Is there a way to remove two numbers not affecting others? - php

Question

The code is giving the following output and each time, it will give a different output.
Is there any way to remove to 2 numbers for example 15 and 60, so that other numbers are not effected they remain the same?
I have tried but could not get the desired result.
Any help or any idea how to do this?
<?php
$arr = array();
for ($i = 1; $i < 82; $i++) {
$arr[] = $i;
}
shuffle($arr);
$lines = array_chunk($arr, 9);
echo "<table>";
foreach ($lines as $key => $line) {
echo "<tr>";
for ($i = 0; $i < sizeof($line); $i++) {
echo "<td align='right'>" . $line[$i] . "</td>";
}
echo "</tr>";
}
echo "</table>";
?>
Out put
52 67 5 44 76 49 1 27 28
73 33 19 66 4 14 63 45 62
26 75 50 80 70 38 12 54 78
9 69 36 32 2 7 56 11 51
40 20 22 15 60 65 31 41 77
57 29 34 79 68 23 18 71 39
42 10 72 17 81 30 35 48 47
37 59 53 6 3 55 13 46 58
61 25 24 64 74 43 21 8 16

Answer 1

This should work for you:
Just place the code before your shuffle() call. Basically first we create an array of patterns, by looping through all numbers, which we want to extract from the list, with array_map().
The pattern basically has two anchors to match the numbers fully in your array and not only partially (E.g. 2 will not match 24, but it will match 2).
With the created pattern array we just use preg_replace() to replace the numbers in your array with an empty string.
$numbers = [15, 60];
$pattern = array_map(function($v){
return "/^$v$/";
}, $numbers);
$arr = preg_replace($pattern, "", $arr);