MySQL row being outputted twice - php

Question

I need to output a name from the last added row of my table, and it works sort of, it outputs the correct data twice. So instead of name1 it gives me name1name1. I'm still a novice with PHP but i think there is a double loop somewhere in this piece of code which is giving me a hard time, but i'm still unable to locate where that is..
If someone can give me a pointer that would be greatly appreciated.
<?php $query="SELECT question FROM poll ORDER BY id DESC LIMIT 1";
$results = mysql_query($query);
while ($row = mysql_fetch_array($results)) {
echo '<tr>';
foreach($row as $field) {
echo '<td>' . htmlspecialchars($field) . '</td>';
}
echo '</tr>';
} ?>

Answer 1

By default, mysql_fetch_array() returns values both as associative and as enumerated (MYSQL_BOTH); specify either one or the other
while ($row = mysql_fetch_array($results, MYSQL_ASSOC)) {
EDIT
But the mysql extension is old and deprecated, and you really should be switching to mysqli or pdo with prepared statements and bind variables. If you're just learning, then it's best to learn the right methods with the right extensions from the start

Answer 2

No need of the while. You are fetching a single row. And use mysql_fetch_assoc for associative array
$row = mysql_fetch_assoc($results);
echo '<tr>';
foreach($row as $field) {
echo '<td>' . htmlspecialchars($field) . '</td>';
}
echo '</tr>';

Answer 3

I would use mysql_fetch_assoc. Because this will only fetch the results as an associative array.
$query="SELECT question FROM poll ORDER BY id DESC LIMIT 1";
$results = mysql_query($query);
while ($row = mysql_fetch_assoc($results)) {
echo '<tr>';
foreach($row as $field) {
echo '<td>' . htmlspecialchars($field) . '</td>';
}
echo '</tr>';
}