i want to fetch youtube videos from the above script but the above code is getting keyword from GET parameter example.com/s=keyword and i want it to get from a example.com/HERE
i mean you can see there is a $_GET['s']
So this function works like this
example.com/s=keyword
and i want it to work like this
example/page/keyword
sorry for my bad english
$keyword = $_GET['s'];
file_get_contents("https://www.googleapis.com/youtube/v3/search?part=snippet&q=$keyword&type=video&key=abcdefg&maxResults=5");
Have a look at $_SERVER[REQUEST_URI]
This will return you the current url. Then process it using simple string or array functions to get the params, like
$current_url = $_SERVER['REQUEST_URI'];
$url_arr = explode("/", $current_url);
Then access the parameters using the array indexes
like $page = $url_arr[0];
Related
I'm trying to setup a page that pulls just a part of the URL but I can't even get it to echo on my page.
Since I code in PHP, I prefer dynamic pages, so my urls usually have "index.php?page=whatever"
I need the "whatever" part only.
Can someone help me. This is what I have so far, but like I said, I can't even get it to echo.
$suburl = substr($_SERVER["HTTP_HOST"],strrpos($_SERVER["REQUEST_URI"],"/")+1);
and to echo it, I have this, of course:
echo "$suburl";
If you need to get the value of the page parameter, simply use the $_GET global variable to access the value.
$page = $_GET['page']; // output => whatever
your url is index.php?page=whatever and you want to get the whatever from it
if the part is after ? ( abc.com/xyz.php?......) , you can use $_GET['name']
for your url index.php?page=whatever
use :
$parameter= $_GET['page']; //( value of $parameter will be whatever )
for your url index.php?page=whatever&no=28
use :
$parameter1= $_GET['page']; //( value of $parameter1 will be whatever )
$parameter2= $_GET['no']; //( value of $parameter2 will be 28 )
please before using the parameters received by $_GET , please sanitize it, or you may find trouble of malicious script /code injection
for url : index.php?page=whatever&no=28
like :
if(preg_match("/^[0-9]*$/", $_GET['no'])) {
$parameter2= $_GET['no'];
}
it will check, if GET parameter no is a digit (contains 0 to 9 numbers only), then only save it in $parameter2 variable.
this is just an example, do your checking and validation as per your requirement.
You can use basic PHP function parse_url for example:
<?php
$url = 'http://site.my/index.php?page=whatever';
$query = parse_url($url, PHP_URL_QUERY);
var_dump(explode('=', $query));
Working code example here: PHPize.online
I've looked at every post on SO that remotely pertains to this and I just can't figure this out. This code is taken directly from another SO post and was marked as the correct working answer:
$query = $_GET;
// replace parameter(s)
$query['d'] = 'new_value';
// rebuild url
$query_result = http_build_query($query);
// new link
Link
Again, taken straight from another post. When I try this code, i change the $_GET to the actual URL that i want to alter. When the code gets to the $query['d'] part, it tells me I get an illegal string offset and the error is the index that's specified. So then I parse the URL, and then do parse_str($query, $output) which in turn allows me to do $output['d'] and THEN I can set a new value to that variable. If I echo it out, it's fine.
But then I get to the http_build_query line, and it tells me that it's expecting an array or object and I can't build the new URL. Here is my code:
$link = parse_url('https://www.google.com/search?source=hp&ei=85GhW6CNHoSqsgXnzoD4Ag&q=coding+tutorial&btnK=Google+Search&oq=coding+tutorial', PHP_URL_QUERY);
parse_str($link, $output);
$output['oq'] = 'new value';
$query_result = http_build_query($link);
echo $query_result;
This code yields that the http_build_query function wants an array or object...i guess i'm not giving it that in some way? What do I need to do to get this to work?
If you want to rebuild the full URL after modifying the query parameters, you could do this:
$url = 'https://www.google.com/search?source=hp&ei=85GhW6CNHoSqsgXnzoD4Ag&q=coding+tutorial&btnK=Google+Search&oq=coding+tutorial';
$link = parse_url($url, PHP_URL_QUERY);
parse_str($link, $output);
$output['oq'] = 'new value';
echo substr($url, 0, strpos($url, '?') + 1) . http_build_query($output);
Output:
https://www.google.com/search?source=hp&ei=85GhW6CNHoSqsgXnzoD4Ag&q=coding+tutorial&btnK=Google+Search&oq=new+value
I'd like to find a clean if possibile (without too much string manipulation preg_*)
I know that to replace a parameter I would do
$_GET['info'] = "newinfo";
and to remove a parameter:
unset($_GET['info']);
so is there something like that that I can use?
of course after I've "unset" or "set" I'm building a new query.
(http_build_query).
At the end I'm trying to make this:
/index.php?foo=bar
to
/index.php?foo=bar&info=newinfo
Just do this:
$get = $_GET;
$get['new'] = 'some value';
function getPath()
{
// Stolen from https://stackoverflow.com/a/8775529/3578036
$request = parse_url($_SERVER['REQUEST_URI']);
$path = $request["path"];
return rtrim(str_replace(basename($_SERVER['SCRIPT_NAME']), '', $path), '/');
}
header("Location: " . getPage() . http_build_query($get));
The above code will create a query string and append it to the current URL and redirect to that location. Obviously, you can change the location that you redirect to by replacing the getPage() function result and putting your own result there, this just demonstrates the premise of the answer.
The docs for http_build_query are a very good place to start.
Effectively, what it will do is convert an associative array into an HTTP query string.
I am trying to set up a small script that can play youtube videos but thats kinda besides the point.
I have $ytlink which equals www.youtube.com/watch?v=3WAOxKOmR90
But I want to make it become www.youtube.com/embed/3WAOxKOmR90
Currently I have tried
$result = str_replace('https://youtube.com/watch?v=', "https://youtube.com/watch?v=", $ytlink);
But this returns it as standard
I have also tried
preg_replace('/https://youtube.com/watch?v=/, '/https://youtube.com/embed/', $ytlink);
but both of these dont work.
Instead of using ugly regexes, I recommend using parse_url() with parse_str(). This allows you to be flexible in the event that you want to change something or if Youtube decides to change their URL slightly.
$url = 'https://www.youtube.com/watch?v=3WAOxKOmR90';
// Parse the URL into parts
$parsed_url = parse_url($url);
// Get the whole query string
$query = $parsed_url['query'];
// Parse the query string into parts
parse_str($query, $params);
// Get the parameter you want
$v = $params['v'];
// Now re-build the URL how you want
echo $parsed_url['scheme'].'://'.$parsed_url['host'].'/embed/'.$v;
// Outputs: https://www.youtube.com/embed/3WAOxKOmR90
This works:
$ytlink = 'www.youtube.com/watch?v=3WAOxKOmR90';
$result = str_replace('watch?v=', 'embed/', $ytlink);
echo $result;
$url = 'www.youtube.com/watch?v=3WAOxKOmR90';
echo preg_replace('/.*?v=(\w+)/i', 'www.youtube.com/embed/$1', $url);
How to put the querystring name in php?
$file_get_html('http://localhost/search/?q=');
And when accessing localhost/?name=example the code looks like this
$file_get_html('http://localhost/search/?q=example');
I do not know how to put $_GET['url'] inside a php :(
The question isn't very clear, but I suspect this is the answer:
file_get_html('http://localhost/search/?q=' . urlencode($_GET['url']));
The ?q=example will let you use something like $example = $_GET['q'],
and $example should equal the value of q in your querystring.
If you have a querystring that looks like this:
?q=example&url=myurl.com
You can access the q and url parameters like this:
$q = $_GET['q']; // which will equal 'example'
$url = $_GET['url']; // which will equal 'myurl.com'
If that is what you are trying to do.
$url = urlencode($_GET['url']);
$contents = file_get_contents("http://localhost/search/?q={$url}");
var_dump($contents);