if(isset($_POST['submit']))
$birthcertificate = $_FILES['file1']['name'];
$temp_name = $_FILES['file1']['tmp_name'];
if(isset($birthcertificate)){
if(!empty($birthcertificate)){
$location = '.images/';
if(move_uploaded_file($temp_name, $location.$birthcertificate)){
echo 'File uploaded successfully';
}
}
} else {
echo 'You should select a file to upload !!';
}
$sql = "insert into tabel(......)values($birh..,$pclaa..,$transfer..);
error:
undefined index and warning in move_upload file
So i want my page to show the image whose path I am getting from the mysql database and displaying on the same screen. This is my code, I have tried everything, please let me know where I'm going wrong.
while ($row = mysqli_fetch_array($return_data)) {
echo "ID:".$row['demo_id']."<br>";
echo "Name: ".$row['demo_name']."<br>";
echo "Version: ".$row['demo_version']."<br>";
echo "Details: ".$row['demo_details']."<br>";
echo "File Link: ".$row['file']."<br>";
$new = $row['file'];
echo '<img src = \"$new\"/>';
}
mysqli_free_result($return_data);
echo "Data retrieved successfully!"."<br>";
?>
<img src = "<?php echo $new?>">
echo "File Link: " returns me the whole path of the uploaded file.
How do I render the image at that path in the same page?
neither of the image tags are working. Thanks in advance!
edit
File Link: C:/Apache24/htdocs/demo_webpages_project/neweruploads/footer.jpg
this is the path I get as an output.
Basically this is the folder where I have uploaded the image from another php file
<?php
//this module is used to temporarily store the uploaded file to the server
$target_dir = "random/"; //we randomly assign a value to the upload target directory
$target_file = $target_dir . basename($_FILES["image_file"]["name"]); /*here ["name"] is the original name of the file before it was updated
target file is assigned this name by appending it to the $targer_dir
now target_file is the uploaded file name along with the path*/
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);/*this returns various kind of info about the path for eg Directory, Basename
in our case it returns extension of the file*/
//this sub module is to check whether the file is really an image file
if(isset($_POST["submit"])) { //isset is used to confirm whether the value has actually being submitted
$check = getimagesize($_FILES["image_file"]["tmp_name"]);/*here ["tmp_name"] is the location of temporary file on server
getimagesize confirms image format by returning dimensions etc*/
if($check !== false) {
echo "A file is of an image format<br>";
}
else {
echo "The file is not an image!<br>";
}
}
//Test module to upload files to a destination directory and check whether they have been uploaded or not
if (is_uploaded_file($_FILES['image_file']['tmp_name']) && $_FILES['image_file']['error']==0) { /*code to check two things: 1. whether the file exists in the temp memory 2. whether the file has any error*/
$path = 'C:\Apache24\htdocs\demo_webpages_project\neweruploads\\' . $_FILES['image_file']['name']; /*this sets the destination directory(along with expected file name)*/
if (!file_exists($path)) { //if the file does not exists at that path
if (move_uploaded_file($_FILES['image_file']['tmp_name'], $path)) { //use the php file move function to move it
echo "The file was uploaded successfully."; //success
}
else {
echo "The file was not uploaded successfully."; //failure
}
}
else {
echo "File already exists. Please upload another file."; //detects existence of file with exact same name
}
}
else {
echo "The file was not uploaded successfully."; //if any problem with original uploading
echo "(Error Code:" . $_FILES['image_file']['error'] . ")";
}
?>
Does this help?
edit 2
http://localhost:8080/demo_webpages_project/download.php?project_name=footer&version=&submit=Search
this is my local directory path.
the solution you provided is allowing me to read images which are in the demo_webpages_project folder pointing directly there), not to neweruploads folder
If your uploaded files are stored in the neweruploads subdirectory, then replace this code:
$new = $row['file'];
echo '<img src = \"$new\"/>';
By this one :
$new = basename( $row['file'] ); // GET FILE NAME ONLY, GET RID OF PATH.
echo '<img src = \"neweruploads/$new\"/>'; // FILENAME WITH UPLOAD PATH.
▲
I use this script to upload files via POST from my android app to my server. 95% of the time it works ok, but sometimes the upload folder of my clients is empty. The file is sent definitely, because I get the name and phone numbers (without a file selected the app will not pass any data), but the uploaded file is not written to disk on the server. I am not an expert in php, maybe I have missed something:
My upload php script:
$file_path = "uploads/{$_POST['name']}/";
if (!file_exists("uploads/{$_POST['name']}")) {
mkdir("uploads/{$_POST['name']}", 0777, true);
} else {
echo 'folder already exists!';
}
$newfile = $_POST['name'] . "_" . date('m-d_H-i-s') . '.zip';
$filename = $file_path . $newfile;
if(!file_exists($filename)) {
if(move_uploaded_file($_FILES['zipFile']['tmp_name'], $filename)) {
echo "success";
}
} else {
echo 'file already exists';
}
I am trying to upload an image to the server (with a path in mysql table) twice through php with different names. One version of the image as "xxxx.png" and the other version of the image as "xxxxt.png".
My php is:
<?php
if ($_FILES['photo']) {
$target = "images/properties/";
$target = $target . basename( $_FILES['photo']['name']);
$pic = "images/properties/" .(mysql_real_escape_string($_FILES['photo']['name']));
if (move_uploaded_file($_FILES['photo']['tmp_name'], $target)) {
mysql_query("INSERT INTO `images` (`productcode`, `photo`) VALUES ('$productcode', '$pic' )");
echo "The new image has been added successfully";
} else {
echo "Error uploading new image - please check the format and size";
}
}
?>
The above code inserts the image into the mysql database and uploads the file to the server correctly.
I am however trying to upload the same image twice with a different naming convention on a "thumbnail" version. The slideshow script in my html only recognises the thumbnails if there are named with a "t" at the end of the filenames hence my problem.
I have been advised to look at the php copy() function to achieve this but am incredibly unclear as to how to incorporate such a function into my existing code.
Happy to provide the html or any other info if required.
Any help much appreciated. I did have another thread attempting to find out the same thing but I wasn't very clear!
Thanks
JD
If I correctly understand you, you do not need to upload this file twice. You already have this file on your server. So you should copy it (optionally do some transitions to make it more like a thumbnail) on your server's hard drive and update database.
Your code should like similar to this:
<?php
if($_FILES['photo'])
{
$target_dir = "images/properties/";
$upload_file_name = basename( $_FILES['photo']['name']);
$upload_file_ext = pathinfo($_FILES['photo']['name'], PATHINFO_EXTENSION);
$target_file = $target_dir . $upload_file_name . '.' . $upload_file_ext;
$target_file_sql = $target_dir . mysql_real_escape_string($upload_file_name . '.' . $upload_file_ext);
$target_thumb = $target_dir . $upload_file_name . 't.' . $upload_file_ext;
$target_thumb_sql = $target_dir . mysql_real_escape_string($upload_file_name . 't.' . $upload_file_ext);
if (move_uploaded_file($_FILES['photo']['tmp_name'], $target_file))
{
mysql_query("INSERT INTO `images` (`productcode`, `photo`) VALUES ('$productcode', '$target_file_sql' )");
echo "The new image has been added successfully";
if (copy($target_file, $target_thumb))
{
mysql_query("INSERT INTO `images` (`productcode`, `photo`) VALUES ('$productcode', '$target_thumb_sql' )");
echo "The new thumb image has been added successfully";
} else
{
echo "Error copying thumb file";
}
} else
{
echo "Error uploading new image - please check the format and size";
}
}
Again, the idea is that you do not need to upload file twice in a row. All you need to do is just copy it on server.
As you've been advised you should use copy(). I didn't fully test this but give it a try:
<?php
if ($_FILES['photo'])
{
$target = "images/properties/";
$ext = array_pop(explode('.', $_FILES['photo']['name']));
$copy = $target . basename($_FILES['photo']['name'], '.' . $ext) . 't.' . $ext;
$target = $target . basename($_FILES['photo']['name']);
$pic = "images/properties/" .(mysql_real_escape_string($_FILES['photo']['name']));
if (move_uploaded_file($_FILES['photo']['tmp_name'], $target))
{
copy($target, $copy);
mysql_query("INSERT INTO `images` (`productcode`, `photo`) VALUES ('$productcode', '$pic' )");
echo "The new image has been added successfully";
}
else
{
echo "Error uploading new image - please check the format and size";
}
}
?>
I'm using the following code to upload and rename files. That part works awesome, however it also posts some data to a db table.
The problem is the old name is getting posted to the db, but the file is renaming to the ID...how can I get the new name into the db?
Thanks in advance here is my code:
<?php
//This is the directory where images will be saved
$allowed_filetypes = array('.jpg','.pdf','.xlsx','.xls','.doc','.docx','.ppt','.pptx','.jpeg','.png','.gif','.pdf');
$max_filesize = 52428800; // max file size = 50MB
$target = $target . basename( $_FILES['document']['name']);
//This gets all the other information from the form
$billing_id=$_POST['billing_id'];
$shipping_id=$_POST['shipping_id'];
$file_name=$_POST['file_name'];
$file_type=$_POST['file_type'];
$file_description=$_POST['file_description'];
$file = $_FILES['document']['name']; // Get the name of the file (including file extension).
$ext = substr($file, strpos($file,'.'), strlen($file)-1);
if(!in_array($ext,$allowed_filetypes))//check if file type is allowed
die('The file extension you attempted to upload is not allowed.'); //not allowed
if(filesize($_FILES['document']['tmp_name']) > $max_filesize) //check that filesize is less than 50MB
die ('The file you attempted to upload is too large, compress it below 50MB.');
// Connects to your Database
mysql_connect("localhost", "root", "password") or die(mysql_error()) ;
mysql_select_db("table") or die(mysql_error()) ;
//Writes the information to the database
mysql_query("INSERT INTO customer_files (billing_id, shipping_id, file_name, file_type, file_description, file)
VALUES ('$billing_id', '$shipping_id', '$file_name', '$file_type', '$file_description', '$target')") ;
$target = "../../file_management/uploads/customers/" .mysql_insert_id() . $ext;
//Writes the file to the server
if(move_uploaded_file($_FILES['document']['tmp_name'], $target))
{
//Tells you if its all ok
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";
}
else {
//Gives and error if its not
echo "Sorry, there was a problem uploading your file.";
}
?>
You are inserting the values to the database before you are renaming the file. You have to make change in your code. First insert the billing and shipping id in the databse, then take the last inserted id, rename the file with the last insert id and update the new name in databse. Change your code to:
<?php
//This is the directory where images will be saved
$allowed_filetypes =array('.jpg','.pdf','.xlsx','.xls','.doc','.docx','.ppt','.pptx','.jpeg','.png','.gif','.pdf');
$max_filesize = 52428800; // max file size = 50MB
$target = $target . basename( $_FILES['document']['name']);
//This gets all the other information from the form
$billing_id=$_POST['billing_id'];
$shipping_id=$_POST['shipping_id'];
$file_name=$_POST['file_name'];
$file_type=$_POST['file_type'];
$file_description=$_POST['file_description'];
$file = $_FILES['document']['name']; // Get the name of the file (including file extension).
$ext = substr($file, strpos($file,'.'), strlen($file)-1);
if(!in_array($ext,$allowed_filetypes))//check if file type is allowed
die('The file extension you attempted to upload is not allowed.'); //not allowed
if(filesize($_FILES['document']['tmp_name']) > $max_filesize) //check that filesize is less than 50MB
die ('The file you attempted to upload is too large, compress it below 50MB.');
// Connects to your Database
mysql_connect("localhost", "root", "password") or die(mysql_error()) ;
mysql_select_db("table") or die(mysql_error()) ;
//Writes the information to the database
mysql_query("INSERT INTO customer_files (billing_id, shipping_id) VALUES ('$billing_id', '$shipping_id')") ;
$target = "../../file_management/uploads/customers/" .mysql_insert_id() . $ext;
$last_id = mysql_insert_id();
$new_file_name = mysql_insert_id() . $ext;
mysql_query("UPDATE customer_files SET file_name='$new_file_name',file_type='$file_type',file_description='$file_description',file='$target' WHERE id=$last_id");
//Writes the file to the server
if(move_uploaded_file($_FILES['document']['tmp_name'], $target))
{
//Tells you if its all ok
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";
}
else {
//Gives and error if its not
echo "Sorry, there was a problem uploading your file.";
}
?>
Hope this helps
The new 'name' is already in the DB - it's the primary key of the record that was created when you inserted the upload data:
$target = "../../file_management/uploads/customers/" .mysql_insert_id() . $ext;
^^^^^^^^^^^^^^^^^ the new filename