On Dropdown Selection, how to fill complete form fields from Database - php

Question

How to fill the complete form input fields from Database based on the value selected from the Dropdown
Example: In a Application, by selecting a client name it fills the complete form input fields with the details stored in the Database.
Sample Code:
<select name="client">
<option value="">-- Select Client Name -- </option>
<option value="1">John</option>
<option value="2">Smith</option>
</select>
<input name="phone" type="text" value="">
<input name="email" type="text" value="">
<input name="city" type="text" value="">
<textarea name="address"></textarea>
All the about input fields need to be filled with values on client name selection.
EDIT:
I tried with AJAX but couldn't able get the particular variable from the file... below is my code:
<script>
$(document).ready(function() {
$('#client').change(function() {
alert();
var selected = $(this).find(':selected').html();
$.post('get_details.php', {'client': selected}, function(data) {
$('#result').html(data);
});
});
});
</script>
In the get_details.php file I am storing different values in different variables, but I didn't understand how to get them to individual variable to main page.

Answer 1

This is a just a basic jQuery example that calls itself (the top portion of the script is active when a $_POST is made), which I have named index.php as indicated in the url of the jQuery AJAX. You can use two separate pages to do this if you want. Just separate out the PHP from the HTML/Javascript and change the url: '/index.php':
<?php
// This is where you would do any database call
if(!empty($_POST)) {
// Send back a jSON array via echo
echo json_encode(array("phone"=>'123-12313',"email"=>'test#test.com','city'=>'Medicine Hat','address'=>'556 19th Street NE'));
// Exit probably not required if you
// separate out your code into two pages
exit;
}
?>
<form id="tester">
<select name="client" id="client">
<option value="">-- Select Client Name -- </option>
<option value="1">John</option>
<option value="2">Smith</option>
</select>
<input name="phone" type="text" value="">
<input name="email" type="text" value="">
<input name="city" type="text" value="">
<textarea name="address"></textarea>
</form>
<!-- jQuery Library required, make sure the jQuery is latest -->
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script>
$(document).ready(function() {
// On change of the dropdown do the ajax
$("#client").change(function() {
$.ajax({
// Change the link to the file you are using
url: '/index.php',
type: 'post',
// This just sends the value of the dropdown
data: { client: $(this).val() },
success: function(response) {
// Parse the jSON that is returned
// Using conditions here would probably apply
// incase nothing is returned
var Vals = JSON.parse(response);
// These are the inputs that will populate
$("input[name='phone']").val(Vals.phone);
$("input[name='email']").val(Vals.email);
$("input[name='city']").val(Vals.city);
$("textarea[name='address']").val(Vals.address);
}
});
});
});
</script>

Answer 2

When you made ajaxCall return data in json format like
json_encode(array("phone"=>'123-12313',"email"=>'test#test.com','city'=>'Medicine Hat','address'=>'556 19th Street NE'));
above shown
then parse it in jQuery and put the value in different selectors like
var Vals = JSON.parse(response);
// These are the inputs that will populate
$("input[name='phone']").val(Vals.phone);
above shown.