Checking if value returned is empty [duplicate] - php

Question

This question already has answers here:
Check if a row exists using old mysql_* API
(6 answers)
Closed 7 years ago.
I have a simple PHP file in which I check if the users email exists in my database using the following code:
$query = "SELECT * FROM userData WHERE email = '$email'";
$result = mysql_query($query);
Which works perfectly fine when the user enters an email address that is in the database, however, when I want to determine if this $query is null or empty - I'm not sure which one though.
When I enter an email that isn't in the database and add the following code in below:
if(is_null($result)){
echo 'email not in database';
}
the code in the {} isn't executed.
I was just wondering if you could help me out.
Hi again,
Sorry for the duplicating another post. I corrected it by using:
if(mysqli_num_rows($result) > 0)
{
// a row with email exists
}
else
{
// no row with particular email exists
}

Answer 1

You can directly check whether your query executed or not by
if($result > 0){
// perform some action
}
You should use mysqli_ instead of mysql_ as it is deprecated and will be removed in future.
what you need is mysqli_num_rows() to see if atleast 1 row was in the table or not
for reference - num_rows
if(mysqli_num_rows($result) > 0)
{
// a row with email exists
}
else
{
// no row with particular email exists
}

Answer 2

Try this
$row = mysql_fetch_rows($result);
if(!$row){
echo 'email not in database';
}
OR
$num = mysql_num_rows($result);
if($num == 0){
echo 'email not in database';
}

Answer 3

You can try this too !
if(empty($result)){
echo 'email not in database';
}
empty() will check if $result is null, or its value is 0, or if $result doesn't exists.
See here : http://php.net/manual/fr/function.empty.php