mysql - delete sql row where data not match with data in array - php

Question

Please can I have some help on this. I'm trying to delete SQL row in a table that are not match the data in an array.
SQL Table:
| id | Name | No
------------------
| 1 | john | 14
| 2 | rui | 156
| 3 | ted | 148
| 4 | alex | 123
| 5 | depay | 56
Array:
Array
(
[0] => Array
(
[name] => john
[no] => 14
)
[1] => Array
(
[name] => ted
[no] => 148
)
[2] => Array
(
[name] => depay
[no] => 56
)
)

Answer 1

This may help you
[akshay#localhost tmp]$ cat test.php
<?php
$array = array (
array (
'name' => 'john',
'no' => '14'
),
array (
'name' => 'ted',
'no' => '148'
),
array (
'name' => 'depay',
'no' => '56'
)
);
$table = "some_table";
$sql = "DELETE FROM ".$table." WHERE (NAME,NO) NOT IN (". implode(",",array_map(function($_){ return sprintf("('%s',%d)",$_['name'],$_['no']);},$array)).")";
print $sql."\n";
?>
Output
[akshay#localhost tmp]$ php test.php
DELETE FROM some_table WHERE (NAME,NO) NOT IN (('john',14),('ted',148),('depay',56))

Answer 2

It would be much easier if you can return "id" aka primary key of the table as array. In that case you can just grab those ids and during delete operation exclude those from the equation.
$selectQ = 'select id from table_name'; // and no>10
$result = mysql_result($selectQ);
$ids = array();
while ($info = mysql_fetch_assoc($result)) {
$ids[] = $info['id'];
}
if($ids) {
$deleteQ = 'delete from table_name where id not in ('.implode(",", array_values($ids)).')';
mysql_query($deleteQ);
}
P.S : During select query make sure to include logic for finding those users. For example, who's "no" is greater than X.Otherwise this query in default will return all ids and eventually nothing will be deleted.