send the selected value from a dropdown menu to another page - php

Question

I have a dropdownlist populated by a MySql database that shows the titles of books stored in my database.
<select id="titles">
<option value="emp" selected>Choose the title</option>
<?php
//drop down list populated by mysql database
$sql = mysql_query("SELECT title FROM book");
while ($row = mysql_fetch_array($sql))
{
echo '<option value="'.$row['title'].'">'.$row['title'].'</option>';
}
?>
I want the option I choose to send it to another php page search.php
This search.php I want it to get the title and search for this specific book details.(title, price, author.... etc) .I tried to do it with but it ruins the page.

Answer 1

Add below code in form that should work for you.
<form action='search.php' method='post'>
<select id="titles" name='titles'>
<option value="emp" selected>Choose the title</option>
<?php
//drop down list populated by mysql database
$sql = mysql_query("SELECT title FROM book");
while ($row = mysql_fetch_array($sql))
{
echo '<option value="'.$row['title'].'">'.$row['title'].'</option>';
}
?>
<input type='submit' value='submit'>
</form>
in search.php:
$title = $_POST['titles'];

Answer 2

You just need to add the form above the select tag and need to give the NAME attribute in the select tag to post the data on another page. You can try with the following code:
<form method="post" action="search.php">
<select id="titles" name="titles">
<option value="emp" selected>Choose the title</option>
<?php
//drop down list populated by mysql database
$sql = mysql_query("SELECT title FROM book");
while ($row = mysql_fetch_array($sql))
{
echo '<option value="'.$row['title'].'">'.$row['title'].'</option>';
}
?>
</select>
<input type="submit" name="submit"/>
</form>
and on the search.php page, you can get the value of the dropdown by this:
$title = $_POST['titles'];

Answer 3

Try as below :
<form method="post" action="YOURPAGEPATH">
<select id="titles">
<option value="emp" selected>Choose the title</option>
<?php
//drop down list populated by mysql database
$sql = mysql_query("SELECT title FROM book");
while ($row = mysql_fetch_array($sql))
{
echo '<option value="'.$row['title'].'">'.$row['title'].'</option>';
}
?>
</select>
<input type="submit" name="submit"/>
</form>
Without submit button :
<form method="post">
<select id="titles" onchange="this.form.submit();">
<option value="emp" selected>Choose the title</option>
<?php
//drop down list populated by mysql database
$sql = mysql_query("SELECT title FROM book");
while ($row = mysql_fetch_array($sql))
{
echo '<option value="'.$row['title'].'">'.$row['title'].'</option>';
}
?>
</select>
</form>

Answer 4

Surround that with a form with the appropriate action and add a submit button. Otherwise use something like jQuery to listen for the value of that to change and submit the form.
For example:
<form action="search.php" method="GET">
<select id="titles" name="title">
<?php /* put your stuff here */ ?>
</select>
</form>
And then in jQuery:
$(function(){
$('#titles').on('change', function(){
$(this).closest('form').submit();
});
});
Or you could go real old-school and attach the event listener to the select like this:
<form action="search.php" method="GET">
<select id="titles" name="title" onchange="this.parentNode.submit()">
<?php /* put your stuff here */ ?>
</select>
</form>

Answer 5

Just in case if you don't want to use the Submit Button
<script language="Javascript">
function books(book)
{
var url="http://www.example.com/search.php/?q="+book;
window.open(url, "_self");
}
</script>
<select id="titles">
<option value="emp" selected>Choose the title</option>
<?php
//drop down list populated by mysql database
$sql = mysql_query("SELECT title FROM book");
while ($row = mysql_fetch_array($sql))
{
echo '<option onClick="books('.$row['title'].')" value="'.$row['title'].'">'.$row['title'].'</option>';
}
?>
Here the list will call the Books function on Click and pass the arguments to the function which will redirect you to search.php
To retrieve the book name use
$_GET["q"]
Change the URL as required.
And if the problem is solved don't forget to Mark the answer.