Combine two arrays on php - php

Question

Hello i am trying to combine two php array.
First one
array (size=13)
0 =>
object(stdClass)[30]
public 'ID' => string '1' (length=1)
public 'name' => string 'html5' (length=5)
public 'img' => string 'HTML5.png' (length=9)
1 =>
object(stdClass)[31]
public 'ID' => string '2' (length=1)
public 'name' => string 'css3' (length=4)
public 'img' => string 'css.png' (length=7)
2 =>
object(stdClass)[32]
public 'ID' => string '3' (length=1)
public 'name' => string 'php' (length=3)
public 'img' => string 'php1.png' (length=8)
3 =>
object(stdClass)[33]
public 'ID' => string '4' (length=1)
public 'name' => string 'java script' (length=11)
public 'img' => string 'javascript.png' (length=14)
Second one
array (size=3)
0 =>
object(stdClass)[26]
public 'ID' => string '1' (length=1)
public 'IDuser' => string '1' (length=1)
public 'IDskill' => string '1' (length=1)
1 =>
object(stdClass)[27]
public 'ID' => string '2' (length=1)
public 'IDuser' => string '1' (length=1)
public 'IDskill' => string '3' (length=1)
2 =>
object(stdClass)[28]
public 'ID' => string '3' (length=1)
public 'IDuser' => string '1' (length=1)
public 'IDskill' => string '4' (length=1)
ID from first array is equal to IDskill from second array. I am trying to combine to create new array if IDskill and ID are same, with something like this in new array
public 'ID' => string '1' (length=1)
public 'name' => string 'html5' (length=5)
public 'img' => string 'HTML5.png' (length=9)
===>New field public 'MATCH' => string '1' (length=9)

Answer 1

use array_merge() function
<?php
$a1=array("red","green");
$a2=array("blue","yellow");
print_r(array_merge($a1,$a2));
?>
or
<?php
$fname=array("Peter","Ben","Joe");
$age=array("35","37","43");
$c=array_combine($fname,$age);
print_r($c);
?>

Answer 2

Try this ( where a1 is first array and a2 is second one and $result is final, merged array ):
$result = array();
$n=0;
foreach($a1 as $k=>$v) {
if (isset($v->ID) && isset($a2[$n]->ID) && $v->ID==$a2[$n]->ID) {
$result[$n]=$v;
$result[$n]->MATCH=1;
}
$n++;
}
print_r($result);

Answer 3

You could use array_map and anonymous functions:
<?php
$first_array = array(...);
$second_array = array(...);
// Anonymous function to extract the IDskills from the second array:
$get_IDs = function($element) {
return($element->IDskill);
};
// Array of (just) IDskills of the second array:
$IDs = array_map($get_IDs, array_filter($second_array, function($element) {
// Anonymous function to filter $second_array elements without IDskill:
return(isset($element->IDskill));
}));
// Another anonymous function that returns a new array with elements from
// $first_array with the new MATCH property.
// use(&$IDs) makes $IDs available inside the function scope:
$check_match = function($element) use(&$IDs) {
// We use clone because we don't want to modify the original array values:
$match_element = clone $element;
if(isset($match_element->ID))
$match_element->MATCH = in_array($match_element->ID, $IDs);
else
$match_element->MATCH = false;
return($match_element);
};
$match = array_map($check_match, $first_array);
?>
If you don't want to use the two first anonymous functions or don't want to create the $IDs array you can replace use(&$IDs) for use(&$second_array) and the line:
$match_element->MATCH = in_array($match_element->ID, $IDs);
for a loop that iterates through $second_array elements to check whether any of them has an IDskill equal to $match_element->ID.
Moreover, you may not need to check if IDskill and ID exist if all the elements in the arrays have the same properties.

Answer 4

let me add my two cents, how to find element matching ID from the 1st array in the second one
$tmp = array_filter($array2, function($ar2) use ($ID) { return $ar2->IDskill === $ID; });
if ($tmp) // Found
else // Not found
all code may be
result = array()
foreach ($array1 as $item) {
$ID = $item->ID;
$tmp = array_filter($array2, function($ar2) use ($ID) { return $ar2->IDskill === $ID; });
if ($tmp) { // Found
$tmp = $item;
$tmp->MATCH = 1;
result[] = $tmp;
}
}