So basically, I have a big string with some other information, and somewhere at the end, I have the following structure of a string:
62AC979D-5277D720
It is numbers and uppercase letters. I would like to extract this substring from many lines of the bigger strings which all contain it at different places. I have tried:
preg_match('/^[\w]+$/', $string);
But I really don't have much experience with regular expressions. Can someone provide the regex necessary or at least tell me where I am mistaken? Thank you for your time!
This regex should do it for you,
([A-Z\d]{8}-[A-Z\d]{8})
in use
<?php
$string = 'This is 62AC979D-5277D720 the whole string.';
preg_match_all('~([A-Z\d]{8}-[A-Z\d]{8})~', $string, $value);
print_r($value[1]);
Your current regex fails I suspect because of the ^ and $. These mark the start and end of the string you are searching for (or line if the m modifier is used). The \w is also a-z, A-Z, 0-9 and _. I think you only care about capital letters and you want to allow only one dash. If the target will also always only be 8 characters you can add the {8} in place of the +. The () are to capture the value that is found. The first found value in $string will be $value[1][0].
Demo: http://sandbox.onlinephpfunctions.com/code/c6b2c391d95c5454a3c7ea81d5ac4a3bb8e49aef
preg_match_all('/\\b[0-9A-Z]+-[0-9A-Z]+\\b/')
This should do it for you.
preg_match('/\\b[0-9A-Z]{8}-[0-9A-Z]{8}\\b/', $string);
This works for the string you gave i.e 8 numbers or alphabets followed by - and then numbers and alphabets again
You try this.
preg_match('/^[0-9A-Z]{8}-[0-9A-Z]{8}$/', $string)
Related
I'am quite new in regex and php but I'm facing an issue I can't handle alone.
I've prepared this regex to find patterns starting with upper-case letter. It could sounds something like :
capture any pattern that
starts with one or more Upper-case letter
then one or more any letter or character in the list
then a space, or punctuation mark
and I use a backreference to set I want those pattern up to 3 times :
([A-ZÁÀÂÄÉÈÊËÍÌÎÏÓÒÔÖÚÙÛÜ]{1,}[a-zàáâãäåçèéêëìíîïðòóôõöùúûüýÿ;:«0-9]{1,}[\s-….?,;]\1{1,3})
According to https://regex101.com/r/pB3nY7/2 it works as a javascript regex but not as a php regex.
I've rade the other posts and make sure :
I use single quotes instead of double quotes
and I "protected" the \ in my php script :
'#([A-ZÁÀÂÄÉÈÊËÍÌÎÏÓÒÔÖÚÙÛÜ]{1,}[a-zàáâãäåçèéêëìíîïðòóôõöùúûüýÿ;:«0-9]{1,}[\\s-….?,;]\\1{1,3})#'
But it still can't match any pattern starting with a Upper-case letter.
Thank you in advance for all advice you may provide,
Regards,
Charles
i have tested it on this website http://www.phpliveregex.com/ :
(^[A-ZÁÀÂÄÉÈÊËÍÌÎÏÓÒÔÖÚÙÛÜ]{1,}[a-zàáâãäåçèéêëìíîïðòóôõöùúûüýÿ;:«0-9]{1,}[\s-….?,;]{1,1}){1,3}
To be more generalist, you could use unicode properties:
^(\p[Lu}+[\p{Ll};:«0-9]+[\s\p{P}]){1,3}
Where \p[Lu} stands for an uppercase letter, \p{Ll} a lowercase letter and \p{P} a punctuation.
preg_match('/^(\p[Lu}+[\p{Ll};:«0-9]+[\s\p{P}]){1,3}/', $string, $match);
I'm using this regex to get house number of a street adress.
[a-zA-ZßäöüÄÖÜ .]*(?=[0-9])
Usually, the street is something like "Ohmstraße 2a" or something. At regexpal.com my pattern matches, but I guess preg_replace() isn't identical with it's regex engine.
$num = preg_replace("/[a-zA-ZßäöüÄÖÜ .]*(?=[0-9])/", "", $num);
Update:
It seems that my pattern matches, but I've got some encoding problems with the special chars like äöü
Update #2:
Turns out to be a encoding problem with mysqli.
First of all if you want to get the house number then you should not replace it. So instead of preg_replace use preg_match.
I modified your regex a little bit to match better:
$street = 'Öhmsträße 2a';
if(preg_match('/\s+(\d+[a-z]?)$/i', trim($street), $matches) !== 0) {
var_dump($matches);
} else {
echo 'no house number';
}
\s+ matches one or more space chars (blanks, tabs, etc.)
(...) defines a capture group which can be accesses in $matches
\d+ matches one or more digits (2, 23, 235, ...)
[a-z] matches one character from a to z
? means it's optional (not every house number has a letter in it)
$ means end of string, so it makes sure the house number is at the end of the string
Make sure you strip any spaces after the end of the house number with trim().
The u modifier can help sometimes for handling "extra" characters.
I feel this may be a character set or UTF-8 issue.
It would be a good idea to find out what version of PHP you're running too. If I recall correctly, full Unicode support came in around 5.1.x
I'm having a bit of difficulties converting some regex from being used in preg_match_all to being used in preg_replace.
Basically, via regex only, I would like to match uppercase characters that are preceded by either a space, beginning of text, or a hypen. This is not a problem, I have the following for this which works well:
preg_match_all('/(?<= |\A|-)[A-Z]/',$str,$results);
echo '<pre>' . print_r($results,true) . '</pre>';
Now, what I'd like to do, is to use preg_replace to only return the string with the uppercase characters that match my criteria above. If I port the regex straight into preg_replace, then it obviously replaces the characters I want to keep.
Any help would be much appreciated :)
Also, I'm fully aware regex isn't the best solution for this in terms of efficiency, but nonetheless I would like to use preg_replace.
According to De Morgan's laws,
if you want to keep letters that are
A-Z, and
preceded by [space], \A, or -
then you'd want to remove characters that are
not A-Z, or
not preceded by [space], \A, or -
Perhaps this (replace match with empty string)?
/[^A-Z]|(?<! |\A|-)./
See example here.
I think it will be something like this:
$sString = preg_replace('#.*?(?<= |\A|-)([A-Z])([a-z]+)#m',"$1", $sString);
Im about to create a registration form for my website. I need to check the variable, and accept it only if contains letter, number, _ or -.
How can do it with regex? I used to work with them with preg_replace(), but i think this is not the case. Also, i know that the "ereg" function is dead. Any solutions?
this regex is pretty common these days.
if(preg_match('/^[a-z0-9\-\_]+$/i',$username))
{
// Ok
}
Use preg_match:
preg_match('/^[\w-]+$/D', $str)
Here \w describes letters, digits and the _, so [\w-]+ matches one or more letters, digits, _, and -. ^ and $ are so called anchors that denote the begin and end of the string respectively. The D modifier avoids that $ really matches the end of the string and is not followed by a line break.
Note that the letter and digits that are matched by \w depend on the current locale and might match other letter or digits than just [a-zA-Z0-9]. So if you just want these, use them explicitly. And if you want to allow more than these, you could also try character classes that are describes by Unicode character properties like \p{L} for all Unicode letters.
Try preg_match(). http://php.net/manual/en/function.preg-match.php
How would I go about removing numbers and a space from the start of a string?
For example, from '13 Adam Court, Cannock' remove '13 '
Because everyone else is going the \d+\s route I'll give you the brain-dead answer
$str = preg_replace("#([0-9]+ )#","",$str);
Word to the wise, don't use / as your delimiter in regex, you will experience the dreaded leaning-toothpick-problem when trying to do file paths or something like http://
:)
Use the same regex I gave in my JavaScript answer, but apply it using preg_replace():
preg_replace('/^\d+\s+/', '', $str);
Try this one :
^\d+ (.*)$
Like this :
preg_replace ("^\d+ (.*)$", "$1" , $string);
Resources :
preg_replace
regular-expressions.info
On the same topic :
Regular expression to remove number, then a space?
regular expression for matching number and spaces.
I'd use
/^\d+\s+/
It looks for a number of any size in the beginning of a string ^\d+
Then looks for a patch of whitespace after it \s+
When you use a backslash before certain letters it represents something...
\d represents a digit 0,1,2,3,4,5,6,7,8,9.
\s represents a space .
Add a plus sign (+) to the end and you can have...
\d+ a series of digits (number)
\s+ multiple spaces (typos etc.)
The same regex I gave you on your other question still applies. You just have to use preg_replace() instead.
Search for /^[\s\d]+/ and replace with the empty string. Eg:
$str = preg_replace(/^[\s\d]+/, '', $str);
This will remove digits and spaces in any order from the beginning of the string. For something that removes only a number followed by spaces, see BoltClock's answer.
If the input strings all have the same ecpected format and you will receive the same result from left trimming all numbers and spaces (no matter the order of their occurrence at the front of the string), then you don't actually need to fire up the regex engine.
I love regex, but know not to use it unless it provides a valuable advantage over a non-regex technique. Regex is often slower than non-regex techniques.
Use ltrim() with a character mask that includes spaces and digits.
Code: (Demo)
var_export(
ltrim('420 911 90210 666 keep this part', ' 0..9')
);
Output:
'keep this part'
It wouldn't matter if the string started with a space either. ltrim() will greedily remove all instances of spaces or numbers from the start of the string intil it can't anymore.