Format number from (-/+)xx.xxxxxxxxx to xxxx.xxxx in PHP - php

i need to arrange a number to a format like this xxxx.xxxx. But I get as input something like this (-/+)xx.xxxxxxxxx.
If the number is x.xx it should get the above mentioned format by adding 0s to end and front.
please guide me on the correct way to get this done!

You can use explode & str_pad -
$num = 7.89;
$temp = explode('.', $num);
echo str_pad($temp[0], 4, 0, STR_PAD_LEFT).'.'.str_pad($temp[1], 4, 0, STR_PAD_RIGHT);
Output
0007.8900

You can use sprintf("%f4.6");
The number before the dot would determine de number of digits fot the integer part and de other, the number of decimals

Related

Convert strings to numbers without losing decimals

I'm developing a map and I have to save this parameters on Parse database:
lat.: 20.6350 . Long: -103.5334
The problem is when i convert them into numbers, that function converts 20.6350 to 20.635. ¿What can I do in order tu preserve the last zero?
You should specify the sig figs and they will display properly.
$lat = "20.6350";
$lng = "-103.5334";
print number_format($lat, 4); // 4 sig figs
print number_format($lng, 4);
See http://php.net/number_format for additional formatting info
UPDATE
Based on your comments above, seems the string you're pulling varies in length, correct?
Why not just get the amount of sig figs after the decimal then use that as the second argument in number_format()? I'm sure there is a more appropriate way to handle, but this would work I believe.
// Calculate sig figs
$length = strlen($lng) - (stripos($lng, '.') + 1);
number_format($lng, $length);
or in one line
number_format($lng, strlen($lng) - (stripos($lng, '.') + 1));
if you want the numbers with four decimals in your database you could use the Decimal type. Under length you could enter 6,4 representing maximum of 6 digits in total and 4 digits behind the point.
If you want to display the number in PHP you could use the number_format() function
echo number_format($longitude, 4);

PHP Number Formatting

I have been trying all morning but how would I this number 1304583496 to look like this
13.04583496
and the same goes for this number
456604223 to 4.56604223
There are always 8 numbers to the right.
Divide it with 100000000, or use "pow" function:
$number / pow(10, 8);
You could also use the official number_format method after division to keep your ending zeroes and have your number displayed in a nice manner.
<?php
$num = 1304583496; //the number
echo number_format($num/100000000,8,"."," "); //number of decimals = 8, comma seperator is . and thousands seperator is a space here
?>
For more information on this function: http://www.w3schools.com/php/func_string_number_format.asp

PHP add thousand separators to number and keep leading zeros

I'm trying to add thousand separators to a number using PHP and at the same time keep the leading zeros (It's part of the design of an app that the leading 0s stay so that people can see the number grow towards the set target - a 6 figure number).
My initial attempt was to use str_pad to add the leading zeros if the current number calculated was less than 6 figures long. Then to add the commas I used number_format. The obvious issue is that number_format removes the leading 0s.
$num = 550;
$num_padded = str_pad($num, 6, '0', STR_PAD_LEFT);
echo number_format($num_padded);
So that returns 550 instead of 000,550
Does anyone know of a reliable way to achieve the format I'm looking for?
Thanks!
I have in mind this simple trick:
function padAndFormat($number, $length)
{
if(strlen($number)>=$length)
{
return number_format($number);
}
$number = number_format('1'.str_pad($number, $length-1, '0', STR_PAD_LEFT));
$number[0] = '0';
return $number;
}
//var_dump(padAndFormat('517', 6)); //string(7) "000,517"
another way to do this is to use sprintf
// length can be changed, here is 6
implode(',',str_split(sprintf('%06d', $this->iterator),3));
the result will be :
input
result
4
000,004
400
000,400
23560
023,560
1234567
1,234,567
it can be improved by reading the length, and computing automatically the final length, multiple of 3
I don't need number format but I need that comma! :)
<?php
$zeroes=0;
$num = 550;
$num_padded = str_pad($zeroes, 3, '0', STR_PAD_LEFT);
$num_padded = str_pad($num_padded,strlen($num_padded)+strlen($zeroes), ',', STR_PAD_RIGHT);
$num_padded = str_pad($num_padded,strlen($num_padded)+strlen($num), $num, STR_PAD_RIGHT);
echo $num_padded;
OUTPUT :
000,550
One Liner with PHP string manipulation. Works for any number of digits:
function pad($number, $min_digits){
return strrev(implode(",",str_split(str_pad(strrev($number), $min_digits, "0", STR_PAD_RIGHT),3)));
}
/* Output for 9 digits
0,000,001
0,000,012
0,000,123
0,001,234
0,012,345
0,123,456
1,234,567
12,345,678
123,456,789
/**/

How can I separate a number and get the first two digits in PHP?

How can I separate a number and get the first two digits in PHP?
For example: 1345 -> I want this output=> 13 or 1542 I want 15.
one possibility would be to use substr:
echo substr($mynumber, 0, 2);
EDIT:
please not that, like hakre said, this will break for negative numbers or small numbers with decimal places. his solution is the better one, as he's doing some checks to avoid this.
First of all you need to normalize your number, because not all numbers in PHP consist of digits only. You might be looking for an integer number:
$number = (int) $number;
Problems you can run in here is the range of integer numbers in PHP or rounding issues, see Integers Docs, INF comes to mind as well.
As the number now is an integer, you can use it in string context and extract the first two characters which will be the first two digits if the number is not negative. If the number is negative, the sign needs to be preserved:
$twoDigits = substr($number, 0, $number < 0 ? 3 : 2);
See the Demo.
Shouldn't be too hard? A simple substring should do the trick (you can treat numbers as strings in a loosely typed language like PHP).
See the PHP manual page for the substr() function.
Something like this:
$output = substr($input, 0, 2); //get first two characters (digits)
You can get the string value of your number then get the part you want using
substr.
this should do what you want
$length = 2;
$newstr = substr($string, $lenght);
With strong type-hinting in new version of PHP (> PHP 7.3) you can't use substr on a function if you have integer or float. Yes, you can cast as string but it's not a good solution.
You can divide by some ten factor and recast to int.
$number = 1345;
$mynumber = (int)($number/100);
echo $mynumber;
Display: 13
If you don't want to use substr you can divide your number by 10 until it has 2 digits:
<?php
function foo($i) {
$i = abs((int)$i);
while ($i > 99)
$i = $i / 10;
return $i;
}
will give you first two digits

Advanced Php Number Formatting

I want to have a PHP number formatted with a minimum of 2 decimal places and a maximum of 8 decimal places. How can you do that properly.
Update: I'm sorry, my question is say I have number "4". I wish for it to display as "4.00" and if I have "2.000000001" then it displays as "2.00" or if I have "3.2102" it will display as such. There is a NSNumber formatter on iPhone, what is the equivalent in PHP.
This formats the $n number for 8 decimals, then removes the trailing zero, max 6 times.
$s = number_format($n, 8);
for($i=0; $i<8-2; $i++) {
if (substr($s, -1) == '0')
$s = substr($s, 0, -1);
}
print "Number = $s";
Use sprintf() to format a number to a certain number of decimal places:
$decimal_places = 4;
$format = "%.${decimal_places}f";
$formatted = sprintf($format,$number);
I don't understand why you would want to display numbers to an inconsistent degree of accuracy. I don't understand what pattern you're trying to describe in your comment, either.
But let us suppose that you want the following behaviour: you want to express the number to 8 decimal places, and if there are more than 2 trailing zeroes in the result, you want to remove the excess zeroes. This is not much more difficult to code than it is to express in English. In pseudocode:
$mystring = string representation of number rounded to 8 decimal places;
while (last character of $mystring is a 0) {
chop off last character of $mystring;
}
Check the number format function:
<?php
$num = 43.43343;
$formatted = number_format(round((float) $num, 2), 2);
?>
http://php.net/manual/en/function.number-format.php
Using preg_match just get the zero ending with and then rtim it
<?php
$nn = number_format(10.10100011411100000,13);
preg_match('/[0]+$/',$nn,$number);
if(count($number)>0){
echo rtrim($nn,$number[0]);
}
Hope it will help you.

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