Multiple queries & LastInsertId - php

Question

How wrong is that query? Can I insert multiple queries like that?
Can I use lastInsertId like that?
$pdo = Database::connect();
$dflt = 'DEFAULT';
$query1 = "INSERT INTO utilizador(email, pass, nome, dt_registo, tipo, activo)
VALUES (:email, '$hashed_password', :nome, :dt_registo, :tipo, :activo)";
$stmt = $pdo->prepare($query1);
$stmt->execute();
$insertedid = $pdo->lastInsertId("utilizador");
$query2 ="INSERT INTO aluno(morada, cd_postal, cidade, utilizador_id)
VALUES (:morada, :cpostal, :cidade,'$insertedid')";
$stmt2 = $pdo->prepare($query2);
$stmt2->execute();
$hashed_password = hash( 'sha512', $_POST['password']);
$stmt->bindParam(':email',$_POST['email']);
$stmt->bindParam(':nome',$_POST['nome']);
$stmt->bindParam(':dt_registo',$dflt);
$stmt->bindParam(':tipo',$dflt);
$stmt->bindParam(':activo',$dflt);
$stmt->bindParam(':morada',$_POST['morada']);
$stmt->bindParam(':cpostal',$_POST['cpostal']);
$stmt->bindParam(':cidade',$_POST['cidade']);
if($stmt->execute()){
echo "Product was created.";
}else{
echo "Unable to create product.";
}
Database::disconnect();
}
catch(PDOException $exception){
echo "Error: " . $exception->getMessage();
}
I've already been searching but couldn't find how to use both in a query and I already expired all the solutions, not sure which is wrong.
EDIT:
I'm starting to think its more than the query, if someone notice something..
JAVASCRIPT
$(document).on('submit', '#create-aluno-form', function() {
// show a loader img
$('#loader-image').show();
// post the data from the form
$.post("registar.php", $(this).serialize())
.done(function(data) {
// show create product button
$('#create-aluno').show();
showProducts();
});
return false;
});

Answer 1

Most likely your statement fails to insert, Your code is full of problems:
You used prepare statement but yet you put values in the query string
hashed_password is undefined in the first query
You try to bind multiple queries at once
wrong order prepare the first query, execute , then bind the parameters
-$pdo->lastInsertId(); is enough not sure why you pass "utilizador"
Try this approach:
try{
$pdo = Database::connect();
$dflt = 'DEFAULT';
$hashed_password = hash( 'sha512', $_POST['password']);
$query1 = "INSERT INTO utilizador(email, pass, nome, dt_registo, tipo, activo)
VALUES (:email, :pass, :nome, :dt_registo, :tipo, :activo)";
$stmt = $pdo->prepare($query1);
$stmt->bindParam(':email',$_POST['email']);
$stmt->bindParam(':pass',$hashed_password);
$stmt->bindParam(':nome',$_POST['nome']);
$stmt->bindParam(':dt_registo',$dflt);
$stmt->bindParam(':tipo',$dflt);
$stmt->bindParam(':activo',$dflt);
if($stmt->execute()){
//query1 success
$insertedid = $pdo->lastInsertId();
$query2 ="INSERT INTO aluno(morada, cd_postal, cidade, utilizador_id)
VALUES (:morada, :cpostal, :cidade, :utilizador_id)";
$stmt2 = $pdo->prepare($query2);
$stmt2->bindParam(':morada',$_POST['morada']);
$stmt2->bindParam(':cpostal',$_POST['cpostal']);
$stmt2->bindParam(':cidade',$_POST['cidade']);
$stmt2->bindParam(':utilizador_id',$insertedid);
if($stmt2->execute()){
//query2 success
}else{
//query2 failed
}
}else{
//query1 failed
}
Database::disconnect();
}
catch(PDOException $exception){
echo "Error: " . $exception->getMessage();
}

Answer 2

Try this....
$query1 = "INSERT INTO utilizador(email, pass, nome, dt_registo, tipo, activo)
VALUES (:email, '$hashed_password', nome, :dt_registo, :tipo, :activo);";
$stmt = $pdo->prepare($query1);
$stmt->execute();
$query2 ="INSERT INTO aluno(morada, cd_postal, cidade, utilizador_id)
VALUES (:morada, :cpostal, :cidade, LAST_INSERT_ID());";
$stmt2 = $pdo->prepare($query2);
$stmt2->execute();
Because insert the query not get last insert id. so separate those queries

Answer 3

You have to use the
mysql_insert_id()
to get the last inserted record's id

Answer 4

I think these will useful to you.
$query = "INSERT INTO utilizador(email, pass, nome, dt_registo, tipo, activo)
VALUES (:email, '$hashed_password', nome, :dt_registo, :tipo, :activo)";
$query_1 = " INSERT INTO aluno(morada, cd_postal, cidade, utilizador_id)
VALUES (:morada, :cpostal, :cidade, mysql_insert_id())";
$stmt = $pdo->prepare($query);
$stmt_1 = $pdo->prepare($query_1);
these will useful to you.
mysql_select_db('test');
mysql_query("INSERT INTO mytable (name) values ('venkatesh')");
printf("Last inserted record has id %d\n", mysql_insert_id());
Thank you.

Answer 5

see here
INSERT INTO questions VALUES(NULL, 'My question');
INSERT INTO answers VALUES(NULL, LAST_INSERT_ID(), 'Answer 1');
INSERT INTO answers VALUES(NULL, LAST_INSERT_ID(), 'Answer 2');
INSERT INTO answers VALUES(NULL, LAST_INSERT_ID(), 'Answer 3');
Now I Have using LAST_INSERT_ID();
INSERT INTO answers VALUES
(NULL, LAST_INSERT_ID(), 'Answer 1') ,
(NULL, LAST_INSERT_ID(), 'Answer 2') ,
(NULL, LAST_INSERT_ID(), 'Answer 3');
OR
also we can try this way
INSERT INTO questions VALUES(NULL, 'My question');
SET #id = (SELECT LAST_INSERT_ID());
INSERT INTO answers VALUES(NULL, #id, 'Answer 1');
INSERT INTO answers VALUES(NULL, #id, 'Answer 2');
INSERT INTO answers VALUES(NULL, #id, 'Answer 3');
It was just an example for you

Answer 6

$query1 = "INSERT INTO utilizador(email, pass, nome, dt_registo, tipo, activo)
VALUES (:email, '$hashed_password', nome, :dt_registo, :tipo, :activo);";
$stmt = $pdo->prepare($query1);
$stmt->execute();
$insertedid = $pdo->lastInsertId("utilizador");
$query2 ="INSERT INTO aluno(morada, cd_postal, cidade, utilizador_id)
Ref link:-http://www.dreamincode.net/forums/topic/169597-pdolastinsertid/
VALUES (:morada, :cpostal, :cidade,'$insertedid'
);";
$stmt2 = $pdo->prepare($query2);
$stmt2->execute();