My SQL server uses the mm/dd/yyyy date format, but the date picker that I have implemented using jQuery gives the date format as dd/mm/yyyy.
So I coded this to check if the given input is in the format of mm/dd/yyyy, but it evaluates to true no matter which format the date input is given in. PHP code is,
$Temp = DateTime::createFromFormat('d/m/Y', $StartsOn);
if($Temp)
$Temp->format('m/d/Y');
I need to convert to mm/dd/yyyy format only if the input is in dd/mm/yyyy. So please tell me what is the logical error that I have made in my code.
it's impossible to reliably check if a date is in dd/mm/yyyy or mm/dd/yyyy format. just think about a date like "May, 7th".
this would be 07/05/2015 or 05/07/2015 depending on the format. so if you just got the date-string with no additional information you can't tell if for example 05/07/2015 is May, 7th or July, 5th.
I am sorry but there is no logical solution to your problem.
From the PHP manual on strtotime
Dates in the m/d/y or d-m-y formats are disambiguated by looking at
the separator between the various components: if the separator is a
slash (/), then the American m/d/y is assumed; whereas if the
separator is a dash (-) or a dot (.), then the European d-m-y format
is assumed. To avoid potential ambiguity, it's best to use ISO 8601
(YYYY-MM-DD) dates or DateTime::createFromFormat() when possible.
The reason passing the date to SQL server works as mm/dd/yyyy is because of the separator. Where possible it is always best to pass as YYYY-MM-DD as per ISO 8601 which was created for exactly this purpose. To fix your problem the best bet is to change the jQuery plugin configuration to output data in that format (if that's not possible, string replace / with - where it's coming from the jQuery plugin. This will avoid future complications by writing code to fix the date format.
You will no be able to tell the difference between mm/dd/yyyy and dd/mm/yyyy when you don't know where it's come from.
You can use a modified version of this function from PHP.net. It uses the DateTime class:
function validateDate($date)
{
$d = DateTime::createFromFormat('d/m/Y', $date);
return $d && $d->format('d/m/Y') == $date;
}
if(validateDate($StartsOn)){
//do job
}
function was copied from this answer or php.net
Related
I'm facing a problem with date formating and adding days.
I have a function like this:
public function test($date)
{
var_dump($date);
var_dump(date("d/m/Y", strtotime($date . '+ 1 days' )))
}
for this example if I use "02/09/2019" as date I get:
02/09/2019
10/02/2019
I'm expecting
02/09/2019
03/09/2019
Can someone help me find a solution to this problem?
Thanks
The essential problem here is that PHP is interepreting $date as a different one to the date you intended it to represent. This is because you're using an ambiguous format for the date. Depending on your cultural norms, 02/09/2019 could mean 2nd September (d/m/Y format - commonly used in Europe and other places) or 9th February (m/d/Y format - commonly used in North America and other places).
PHP is treating your string as if it's an m/d/Y format, and adding one day to it - hence you get 10th February as the result.
However, this shouldn't be too much of a surprise. What it will do with your string is documented and predictable. The strtotime manual says, in the notes:
Dates in the m/d/y or d-m-y formats are disambiguated by looking at
the separator between the various components: if the separator is a
slash (/), then the American m/d/y is assumed; whereas if the
separator is a dash (-) or a dot (.), then the European d-m-y format
is assumed. If, however, the year is given in a two digit format and
the separator is a dash (-), the date string is parsed as y-m-d.
To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD)
dates or DateTime::createFromFormat() when possible.
There are two basic ways to solve this, which I've demonstrated in the "test" and "test2" functions in the code sample below.
The first approach, in the "test" function keeps your existing code the same, but inputs the date in the universal Y-m-d format, so there's no confusion over which part is the day and which the month.
If that's not workable for you for some reason, then the second approach changes the code to use the DateTime::createFromFormat function, which will parse the date according to the format string you pass to it, and create a DateTime object which can then be manipulated and also re-formatted again (into any string format you choose) when you're ready to output it.
<?php
function test($date)
{
var_dump($date);
var_dump(date("d/m/Y", strtotime($date . '+ 1 days' )));
}
function test2($date)
{
var_dump($date);
$dt2 = DateTime::createFromFormat("d/m/Y", $date);
$dt2->add(new DateInterval('P1D'));
var_dump($dt2->format("d/m/Y"));
}
test("2019-09-02");
test2("02/09/2019");
output of "test":
"2019-09-02"
"03/09/2019"
output of "test2":
"02/09/2019"
"03/09/2019"
Demo: http://sandbox.onlinephpfunctions.com/code/71e07798a109859cabd242d77acb1eafaef5bfe8
Have you tried using Carbon a php date-time library. it makes working with dates very easy, it is very easy to format dates and add dates using this library. Here is a quick tutorial
$dt = Carbon::create(2019, 09, 02, 0);
echo $dt->addDays(1);
Basically the 09 is been considered as day so its adding +1 to it so output is 10/02/2019.The provided solution may not be perfect but it should serve your purpose.
echo date("d/m/Y", strtotime(str_replace('/','-','02/09/2019') . '+1 days'));
which will give 03/09/2019
This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 1 year ago.
I have a Web for that requires the user to enter a date which is then stored in a MySQL database. I'd like to have the user enter the date in m/d/yyyy and have the system convert it into the Y-m-d format that MySQL requires. I thought that was simple enough, but I can't get it to stop making a serious error,
I've tried the following:
$date = new DateTime($this->vital_date);
$this->vital_date = $date->format('Y-m-d');
When the user enter 9/6/2013, 2013-06-09 gets stored in the MySQL table. (Note the transposition of the month and date.
Then, I tried the older, pre-object way:
$date = strtotime($this->vital_date);
$this->vital_date = date('Y-m-d', $date);
And that did the same thing -- a transposed month and date.
Can anyone give me any help on what I'm doing wrong or how I could make a better conversion.
You should be using DateTime::createFromFormat
From PHP DOC
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD) dates or DateTime::createFromFormat() when possible.
Example
$vital_date = "9/6/2013";
$date = DateTime::createFromFormat("m/d/Y", $vital_date);
echo $date->format('Y-m-d');
You should use DateTime::createFromFormat for non-standard format
You can specify the format you are giving the data in the following way:
$date = DateTime::createFromFormat('j/n/Y', '9/6/2013');
This sample is not just obvious for this situation but it is even useful in many other places too for eg getting info from an mathematician entered quadratic equation in your site text box without regex
or driving licence number can be properly handled and stored in a database formatting it using scanf for eg scanf($input, '%s-%s-%d/%d); etc
it depends on your need so you have to know about sscanf, scanf, printf, sprintf, vsprintf
<?php
$date = '9/6/2013';
list($month,$day,$year) = sscanf($date, '%d/%d/%d');
$date = sprintf('%d-%02d-%02d',$year,$month,$day);
echo $date;
?>
In my DB I have date field with a standard datetime for MySQL (YYYY-MM-DD HH:MM:SS). Trough AJAX request I am getting this time: DD/MM/YYYY
This is the function I had written to search trough DB:
$this->db->get_where('tvprogram', array('DATE(date)' => $date))->result_array();
At the moment this function isn't getting any data. What seems to be wrong here? How can I search and find all entries for specific day?
Use strtotime function to convert the date to correct format:
$date = date('Y-m-d', strtotime($date));
$this->db->get_where('tvprogram', array('DATE(date)' => $date))->result_array();
Please convert first posted date in database format and use with Date function in your searching field like this.
$date = date('Y-m-d', strtotime($search));
$this->db->where('DATE(created)',$date);
Check the format coming out of DATE(date) because it is probably like YYYY-MM-DD and the comparison will always fail.
Go into phpMyAdmin or similar and try SELECT DATE(now()) and double check the date format.
If $date has a format like DD/MM/YYY, then you can reformat it by using:
$date=date('Y-m-d',strtotime(strtr($date,"/","-")));
From the PHP manual (http://www.php.net/manual/en/function.strtotime.php):
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
To fix the American/European date ambiguity, I simply replace "/" with "-" before the string to time conversion.
I have this string in a post variable
'03/21/2011'
I need to parse it via php and turn it into this format
'2011-03-21'
I am using php and i need this format so i can run this query
SELECT prospect as 'Prospect', company as 'Company', industry as 'Industry', created_at as 'Original Date Submitted', software as 'Software', warm_transfer as 'Warm Transfer', UserName as 'Sales Rep' FROM mercury_leads join user on UserID=user_id WHERE created_at BETWEEN '2011-01-01' AND '2011-03-22'
If you want to handle it in PHP, your best bet is to use the strtotime() function which converts a string into a time that can then be manipulated with the date() function.
So you'd do something like:
$dateStr = date('Y-m-d', strtotime('03/21/2011'));
The nice thing about using strtotime() is that you don't have to worry about the exact format of the string you pass in. As long as it's something semi-reasonable, it'll will convert it.
So it would handle 03/21/2011, 3-21-2011, 03-21-11 without any modifications or special cases.
You can parse it even from mysql
select str_to_date('03/21/2011','%m/%d/%Y')
$date = '03/21/2011';
$timestamp = strtotime($date);
$sqlDate = date('Y-m-d', $timestamp);
That should do what you need.
strtotime
date
$items=explode('/','03/21/2011');
$time=mktime(0,0,0,$items[0],$items[1],$items[2]);
$isodate=date('Y-m-d',$time);
While there are many ways to do this, I think the easiest to understand and apply to all date conversions is:
$date = date_create_from_format('n/d/Y', $date)->format('Y-n-d');
It is explicit and you'll never have to wonder about m/d or d/m, etc.
You can see it here
http://www.codegod.de/WebAppCodeGod/PHP-convert-string-to-date--AID597.aspx
Or use the Date class of PHP 5.3
STR_TO_DATE(created_at, '%m/%d/%Y') as 'Original Date Submitted'.
Answer 1:
You can use something like this
$dateStr = date('Y-m-d', strtotime($someDate));
Con
It is not great for code readability because it does not allow you to explicitly parse a certain format and make that obvious in the code. For instance your code will not be obvious to an outside programmer as to what format $someDate was in since strtotime parses multiple formats.
Pro
However if $someDate is subject to change and you want the code to continue to attempt to normalize various formats this is a great choice
Con
If you the data comes in a format that is not supported. For instance when trying to parse a date in a non-US date format meaning the month and day are switched but the format uses forward slashes (21/04/78) Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
Answer 2:
To really make your code clear as to which date you are parsing and to validate that the data coming in as using the correct format, I would use date_create_from_format. Here is some code to help:
$server_date_str='06-10-2013 16:00:09';
$server_date_time = DateTime::createFromFormat('d-m-Y H:i:s',$server_date_str);
// check the format
if ( !($server_date_time instanceof DateTime) ) {
$error_array = DateTime::getLastErrors();
throw new Exception( implode(" - ",$error_array['errors']) );
}
//convert DateTime object to Unix time stamp
$server_time = strtotime($server_date_time->format('d-m-Y H:i:s'));
//convert Unix timestamp to date string of the format 2012-10-21
$dateStr = date('Y-m-d', $server_time);
This example is explained in more full detail at this link:
http://boulderapps.co/parse-a-date-by-a-specific-date-format-in-php
I want to convert an input date in the form of dd/mm/yyyy to the MySQL format which is yyyy-mm-dd.
I was trying to use date('Y-m-d', strtotime($_POST['date'])) but the problem is that the output is always Y-d-m, I think because it considers my 2nd argument to be mm/dd/yyyy.
How do I solve that?
date('Y-m-d', strtotime(str_replace('/', '-', $_POST['date'])))
From the manual:
Dates in the m/d/y or d-m-y formats
are disambiguated by looking at the
separator between the various
components: if the separator is a
slash (/), then the American m/d/y is
assumed; whereas if the separator is a
dash (-) or a dot (.), then the
European d-m-y format is assumed.
You need to convert your delimiters from / to -.
You could do:
$date = implode('-', array_reverse(explode('/', trim($_POST['date']))));
Reference: trim, explode, array_reverse, implode
(trim might not be necessary)
Mohamed,
I would recommend not even formatting the date in the database. If you store all of your date / time values as UNIX TIMESTAMP, you can format the data any way you want after you pull it from the data base.
Here's why: If all of your dates are formatted and you need to compare them, you'd need to bring them back to UNIX TIMESTAMP anyways. Yes, there are wheres to compare formatted date strings but its just one more extra step.
Although this is a bit late : If he uses timestamps then, in my experience he will run into trouble if he tries to perform any MySQL Date arithmetic / calculations on the timestamps - and the over head to do the same in PHP has the potential to become very expensive as it would involve selecting ALL records and then performing comparisons / calculations on the converted dates.
And I concur with jasonbar - PHP is looking at the delimiters of the date and considers it to be a US format date! He will need to run a str_replace('/','-',$_POST['date']) BEFORE using the date() function.
So, to fix this on an incoming request:
$mysqldate = date('Y-m-d', str_replace('/','-',strtotime($_POST['date'])));
So long as the data type for the target column is datetime anyways!
I found a pretty simple conversion.
$YOUR_DATE_FORMAT YYYY/MM/DD
$date = strtotime($YOUR_DATE_FORMAT);
$newdate = date('Y-m-d', $date); //or whatever format you choose.
works like a charm.