I am trying to show echo 2 but its not working
$zipcode1 = 07300-011;
$zipcode= str_replace("-","",$zipcode1);
$zipcode = 07300011;
if ($zipcode >= 20000000 && $zipcode <= 26600999) {
echo '1';
}
elseif ($zipcode >= 07000001 && $zipcode <= 07399999) {
echo '2';
}
else {
echo 'no value';
}
Please let me know where i am doing wrong. Thank you for the help
Result = 2
You need to compare string with string if the leading 0 of the zipcode is important:
$zipcode1 = "07300-011";
$zipcode= str_replace("-","",$zipcode1);
$zipcode = "07300011";
if ($zipcode >= "20000000" && $zipcode <= "26600999") {
echo '1';
} elseif ($zipcode >= "07000001" && $zipcode <= "07399999") {
echo '2';
} else {
echo 'no value';
}
You made two mistakes.
One is that the value assigned to $zipcode1 is not a string, but rather the result of an arithmetic operation. I'm saying $zipcode1 is not "07300-011", but rather 07300-011, which is equal to the octal number 7300 (3776 in base 10) minus octal 11 (9 in base 10), i.e 3776 - 9 which is 3767.
The second is that you're trying to do a numeric comparison using strings. "20" > "1000" is not the same as 20 > 1000. The first would resolve to true, whereas the second would give false (which is likely what you want).
To fix this, you have to first convert both of them to numbers. You can either cast them:
((int) $zipcode1) > (int) $zipcode2
or you can use the + sign instead:
(+$zipcode1) > (+$zipcode2)
In both cases, you need to first remove whitespaces and every other non-numeric character from the zipcode.
$zipcode = str_replace([' ', '-'], '', $zipcode);
Read the following topics in the php docs for more info:
Numeric Strings
Comparison Operators
Is it possible to assign a conditional statement into a variable and use it in an if statement? For example, I have the following code where the condition in the if statement will change from time to time:
<?php
$x = 2;
//This "x > 5" value will come from a database
$command = "x > 5";//Some times this value might be x > 5 || x == 1
if($command)//This will always be true no matter what since the content of the $command is not empty
echo "x is bigger than 5";
else
echo "x is smaller than 5";//I want this line to get executed since x is smaller than 5 in this case
?>
Expected output is x is smaller than 5, but what I get is x is bigger than 5
You need to use eval(). $command will have to contain $ before the variables so it's valid PHP syntax.
$x = 2;
$command = '$x > 5';
$result = eval("return ($command);");
if ($result) {
echo "x is bigger than 5";
} else {
echo "x is smaller than 5";
}
Since eval() can execute arbitrary code, you should be extremely careful about what you allow to be put into $command.
I am new to PHP. My problem is I need the input to validate to a minimum 20 character input and return the last nine. Can anybody tell me if my argument is close to working and if not what do I need to do?
if (!empty($_POST['usen']) ||
strlen($usen['usen'] >= 20 )) {
$switch = substr($usen, -9, 9); // returns last nine of sentence
$output_form=false;
} else {
$error_text .="<p><span class='error'>*<strong>A Sentence of 20 char is required .</strong></span></p>";
$output_form=true;
}
You have several syntax problems and variable-naming problems. Your code should be:
if (!empty($_POST['usen']) && // || should be &&; the || doesn't make sense here
strlen($_POST['usen']) >= 20 ) { // You had $usen['usen'] and an incorrectly placed )
$switch = substr($_POST['usen'], -9); // again, this should be $_POST['usen'], not $usen. The third parameter is unnecessary here.
$output_form = false;
} else {
$error_text .= "<p><span class='error'>*<strong>A Sentence of 20 char is required .</strong></span></p>";
$output_form = true;
}
The key points:
You're using the wrong boolean operator. !empty($x) || strlen($x) >= 20 doesn't make sense. It should be &&, not ||. If you have a non-empty value for $_POST['usen'], then !empty($_POST['usen']) is true. But because you had a || in your if conditional, this meant the if block always executed for non-empty values, never the else block. You only want the if to execute if the value is non-empty and at least 20 characters.
Your variable is $_POST['usen'], but your code referred to $usen['usen'] and $usen, which are incorrect.
You had strlen($usen['usen'] >= 20) where you should have strlen($_POST['usen']) >= 20. Both the variable name and the ) placement were incorrect.
To get the last 9 characters of $usen['usen'] use
$switch = substr($usen, -9);
if (!empty($_POST['usen']) ||
strlen($_POST['usen']) >= 20 ) { // changed condition
$switch = substr($usen, -9, 9); // returns last nine of sentence
$output_form=false;
} else {
$error_text .="<p><span class='error'>*<strong>A Sentence of 20 char is required .</strong></span></p>";
$output_form=true;
}
The if-condition has two issues in second part
You use $usen['usen'] but i think it schould be $_POST['usen'] (see also comment by #Ed Cottrell)
The closing bracker from method-call strlen has to be after the param
if (!empty($_POST['usen']) &&
strlen($_POST['usen'] )>= 20 ) { //condition change
$switch = substr($_POST['usen'] ,-9); // returns last nine of sentence
$output_form=false;
} else {
$error_text .="<p><span class='error'>*<strong>A Sentence of 20 char is required .</strong></span></p>";
$output_form=true;
}
To get last 9 charcters , you can use substr(string, -9);
What is wrong with this if-else statement.
if((strlen($objectData['pss'] >= 8))AND(strlen($objectData['pss'] <= 20)))
{
//do my bidding
}
else
{
echo "String to short or to long";
}
Ultimately I am trying to find if the variable is greater than or equal to 8 chars while being under or equal to 20 chars. My test string is 11 char, and I am seeing string to short/to long. I've done similar to this in the past, so I dunno what I mucked up at the moment (maybe Im just to tired to realize it)
if (strlen($objectData['pss']) >= 8 && strlen($objectData['pss']) <= 20)
if ((strlen($objectData['pss']) >= 8) and (strlen($objectData['pss']) <= 20))
{
//do my bidding
}
else
{
echo "String to short or to long";
}
I have corrected you brackets
Yes you are indeed "to tired".. You are basically counting the length of an expression instead of the string itself:
if((strlen($objectData['pss']) >= 8)AND(strlen($objectData['pss']) <= 20))
I need to check for a form input value to be a positive integer (not just an integer), and I noticed another snippet using the code below:
$i = $user_input_value;
if (!is_numeric($i) || $i < 1 || $i != round($i)) {
return TRUE;
}
I was wondering if there's any advantage to using the three checks above, instead of just doing something like so:
$i = $user_input_value;
if (!is_int($i) && $i < 1) {
return TRUE;
}
Not sure why there's no suggestion to use filter_var on this. I know it's an old thread, but maybe it will help someone out (after all, I ended up here, right?).
$filter_options = array(
'options' => array( 'min_range' => 0)
);
if( filter_var( $i, FILTER_VALIDATE_INT, $filter_options ) !== FALSE) {
...
}
You could also add a maximum value as well.
$filter_options = array(
'options' => array( 'min_range' => 0,
'max_range' => 100 )
);
Learn more about filters.
the difference between your two code snippets is that is_numeric($i) also returns true if $i is a numeric string, but is_int($i) only returns true if $i is an integer and not if $i is an integer string. That is why you should use the first code snippet if you also want to return true if $i is an integer string (e.g. if $i == "19" and not $i == 19).
See these references for more information:
php is_numeric function
php is_int function
The best way for checking for positive integers when the variable can be INTEGER or STRING representing the integer:
if ((is_int($value) || ctype_digit($value)) && (int)$value > 0 ) { // int }
is_int() will return true if the value type is integer. ctype_digit() will return true if the type is string but the value of the string is an integer.
The difference between this check and is_numeric() is that is_numeric() will return true even for the values that represent numbers that are not integers (e.g. "+0.123").
It's definitely heading towards the land of micro-optimisation, but hey: the code I'm working on chews through millions of items every day and it's Friday. So I did a little bit of experimenting...
for ($i = 0; $i < 1000000; $i++) {
// Option 1: simple casting/equivalence testing
if ((int) $value == $value && $value > 0) { ... }
// Option 2: using is_int() and ctype_digit(). Note that ctype_digit implicitly rejects negative values!
if ((is_int($value) && $value > 0) || ctype_digit($value)) { ... }
// Option 3: regular expressions
if (preg_match('/^\d+$/', $value)) { ... }
}
I then ran the above tests for both integer and string values
Option 1: simple casting/equivalence testing
Integer: 0.3s
String: 0.4s
Option 2: using is_int() and ctype_digit()
Integer: 0.9s
String: 1.45s
Option 3: regular expressions
Integer: 1.83s
String: 1.60s
Perhaps unsurprisingly, option 1 is by far the quickest, since there's no function calls, just casting. It's also worth noting that unlike the other methods, option 1 treats the string-float-integer value "5.0" as an integer:
$valList = array(5, '5', '5.0', -5, '-5', 'fred');
foreach ($valList as $value) {
if ((int) $value == $value && $value > 0) {
print "Yes: " . var_export($value, true) . " is a positive integer\n";
} else {
print "No: " . var_export($value, true) . " is not a positive integer\n";
}
}
Yes: 5 is a positive integer
Yes: '5' is a positive integer
Yes: '5.0' is a positive integer
No: -5 is not a positive integer
No: '-5' is not a positive integer
No: 'fred' is not a positive integer
Whether or not that's a good thing for your particular use-case is left as an exercise for the reader...
The other best way to check a Integer number is using regular expression. You can use the following code to check Integer value. It will false for float values.
if(preg_match('/^\d+$/',$i)) {
// valid input.
} else {
// invalid input.
}
It's better if you can check whether $i > 0 too.
preg_match('{^[0-9]*$}',$string))
and if you want to limit the length:
preg_match('{^[0-9]{1,3}$}',$string)) //minimum of 1 max of 3
So pisitive int with a max length of 6:
if(preg_match('{^[0-9]{1,6}$}',$string)) && $string >= 0)
You don't really need to use all three check and if you want a positive integer you might want to do the opposite of what is in your code:
if(is_numeric($i) && $i >= 0) { return true; }
Check Sören's answer for more information concerning the difference between is_int() and is_numeric()
if(preg_match('/^[1-9]\d*$/',$i)) {
//Positive and > 0
}
Rather than checking for int OR string with multiple conditions like:
if ( ctype_digit($i) || ( is_int($i) && $i > 0 ) )
{
return TRUE;
}
you can simplify this by just casting the input to (string) so that the one ctype_digit call will check both string and int inputs:
if( ctype_digit( (string)$i ) )
{
return TRUE;
}
In addition to all the other answers: You are probably looking for ctype_digit. It looks for a string containing only digits.
Definition:
!A = !is_numeric($i)
B = $i < 1
!C = $i != round($i)
Then...
!is_numeric($i) || $i < 1 || $i != round($i) is equal to
!A || B || !C
So:
!A || B || !C = !A || !C || B
Now, using the deMorgan theorem, i.e. (!A || !C) = (A && C), then:
!A || !C || B = (A && C) || B
Now, note that A && C = is_numeric($i) && $i == round($i), but if $i == round($i) is TRUE, then is_numeric($i) is TRUE as well, so we can simplify A && C = C so,
(A && C) || B = C || B =
$i == round($i) || $i < 1
So you just need to use:
$i = $user_input_value;
if ($i == round($i) || $i < 1) {
return TRUE;
}
Laravel 4.2 Validation rule for positive number
It takes only positive numbers including float values.
public static $rules = array(
'field_name' => 'required|regex:/^\d*\.?\d*$/'
);
e.g:20,2.6,06
The first example is using round to verify that the input is an integer, and not a different numeric value (ie: a decimal).
is_int will return false if passed a string. See the PHP manual examples for is_int
To check for positive integer use:
$i = $user_input_value;
if (is_int($i) && $i > 0) {
return true; //or any other instructions
}
OR
$i = $user_input_value;
if (!is_int($i) || $i < 1) {
return false; //or any other instructions
}
Use the one that fits your purpose as they are the same. The following examples demonstrate the difference between is_numeric() and is_int():
is_numeric(0); // returns true
is_numeric(7); // returns true
is_numeric(-7); // returns true
is_numeric(7.2); // returns true
is_numeric("7"); // returns true
is_numeric("-7"); // returns true
is_numeric("7.2"); // returns true
is_numeric("abc"); // returns false
is_int(0); // returns true
is_int(7); // returns true
is_int(-7); // returns true
is_int(7.2); // returns false
is_int("7"); // returns false
is_int("-7"); // returns false
is_int("7.2"); // returns false
is_int("abc"); // returns false
All these answers overlook the fact that the requestor may checking form input.
The is_int() will fail because the form input is a string.
is_numeric() will be true also for float numbers.
That is why the $i == round($i) comes in as it checks for the input being a whole number.
Ok, I know this thread is really old but I share #Jeffrey Vdovjak's opinion: since I was able to find it, it might still help someone else out there.
php's gmp_sign() might be another easy way to check. It works for integer and numeric strings, and returns 1 if a is positive, -1 if a is negative, and 0 if a is zero.
So:
// positive
echo gmp_sign("500") . "\n";
// negative
echo gmp_sign("-500") . "\n";
// zero
echo gmp_sign("0") . "\n";
will output:
1
-1
0
See function manual at http://php.net/manual/en/function.gmp-sign.php
P.S. You'll need to have php_gmp.dll enabled in your .ini file.
This's my solution, hope helpful :
if (is_numeric($i) && (intval($i) == floatval($i)) && intval($i) > 0)
echo "positive integer";
i check if string is numeric, second check to sure it's integer and third to sure it positive
If you use "is_int" the variable must be integer, so it can't be a float value. (no round needed).
if(isset($i) && is_int($i) && $i >= 0){ //0 is technically a postive integer I suppose
return TRUE; //or FALSE I think in your case.
}
I would do something like this:
if ((int) $i > 0) {
// this number is positive
}
The number gets typecast to a positive or negative number depending on the minus sign being at the front. Then compares the typecast number to being greater than 0 to determine if the number is positive.