I am interested in collecting data from the last month in the database with MySQLi.
But using INTERVAL 1 MONTH each month overlaps the other, so is there a way to tell the function to check my current month, start from the first day, and collect all data from said month?
Something like:
SELECT count(DISTINCT ip) AS visitor_ip FROM visitor_list
WHERE visited_date > ( INTERVAL CURRENT_MONTH_BEGINNING)
You can just use the current year and month, and 01 as the day:
SELECT count(DISTINCT ip) AS visitor_ip
FROM visitor_list
WHERE visited_date > CONCAT(DATE_FORMAT(NOW(),'%Y%m'), '01')
This has the advantage that any index on visited_date will still be used correctly.
First you need to generate current month starting date from PHP like this:
$monthStartDate = date('Y-m').'-01';
Then your query will become:
$sql = "SELECT count(DISTINCT ip) AS visitor_ip FROM visitor_list WHERE visited_date > DATE_SUB(now(), interval (datediff(now(), '".$monthStartDate."')) day)";
Related
I have a mysql table orders in that I have a column order_date which is current time stamp(2016-08-17 00:00:00.000000). now I want to select or count the data's entered this month and the previous month, after this I can find the difference between these two months I am using this code and it is not working.
$sql="SELECT * FROM order WHERE order_date > DATE_SUB(NOW(), INTERVAL 1 MONTH)";
$result = $this->db->query($sql);
return $result;
this is not working an mysql error is produced.
Try
$sql="SELECT * FROM order WHERE DATE(order_date) LIKE DATE_SUB(CURDATE(), INTERVAL 1 MONTH)";
$result = $this->db->query($sql);
return $result;
i think this Link[http://sqlhints.com/2015/07/10/how-to-get-difference-between-two-dates-in-years-months-and-days-in-sql-server/] will help you
Use this. Hope it helps what you want. Thanks
$todayDate = date('Y-m-d');
$todayMonth = date("m", strtotime($todayDate ));
$previousMonth = $todayMonth - 1;
$sql = "SELECT * FROM order WHERE MONTH(order_date) BETWEEN '$todayMonth' AND '$previousMonth'";
First, the following is the correct logic to get all values from the current month and all of the previous month:
select *
from orders o
where order_date >= date_sub(date_sub(curdate(), interval day(curdate) - 1 day), interval 1 month);
Then, use conditional aggregation for comparison. Here is an easy way:
select sum(month(order_date) = month(curdate())) as cur_month,
sum(month(order_date) <> month(curdate())) as prev_month,
(sum(month(order_date) = month(curdate())) -
sum(month(order_date) <> month(curdate()))
) as diff
from orders o
where order_date >= date_sub(date_sub(curdate(), interval day(curdate) - 1 day), interval 1 month);
Note: I don't fully see the utility of comparing a partial month (this month) to a full month (last month), but that is what you seem to be asking for. If you are asking for something different, then ask another question with sample data and desired results.
Need help writing a function for database. I want to keep track of the total cost of member orders each month based on their signup date. So if someone signed up in the middle of the month, the function should add 30 days to their signup date and sum the sales whithin that period and place in database. Then display on user page. Using mysql functions (not PDO or mysqli for now).
Something like:
<?php
$query = ("SELECT SUM(cost) FROM memberOrders WHERE
memberNumber='$memberNumber' GROUP BY signupdate+30days");
?>
But it can't be just 30 days...it should be +30, +60, +90...That's the part I'm stuck on. Thanks!
calculate the start/end date in PHP and make use of a subquery:
SELECT SUM(cost) FROM
(Select cost, membernumber from memberOrders WHERE
memberNumber='$memberNumber' and date >= '$startdate' and date <= '$enddate'
GROUP BY substr(date, 7))
GRoup by membernumber
Assuming you have both the signup date and order date in MemberOrders, the following will return all months with orders:
SELECT datediff(orderdate, signupdate, interval month) as MonthsAfter,
SUM(cost) as MonthCost
FROM memberOrders
WHERE memberNumber='$memberNumber'
GROUP BY datediff(orderdate, signupdate, interval month)
If you have all months having 30-days, you can do:
SELECT floor(datediff(orderdate, signupdate, interval day)/30) as Months,
SUM(cost) as MonthCost
FROM memberOrders
WHERE memberNumber='$memberNumber'
GROUP BY floor(datediff(orderdate, signupdate, interval day)/30)
Note: both of these assign "0" to the first month after signup. Add +1 if you want to start at 1.
I have to filter the results of an SQL starting at the current day and displaying all records until the current day + 10 days. So if it's the 22th of December I should display all records starting that day and that aren't after the the 1st of January. How can I do this? I tried a simple query like the one below but it seems to only display the records until the last day of the current month and then instead of showing the records of the next year goes back to the first month of the current year.
SELECT *
FROM mytable
WHERE DAY(mydatefield) >= DAY(CURRENT_TIMESTAMP)
AND mydatefield <= DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 10 DAY)
EDIT 1
I'm using Symfony 2 + Doctrine 2 querybuilder so the query must be compatible with them
EDIT 2
I solved the Doctrine 2 problem by using the query suggested by eggyal with this PHP code
$queryBuilder->where($queryBuilder->expr()->gte('mydatefield', 'CURRENT_DATE()'))->andWhere($queryBuilder->expr()->lte('mydatefield', 'DATE_ADD(CURRENT_DATE(), 10, \'DAY\')'));
The problem lies in your erroneous use of MySQL's DAY() function, which returns the day of the month. You should use instead DATE(); you can also simplify with the BETWEEN ... AND ... comparison operator:
SELECT *
FROM mytable
WHERE DATE(mydatefield) BETWEEN CURDATE() AND CURDATE() + INTERVAL 10 DAY
Note that, in order to benefit from index optimisation, you could instead do:
SELECT *
FROM mytable
WHERE mydatefield >= CURDATE() AND mydatefield < CURDATE() + INTERVAL 11 DAY
You should be able to use this:
SELECT *
FROM mytable
WHERE date(mydatefield) >= date(CURRENT_TIMESTAMP)
AND date(mydatefield) <= date(DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 10 DAY))
See SQL Fiddle with Demo
try this
SELECT *
FROM mytable
WHERE DATE( mydatefield ) BETWEEN CURRENT_DATE AND CURRENT_DATE + INTERVAL 10 DAY
I have the following relation in my schema:
Entries:
entryId(PK) auto_inc
date date
In order to count the total entries in the relation I use a query in my php like this:
$sql = mysql_query("SELECT COUNT(*) as Frequency FROM Entries WHERE date = '$date'");
My question is how can I count the number of entries for the CURRENT month..
You want a between query based on your date column.
WHERE date BETWEEN startdate AND enddate.
Between is equivalent to date >= startdate AND date <= enddate. It would of course be also possible to just use >= AND < explicitly which would simplify it a bit because you don't need to find the last day of the month, but just the first day of the following month using only DATE_ADD(..., INTERVAL 1 MONTH).
However startdate and enddate in this case would be derived from CURDATE().
You can use CURDATE(), MONTH(), DATE_ADD and STR_TO_DATE to derive the dates you need (1st day of current month, last day of current month). This article solves a similar problem and all the techniques needed are shown in examples that you should be able to adapt:
http://www.gizmola.com/blog/archives/107-Calculate-a-persons-age-in-a-MySQL-query.html
The first day of the current month is obvious YEAR-MONTH(CURDATE())-01. The last day you can calculate by using DATE_ADD to add 1 Month to the first day of the current month, then DATE_ADD -1 Days.
update-
Ok, I went and formulated the full query. Don't think str_to_date is really needed to get the index efficiency but didn't actually check.
SELECT count(*)
FROM entries
WHERE `date` BETWEEN
CONCAT(YEAR(CURDATE()), '-', MONTH(CURDATE()), '-', '01')
AND
DATE_ADD(DATE_ADD(CONCAT(YEAR(CURDATE()), '-', MONTH(CURDATE()), '-', '01'), INTERVAL 1 MONTH), INTERVAL -1 DAY);
Try this
SELECT COUNT(1) AS `Frequency`
FROM `Entries`
WHERE EXTRACT(YEAR_MONTH FROM `date`) = EXTRACT(YEAR_MONTH FROM CURDATE())
See EXTRACT() and CURDATE()
Edit: Changed NOW() to CURDATE() as it is more appropriate here
Try
$sql = mysql_query("SELECT COUNT(*) as Frequency FROM Entries WHERE MONTH(date) = MONTH(NOW()) );
I'm looking for a best practice advice how to speed up queries and at the same time to minimize the overhead needed to invoke date/mktime functions. To trivialize the problem I'm dealing with the following table layout:
CREATE TABLE my_table(
id INTEGER PRIMARY KEY NOT NULL AUTO_INCREMENT,
important_data INTEGER,
date INTEGER);
The user can choose to show 1) all entries between two dates:
SELECT * FROM my_table
WHERE date >= ? AND date <= ?
ORDER BY date DESC;
Output:
10-21-2009 12:12:12, 10002
10-21-2009 14:12:12, 15002
10-22-2009 14:05:01, 20030
10-23-2009 15:23:35, 300
....
I don't think there is much to improve in this case.
2) Summarize/group the output by day, week, month, year:
SELECT COUNT(*) AS count, SUM(important_data) AS important_data
FROM my_table
WHERE date >= ? AND date <= ?
ORDER BY date DESC;
Example output by month:
10-2009, 100002
11-2009, 200030
12-2009, 3000
01-2010, 0 /* <- very important to show empty dates, with no entries in the table! */
....
To accomplish option 2) I'm currently running a very costly for-loop with mktime/date like the following:
for(...){ /* example for group by day */
$span_from = (int)mktime(0, 0, 0, date("m", $time_min), date("d", $time_min)+$i, date("Y", $time_min));
$span_to = (int)mktime(0, 0, 0, date("m", $time_min), date("d", $time_min)+$i+1, date("Y", $time_min));
$query = "..";
$output = date("m-d-y", ..);
}
What are my ideas so far? Add additional/ redundant columns (INTEGER) for day (20091212), month (200912), week (200942) and year (2009). This way I can get rid of all the unnecessary queries in the for loop. However I'm still facing the problem to very fastly calculate all dates that doesn't have any equivalent in database. One way to simply move the problem could be to let MySQL do the job and simply use one big query (calculate all the dates/use MySQL date functions) with a left join (the data). Would it be wise to let MySQL take the extra load? Anyway I'm reluctant to use all these mktime/date in the for loop. Since I have complete control over the table layout and code even suggestions with major changes are welcome!
Update
Thanks to Greg I came up with the following SQL query. However it still bugs me to use 50 lines of sql statements - build up with php - that maybe could be done faster and more elegantly otherwise:
SELECT * FROM (
SELECT DATE_ADD('2009-01-30', INTERVAL 0 DAY) AS day UNION ALL
SELECT DATE_ADD('2009-01-30', INTERVAL 1 DAY) AS day UNION ALL
SELECT DATE_ADD('2009-01-30', INTERVAL 2 DAY) AS day UNION ALL
SELECT DATE_ADD('2009-01-30', INTERVAL 3 DAY) AS day UNION ALL
......
SELECT DATE_ADD('2009-01-30', INTERVAL 50 DAY) AS day ) AS dates
LEFT JOIN (
SELECT DATE_FORMAT(date, '%Y-%m-%d') AS date, SUM(data) AS data
FROM test
GROUP BY date
) AS results
ON DATE_FORMAT(dates.day, '%Y-%m-%d') = results.date;
You definitely shouldn't be doing a query inside a loop.
You can group like this:
SELECT COUNT(*) AS count, SUM(important_data) AS important_data, DATE_FORMAT('%Y-%m', date) AS month
FROM my_table
WHERE date BETWEEN ? AND ? -- This should be the min and max of the whole range
GROUP BY DATE_FORMAT('%Y-%m', date)
ORDER BY date DESC;
Then pull these into an array keyed by date and loop over your data range as you are doing (that loop should be pretty light on CPU).
Another idea is not to use string inside the query. Transform the string parameter to datetime, on mysql.
STR_TO_DATE(str,format)
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html