PHP / MySQL: How to store Select results in array - php

Question

I am new to PHP and MySQL and hope someone can help me with this.
I have a MySql db with a table "TranslationsMain" and the following PHP query.
This returns all the items from column "German" (incl. the corresponding ID) from the db table and works correctly so far.
Instead of echoing the whole list (I just did this here for testing), **how can I store the results in an array in a way that each item within the array is stored with its value and a unique ID + how I can I echo specific items from this array by referring to their ID ?
Example:
I would like to echo the item value for ID "xyz" from this array (without calling the db again since this will be needed for multiple items on the page).
My PHP:
<?php
require_once("includes/header.php");
$tblTranslations = "TranslationsMain";
$conn = new mysqli($servername, $username, $password, $dbname);
if($conn->connect_error){
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM " . $tblTranslations;
$translations = $conn->query($sql);
// for testing only
if($translations->num_rows > 0){
echo "<table><tr><th>ID</th><th>Translation</th></tr>";
while($translation = $translations->fetch_assoc()){
echo "<tr><td>" . $translation["ID"] . "</td><td>" . $translation["German"] . "</td></tr>";
}
echo "</table>";
}else{
echo "0 results";
}
$conn->close();
?>
Update:
What I am looking for here is how to create a two dimensional array and how to fetch from it.
Many thanks in advance,
Mike

Answer 1

if($translations->num_rows > 0){
$result_arr = array();
echo "<table><tr><th>ID</th><th>Translation</th></tr>";
while($translation = $translations->fetch_assoc()){
echo "<tr><td>" . $translation["ID"] . "</td><td>" . $translation["German"] . "</td></tr>";
$result_arr[] = $translation;
}
echo "</table>";
}else{
echo "0 results";
}
// now you can iterate $result_arr
foreach($result_arr as $row){
echo "<tr><td>" . $row["ID"] . "</td><td>" . $row["German"] . "</td></tr>";
}