MySQL Multiple Conditions on Group By / Having Clause - php

I have three tables that are all inter-related with the following structure.
ModuleCategory Table:
+------------------+----------------+------------+
| ModuleCategoryID | ModuleCategory | RequireAll |
+------------------+----------------+------------+
| 90 | Cat A | YES |
| 91 | Cat B | NO |
+------------------+----------------+------------+
ModuleCategorySkill Table:
+------------------+---------+
| ModuleCategoryID | SkillID |
+------------------+---------+
| 90 | 1439 |
| 90 | 3016 |
| 91 | 1440 |
| 91 | 3016 |
+------------------+---------+
EmployeeSkill Table:
+---------+---------+
| EmpName | SkillID |
+---------+---------+
| Emp1 | 1439 |
| Emp1 | 3016 |
| Emp2 | 1440 |
| Emp2 | 3016 |
| Emp3 | 1439 |
| Emp4 | 3016 |
+---------+---------+
Desired Output:
+------------------+-------+
| ModuleCategory | Count |
+------------------+-------+
| Cat A | 1 |
| Cat B | 3 |
+------------------+-------+
I am trying to group by ModuleCategoryID's and get the count of employees which have the skills being tracked.
Normally, I can do the following query to obtain the numbers:
select mc.ModuleCategory, Count(*) as Count from ModuleCategory as mc
join ModuleCategorySkill as mcs on mc.ModuleCategoryID = mcs.ModuleCategoryID join EmployeeSkill as es on es.SkillID= mcs.SkillID
group by mc.ModuleCategoryID
However, I have a column RequireAll in the ModuleCategory table which if it is set to 'YES' should only count employees as 1 only if they have all the skills in the category. If it is set to NO then it can count each row normally and increase the count by the number of rows it groups by.
I can achieve this by writing separate queries for each modulecategoryID and using a having Count() > 1 (which will find me anyone that has all the skills for ModuleCategoryID 90). If there were 3 skills than I would have to change it to Having Count() > 2. If there isn't anyone that has all the skills specified, the count should be 0.
I need a dynamic way of being able to do this since there is a lot of data and writing one query for each ModuleCategoryID isn't the proper approach.
Also, I am using PHP so I can loop through and create a sql string that can help me achieve this. But I know I will run into performance issues on big tables with a lot of skills and modulecategoryID's.
Any guidance on how to achieve this is much appreciated.

You can do it by joining on the total category counts, and then using conditional aggregation:
select modulecategory,
count(case when requireall = 'yes'
then if(s = t, 1, null)
else s
end)
from (
select modulecategory,empname, requireall, count(*) s, min(q.total) t
from employeeskill e
inner join modulecategoryskill mcs
on e.skillid = mcs.skillid
inner join modulecategory mc
on mcs.modulecategoryid = mc.modulecategoryid
inner join (
select modulecategoryid, count(*) total
from modulecategoryskill
group by modulecategoryid
) q
on mc.modulecategoryid = q.modulecategoryid
group by modulecategory, empname
) qq
group by modulecategory;
demo here
This operates under the assumption an employee isn't going to be allocated the same skill twice, if that is something that may happen, this query is alterable to support it, but it seems like a broken scenario to me.
What we have here is an inner query that collates all the information we need (category name, employee name, whether or not all skills are required, how many skills are in the group per employee, and how many there in the group total), with an outer query that uses a conditional count to change how the rows are tallied, based on the value of requireall.

Related

MySQL SUM of multiple rows from multiple table

I am trying to get the sum of multiple rows from 2 different tables, but somehow the result returns multiple rows.
I need to get the SUM of quotation_item_amount (group by quotation_id) and invoice_item_amount (group by invoice_id) and if I query unpaid quotation, I need to get WHERE SUM(invoice) < SUM(quotation)
So here's my sample table
table client_project_id
+-------------------+-----------+----------------------+
| client_project_id | client_id | client_project_title |
+-------------------+-----------+----------------------+
| 23 | 5 | Project 1 |
| 17 | 9 | Project 2 |
| 54 | 7 | Project 3 |
+-------------------+-----------+----------------------+
table quotation
+--------------+-------------------+------------------+
| quotation_id | client_project_id | quotation_number |
+--------------+-------------------+------------------+
| 1 | 23 | Q/01/2020/001 |
| 2 | 17 | Q/01/2020/002 |
| 3 | 54 | Q/01/2020/003 |
+--------------+-------------------+------------------+
table quotation_item
+-------------------+--------------+-----------------------+
| quotation_item_id | quotation_id | quotation_item_amount |
+-------------------+--------------+-----------------------+
| 1 | 1 | 500 |
| 2 | 1 | 700 |
| 3 | 1 | 600 |
| 4 | 2 | 200 |
| 5 | 2 | 150 |
| 6 | 3 | 900 |
+-------------------+--------------+-----------------------+
table invoice
+--------------+-------------------+------------------+
| invoice_id | client_project_id | invoice_number |
+--------------+-------------------+------------------+
| 1 | 23 | I/01/2020/001 |
| 2 | 17 | I/01/2020/002 |
| 3 | 54 | I/01/2020/003 |
+--------------+-------------------+------------------+
table invoice_item
+-------------------+--------------+-----------------------+
| invoice_item_id | invoice_id | invoice_item_amount |
+-------------------+--------------+-----------------------+
| 1 | 1 | 500 |
| 2 | 1 | 700 |
| 3 | 1 | 600 |
| 4 | 2 | 200 |
| 5 | 2 | 150 |
| 6 | 3 | 900 |
+-------------------+--------------+-----------------------+
The result that I need to obtain is:
SUM of quotation_item_amount and SUM of invoice_item_amount PER client_project_id
To query WHERE SUM(invoice) < SUM(quotation)
Here is my latest try at the query
SELECT
SUM(quotation_item.quotation_item_amount) as quot_amt,
SUM(invoice_item.invoice_item_amount) as inv_amt,
data_client_project.client_project_id,
data_client.client_name
FROM data_client_project a
LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
LEFT JOIN data_client d ON a.client_id = d.client_id
LEFT JOIN invoice i ON a.client_project_id = i.client_project_id
JOIN (
SELECT quotation_id,
SUM(c.quotation_item_amount) as quot_amt
FROM quotation_item c
GROUP BY c.quotation_id
) quotitem
ON b.quotation_id = quotitem.quotation_id
JOIN (
SELECT invoice_id,
SUM(e.invoice_item_price) as inv_amt
FROM invoice_item e
GROUP BY e.invoice_id
) invitem
ON i.invoice_id = invitem.invoice_id
However, this results in multiple duplicate rows of the quotation_item_amount and invoice_item_amount.
Have tried using UNION / UNION ALL and several other queries which just do not work.
Thank you for all your suggestions.
It looks like you are trying to aggregate along two different dimensions at the same time. The solution is to pre-aggregate along each dimension:
SELECT *
FROM data_client_project cp LEFT JOIN
(SELECT q.client_project_id,
SUM(qi.quotation_item_amount * qi.quotation_item_qty) as quot_amt
FROM quotation q JOIN
quotation_item qi
ON qi.quotation_id = q.quotation_id
GROUP BY q.client_project_id
) q
USING (client_project_id) LEFT JOIN
(SELECT i.client_project_id,
SUM(invoice_item_price) as inv_amt
FROM invoice i JOIN
invoice_item ii
ON i.invoice_id = ii.invoice_id
GROUP BY i.client_project_id
) i
USING (client_project_id);
Two notes about your style.
First, you are using arbitrary letters for table aliases. This makes the query quite hard to follow and becomes quite awkward if you add new tables, remove tables, or rearrange the names. Use abbreviations for the tables. Much easier to follow.
Second, I don't really recommend SELECT * for such queries. But, you can avoid duplicated column by replacing ON with USING.
I may be missing something, but your table descriptions do not include a example for data_client or data_client_project Given your example, I expect your row expansion is coming from the first 3 joins.
Make sure that the below is giving you the list of data you want first, then try joining in the calculation:
SELECT *
FROM data_client_project a
LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
LEFT JOIN data_client d ON a.client_id = d.client_id
LEFT JOIN invoice i ON a.client_project_id = i.client_project_id;
#you may want to append the above with a limit 100 for testing.
if you have duplicated rows form the main query then add distinct for obatin a only distinct rows
and andd the where conditio for filtering the result by quotitem.quot_amt < invitem.inv_amt
SELECT distinct a.*, b.*, d.*, i.*
FROM data_client_project a
LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
LEFT JOIN data_client d ON a.client_id = d.client_id
LEFT JOIN invoice i ON a.client_project_id = i.client_project_id
JOIN (
SELECT quotation_id,
SUM(c.quotation_item_amount * c.quotation_item_qty) as quot_amt
FROM quotation_item c
GROUP BY c.quotation_id
) quotitem ON b.quotation_id = quotitem.quotation_id
JOIN (
SELECT invoice_id,
SUM(e.invoice_item_price) as inv_amt
FROM invoice_item e
GROUP BY e.invoice_id
) invitem ON i.invoice_id = invitem.invoice_id
WHERE quotitem.quot_amt < invitem.inv_amt

GROUP BY multiple conditions at once

I have a tables like this:
Users
+----+----------+-------------+
| id | name | other_stuff |
+----+----------+-------------+
| 1 | John Doe | x |
| 2 | Jane Doe | y |
| 3 | Burt Olm | z |
+----+----------+-------------+
Places
+----+------------+-------------+
| id | name | other_stuff |
+----+------------+-------------+
| 1 | Building A | x |
| 2 | Building B | y |
+----+------------+-------------+
Subjects
+----+------------+-------------+
| id | name | other_stuff |
+----+------------+-------------+
| 1 | Math | x |
| 2 | English | y |
+----+------------+-------------+
And a joining table:
PastLectures = lectures that took place
+----+-----------+----------+------------+---------+------------+
| id | id_users | id_place | id_subjects| length | date |
+----+-----------+----------+------------+---------+------------+
| 1 | 1 | 1 | 1 | 60 | 2015-10-25 |
| 2 | 1 | 1 | 1 | 120 | 2015-11-06 |
| 3 | 2 | 2 | 2 | 120 | 2015-11-04 |
| 4 | 2 | 2 | 1 | 60 | 2015-11-10 |
| 5 | 1 | 2 | 1 | 60 | 2015-11-10 |
| 6 | 2 | 2 | 1 | 40 | 2015-11-15 |
| 7 | 1 | 2 | 2 | 30 | 2015-11-15 |
+----+-----------+----------+------------+---------+------------+
I would like to display SUM of all lessons for each user for given month. The SUM should by grouped by each Places and Subjects.
The result in final PHP output should look like this:
November 2015
+------------+-------------+---------------+-------------+
| Users.name | Places.name | Subjects.name | sum(length) |
+------------+-------------+---------------+-------------+
| Burt Olm | - | - | - |
| Jane Doe | Building B | Math | 100 |
| = | = | English | 120 |
| John Doe | Building A | Math | 120 |
| = | Building B | Math | 60 |
| = | = | English | 30 |
+------------+-------------+---------------+-------------+
I have tried creating the full output in pure SQL query using multiple GROUP BY (Group by - multiple conditions - MySQL), but when I do GROUP BY User.id,Places.id it shows each user only once (3 results) no matter the other GROUP BY conditions.
SQL:
SELECT PastLectures.id_users,Users.name AS user,Places.name AS places,Subjects.name AS subjects
FROM PastLectures
LEFT JOIN Users ON PastLectures.id_users = Users.id
LEFT JOIN Places ON PastLectures.id_Places = Places.id
LEFT JOIN Subjects ON PastLectures.id_Subjects = Subjects.id
WHERE date >= \''.$monthStart->format('Y-m-d H:i:s').'\' AND date <= \''.$monthEnd->format('Y-m-d H:i:s').'\'
GROUP BY Users.id,Places.id
ORDER BY Users.name,Places.name,Subjects.name
But I don't mind if part of the solution is done in PHP, I just don't know what to do next.
EDIT:
I also have a table Timetable, that stores who regularly teaches what and where. It stores only used combinations of the tables (each valid combination once).
Timetable = lectures that regularly take place
+----+-----------+----------+------------+-------------+
| id | id_users | id_place | id_subjects| other_stuff |
+----+-----------+----------+------------+-------------+
| 1 | 1 | 1 | 1 | x |
| 2 | 1 | 2 | 1 | y |
| 3 | 1 | 2 | 2 | z |
| 4 | 2 | 2 | 1 | a |
| 5 | 2 | 2 | 2 | b |
+----+-----------+----------+------------+-------------+
Is it possible to add only users with combinations that have a row in this table?
In this case it would mean omitting Burt Olm (no id=3 in Timetable). But if Burt has a Timetable entry and still no PastLectures entry, he would show here as in sample result (he should have had a lecture that month, because he is in Timetable, but no lectures took place).
Based on #Barmar's solution I updated the final SQL by making Timetable a primary table and adding one more LEFT JOIN to suffice those needs.
Final SQL:
SELECT Users.name AS user,Places.name AS places,Subjects.name AS subjects, SUM(PastLectures.length)
FROM Timetable
LEFT JOIN PastLectures ON PastLectures.id_users = Timetable.id_users AND PastLectures.id_place = Timetable.id_place AND PastLectures.id_subjects = Timetable.id_subjects
AND date BETWEEN '2015-11-01 00:00:00' AND '2015-11-30 23:59:59'
LEFT JOIN Places ON Timetable.id_Place = Places.id
LEFT JOIN Subjects ON Timetable.id_Subjects = Subjects.id
LEFT JOIN Users ON Timetable.id_users = Users.id
GROUP BY Timetable.id,Timetable.id_users,Timetable.id_Place,Timetable.id_Subjects
ORDER BY Users.name,Places.name,Subjects.name
You need to include Subjects.id in the GROUP BY, so you get a separate result for each subject.
Also, you shouldn't use columns in tables that are joined with LEFT JOIN in the GROUP BY column. If you do that, all the non-matching rows will be grouped together, because they all have NULL in that column. Use the columns in the main table.
GROUP BY PastLectures.id_users, PastLectures.id_Place, PastLectures.id_Subjects
DEMO
Note that there's no row for Burt Olm in the demo output, because all his rows are filtered out by the WHERE clause. If you want all users to be shown, you should make Users the main table, not PastLectures. And the date criteria needs to be moved into the ON clause when joining with PastLectures.
SELECT Users.name AS user,Places.name AS places,Subjects.name AS subjects, SUM(length)
FROM Users
LEFT JOIN PastLectures ON PastLectures.id_users = Users.id
AND date BETWEEN '2015-11-01 00:00:00' AND '2015-11-30 23:59:59'
LEFT JOIN Places ON PastLectures.id_Place = Places.id
LEFT JOIN Subjects ON PastLectures.id_Subjects = Subjects.id
GROUP BY Users.id, PastLectures.id_Place, PastLectures.id_Subjects
ORDER BY Users.name,Places.name,Subjects.name
DEMO
According to standard SQL, you should GROUP BY all the fields you select, except for the aggregated fields (like sum). Althought MySql allows to do otherwise, when it can be done adhering to the standards, it is better to do so (who knows when you need to port your code to another database engine). So write your SQL like this:
SELECT PastLectures.id_users,
Users.name AS user,
Places.name AS places,
Subjects.name AS subjects,
Sum(length)
FROM PastLectures
LEFT JOIN Users ON PastLectures.id_users = Users.id
LEFT JOIN Places ON PastLectures.id_Places = Places.id
LEFT JOIN Subjects ON PastLectures.id_Subjects = Subjects.id
WHERE date BETWEEN \''.$monthStart->format('Y-m-d H:i:s').'\'
AND \''.$monthEnd->format('Y-m-d H:i:s').'\'
GROUP BY PastLectures.id_users,
Users.name,
Places.name,
Subjects.name
ORDER BY Users.name,
Places.name,
Subjects.name

Converting PHP dependent SQL code to full SQL

the question will require a bit long of an answer to explain due to my ignorance on SQL.
I hope it will not be viewed as vague because I have tried doing it by parts, but then I wont know which part exactly is causing which problem.(It really shows my level of knowledge on SQL.)
I have a code that was originally written in a PHP file, but I have decided I want to create a view table in order for the page to load faster.
The reason was because it does a loop to list the ranking of students and was taking too long for the web page to load.
Anyways, here is the code :
SELECT
SUM(VCA.meritPoint) AS merit,
VCA.student_no AS student_no,
P.program_code AS education_level,
P.name AS name,
P.gender AS gender,
P.campus_id AS campus_id
FROM viewcardactivity VCA
JOIN pupil P ON P.student_no = VCA.student_no
JOIN semester S ON S.id = '{$id}' -- MAX() AND (MAX() - 1)
AND DATE(VCA.tarikh) BETWEEN DATE(s.tarikhStart) AND DATE(s.tarikhEnd)
WHERE P.campus_id = '{$campus}' -- 1, 2
AND P.gender= '{$gender}' -- M, F
AND VCA.level= '{$level}' -- Diploma, Degree
AND P.program_code = (CONVERT(IF((SUBSTR(REPLACE(`p`.`program_code`,' ',''),3,1) = 1),'Diploma','Degree')USING latin1))
GROUP BY student_no ORDER BY merit DESC
As the name of the columns suggests, I would like to display more than one instead of specific ids, gender and level provided from the PHP variables.
The example output I would like to have is such as(based on the SQL Fiddle mock data :
table 'viewrankingmerit'
| merit | student_no | education_level | name | gender | campus_id |
---------------------------------------------------------------------
| 99 | 111111111 | Diploma | Ash | M | 1 |
---------------------------------------------------------------------
| 87 | 222222222 | Diploma |Belle | F | 1 |
---------------------------------------------------------------------
| 85 | 333333333 | Degree | Carl | M | 1 |
---------------------------------------------------------------------
| 80 | 444444444 | Degree | Deli | F | 1 |
---------------------------------------------------------------------
| 75 | 555555555 | Diploma | Eddy | M | 2 |
---------------------------------------------------------------------
| 74 | 666666666 | Diploma |Foxxy | F | 2 |
---------------------------------------------------------------------
| 50 | 777777777 | Degree | Greg | M | 2 |
---------------------------------------------------------------------
| 20 | 888888888 | Degree |Haley | F | 2 |
---------------------------------------------------------------------
As for the semester id, I would like to get the latest 2 ids. Which is the highest and second highest, based on the auto-generated id that will keep on increasing..
I was immediately stuck at trying to get 2 ids from table semester. I've tried using :
JOIN semester S1 ON S1.id = (SELECT MAX(s1.id) FROM semester)
AND DATE(VCA.tarikh) BETWEEN DATE(s1.tarikhStart) AND DATE(s1.tarikhEnd)
JOIN semester S2 ON S2.id = (SELECT MAX(s2.id)-1 FROM semester)
AND DATE(VKA.tarikh) BETWEEN DATE(s2.tarikhStart) AND DATE(s2.tarikhEnd)
It was probably a bad reference, but that was the closest solution I got so far.
1) Is it possible to do a table to show all the info?
2) If yes, how to get both S.id, P.campus_id, P.gender and VCA.level. Hoping that the solution would be alike.
3) If no, what is the best solution?
Thanks a lot guys.
[Edit] I've added a demo data in an SQL Fiddle
After some discussion in coments, this is the final result. I think.
select sum(vca.meritPoint) as merit,
vca.student_no AS student_no,
vca.type AS education_level,
p.name AS name,
p.gender AS gender,
p.campus_id AS campus_id
from
viewcardactiviti vca
inner join pupil p ON p.student_no = vca.student_no
inner join (select * from semester order by id desc limit 2) s
ON (vca.tarikh between s.tarikhStart and s.tarikhEnd
AND vca.type = s.level)
group by vca.student_no, vca.type, p.name, p.gender, p.campus_id
order by merit desc, p.campus_id;
See it here on SQLFiddle
If you need to filter for specific configurations like the parameters on your original query just add a WHERE clause.
This subquery (select * from semester order by id desc limit 2) will get the last to semesters based on the ID. And since there is no direct link (foreign key) between semester and viewcardactiviti you can use there join conditions ON (vca.tarikh between s.tarikhStart and s.tarikhEnd AND vca.type = s.level)
If you think that it still need to change anything let me know!

Select distinct and random rows from one table that match a value from another table

This topic has been much discussed but I was unable to find a solution that I can modify and make it work for my case. So maybe a more advanced expert will be able to help out.
I have a table called keywords which contains about 3000 rows with distinct keywords. Against each keyword there is a matching product_id, which are NOT unique, i.e. some of them are repeated. Table looks something like this:
+---------+------------+
| keyword | product_id |
+---------+------------+
| apple1 | 15 |
| apple2 | 15 |
| pear | 205 |
| cherry | 307 |
| melon | 5023 |
+---------+------------+
I have a second table called inventory that contains about 500K of products each with it's own product ID and other product data.
Now I need to get one random product row from inventory table that matches each product_id from keywords table and insert those rows into another table.
Resulting table should be something like this:
+---------+------------+---------+---------+---------+
| keyword | product_id | product | data1 | data2 |
+---------+------------+---------+---------+---------+
| apple1 | 15 | app5 | d1 | d2 |
| apple2 | 15 | app1 | d1 | d2 |
| pear | 205 | pear53 | d1 | d2 |
| cherry | 307 | cher74 | d1 | d2 |
| melon | 5023 | melo2 | d1 | d2 |
+---------+------------+---------+---------+---------+
This is my query at the moment and the problem is how to get a random product from inventory that matches a product_id:
SELECT keywords.keyword, keywords.product_id, inventory.*
FROM keywords LEFT OUTER JOIN
inventory
ON keywords.product_id = inventory.id
ORDER BY RAND();
If you want it to only return rows when there is a match between the tables, then you want a regular (i.e. inner) join not a left outer join. You can also add the word distinct.
SELECT DISTINCT keywords.keyword, keywords.product_id, inventory.*
FROM keywords JOIN
inventory
ON keywords.product_id = inventory.id
ORDER BY RAND();
And if you only want 1 row returned, add limit 1 at the end.
SELECT keywords.keyword, keywords.product_id, inventory.*
FROM keywords JOIN
inventory
ON keywords.product_id = inventory.id
ORDER BY RAND() LIMIT 1;
Is this what you want?
SELECT *
FROM (
SELECT keywords.keyword, keywords.product_id, inventory.*
FROM keywords JOIN
inventory
ON keywords.product_id = inventory.id
ORDER BY RAND()
) tmp
GROUP BY tmp.keyword;
I also test it at http://sqlfiddle.com/#!2/e559a9/2/0. Just run some times, the result will be randomize.

Subtract two query results in mySQL

I have 2 queries which gives all records(including the booked ones) and gives out booked records only. I wanted to subtract the two tables so that it only shows the unbooked records, here are the example of the query results:
Query 1:
+--------+--------+
| Number | AreaNo |
+--------+--------+
| 6 | A |
| 6 | B |
| 6 | C |
| 7 | A |
| 7 | B |
+--------+--------+
Query 2:
+--------+--------+
| Number | AreaNo |
+--------+--------+
| 6 | B |
| 6 | C |
| 7 | B |
+--------+--------+
Desired Results:
+--------+--------+
| Number | AreaNo |
+--------+--------+
| 6 | A |
| 7 | A |
| 7 | C |
+--------+--------+
I know that I can't use MINUS in mySQL but I'm not sure that LEFT JOIN works in this situation. If this doesn't work, is it possible to work on the where clause?(Like if the number match, it only clear out the one with matching AreaNo). I tried this with two AND clause and it doesn't work. It clears out the results that doesnt fit either criteria. I have been doing researches over a week and nothing works. Please help, I am really desperated.
Query 1:
SELECT bookingListNo,
areaNo
FROM BookingList,
BookingArea,
BookingLocation
WHERE bookingListNo NOT IN (SELECT bookingListNo
FROM Booking
WHERE bookingAreaNo IS NULL) AND
BookingList.bookingLocationNo = BookingLocation.bookingLocationNo AND
BookingLocation.BookingLocationNo = BookingArea.bookingLocationNo
Query 2:
SELECT bookingListNo,
areaNo
FROM Booking,
BookingArea
WHERE Booking.bookingAreaNo = BookingArea.bookingAreaNo
This is how you do it.
SELECT Q1.Number,
Q1.AreaNo
FROM Query1 Q1
LEFT JOIN Query2 Q2
ON Q1.Number = Q2.Number AND
Q1.AreaNo = Q2.AreaNo
WHERE Q2.Number IS NULL AND
Q2.AreaNo IS NULL
LEFT OUTER JOIN will do the trick
SELECT *
FROM TABLE1 t_1 LEFT OUTER JOIN TABLE2 t_2
ON t_1.AreaNo = t_2.AreaNo ;
Check out this article for reference: http://www.sitepoint.com/understanding-sql-joins-mysql-database/
I'm guessing a RIGHT JOIN would do the trick.
Not exactly sure what your tables are like, but if you are joining a table with unbooked data to one that has all of our items, then you could do a query like this:
SELECT *
FROM all_items
RIGHT JOIN unbooked_data ON all_items.item_id = unbooked_data.item_id
When you RIGHT JOIN it only selects the items that are in the table you are joining on that have matches in the table being joined to. This should allow you to select unbooked data. If this doesn't fit your situation, including your queries in your question might help us answer your problem more directly.
mysql> SELECT tabl1.number,tabl1.areano FROM tabl1 LEFT JOIN tabl2 using(number,
areano) WHERE tabl2.number IS NULL; ;
+--------+--------+
| number | areano |
+--------+--------+
| 6 | A |
| 7 | A |
+--------+--------+

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