Submit a Form via a Reveal Modal - php

I am trying to submit a form and open a modal with the forms post data on it.
Modal works fine but the form post is not passed through.
I have tried jquery/ajax but no luck.
<form id="frmTractors" method="post" action='process.php'>
<select id="tractor" name="tractor_number">
<options...>
</select>
<input type="submit" value="Submit" data-reveal-id="myModal" data-reveal-ajax="process.php" />
</form>
<!-- ### MODAL ### -->
<div id="myModal" class="reveal-modal" data-reveal></div>

I am running something similar on a site:
HTML
<input type="hidden" id="processURL" value="process.php">
<select id="tractor" name="tractor_number">
<options...>
</select>
JQUERY
$(function() {
$( "#tractor" ).change(function(){
var url = $('#processURL').val();
var tractor_number = $(this).val();
var postit = $.post( url, {tractor_number:tractor_number});
postit.done(function( data ) {
$('#myModal').foundation('reveal', 'open');
});
});
});
You don't need a form, just a hidden input to hold your process file URL.

Related

Ajax does not work in jquery for redirecting to php page

Problem with ajax, when clicking the Properties button, it does not go to the desired page in any way. I tried to add a link jquery in the head and in the body.
I have two inputs and a button Save.
When the button Save is clicked, the input values are added to tags, and create button Properties. Then when clicked Properties button, ajax should work, but it does not work.
search.php
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.6.1/jquery.min.js"></script>
</head>
<body>
<div>
<input type="search" name='search1' list="doc" id="inp1">
<datalist id='doc'>
<option value="virgil">Virgil</option>
<option value="alistair">Alistair</option>
</datalist>
</div>
<div>
<input type="search" name='search2' list="doc2" id="inp2">
<datalist id='doc2'>
<option value="sherman">Sherman</option>
<option value="dejesus">Dejesus</option>
</datalist>
</div>
<div>
<button name='btn' id='btn'>Save</button>
</div>
<div id='div1'></div>
<div id='div2'></div>
<div id='div3'></div>
<script src="scripts.js"></script>
</body>
</html>
scripts.js
$(function() {
$('#btn').click(function() {
let inp1 = $('#inp1').val(); // the value of the first input
let inp2 = $('#inp2').val(); // the value of the second input
let div1 = $('#div1');
let div2 = $('#div2');
let div3 = $('#div3');
div1.html(inp1)
div2.html(inp2);
if(inp1 && inp2) { // if there are both values create button
let btn = $('<button>Properties</button>');
div3.html(btn);
btn.click(function() {
console.log('hello') // It work's
$.ajax({ // when the button is clicked, it should redirect to another page, but it does not work
url: 'new.php',
method: 'post',
data: inp1, inp2,
action: 'prop'
})
})
}
})
})
Thank you.
You shouldn't use Ajax to redirect pages.
Ajax is more like background threading.
In your situation, you should build a form with js and POST data to new.php via php.

JQuery Ajax post method is not working in laravel

I want to save an image and two text field using JQuery,Ajax. here, i'm using bootstrap modal. But when I submit the modal form it's show MethodNotAllowedHttpException Exception.
My Ajax Method.
$(document).ready(function(){
$('#advisoradd').on('submit',function(){
var name=$('#adname').val();
var title=$('#adtitle').val();
var img=$('#adfile').val();
$.ajax({
url:"{{route('add.advisor')}}",
type:'post',
data:{
'_token':"{{csrf_token()}}",
'name':name,
'title':title,
'img':img,
},
success:function(data)
{
console.log(data);
}
});
});
});
My view Modal code.
<form method="POST" enctype="multipart/form-data">
{{csrf_field()}}
<div class="form-group">
<div class="img_upload_team">
<button class="btn">+</button>
<input type="file" name="myfile" id="adfile">
</div>
<h2>Add A Profile Photo</h2>
<p>Click “+” Sign to Add</p>
</div>
<div class="form-group">
<input type="text" name="adname" class="form-control" id="adname" placeholder="Name">
</div>
<div class="form-group">
<input type="text" name="adtitle" class="form-control" id="adtitle" placeholder="Title">
</div>
<button type="submit" class="btn btn_modal_submit" id="advisoradd">Add</button>
</form>
My controller and Route for this Request.
public function addadvisor(Request $request)
{
$advisor=new Advisor();
$advisor->name=$request->name;
$advisor->title=$request->title;
$file = $request->file('img') ;
$fileName = $file->getClientOriginalName();
$destinationpath=public_path().'/images/';
$file->move($destinationpath,$fileName);
$advisor->image=$fileName;
$advisor->save();
return response()->json($advisor);
}
Route::post('/advisor','ImageController#addadvisor')->name('add.advisor');
You've mixed up button and form events. Buttons don't have a submit event, forms do. Since you're adding the event on the button, change it to click.
We should also add a preventDefault() to stop the button from submitting the form.
(We could also add the type="button" attribute on the button element to stop it from submitting the form).
This should work:
$(document).ready(function() {
// Add a 'click' event instead of an invalid 'submit' event.
$('#advisoradd').on('click', function(e) {
// Prevent the button from submitting the form
e.preventDefault();
// The rest of your code
});
});

when submit jquery form dynamic change action url

I am using jquery ajax form library.... i want to change action url when i submit form
html
<div class="modal-body form"><?php echo form_open_multipart("#",array('id'=>'mng_form', 'name'=>'mng_form','class'=>'form-horizontal','role'=>'form')); ?>
javascript
var options = {replaceTarget:true, beforeSubmit: showRequest, success: showResponse};
how can i change action url using jquery form ?
use jQuery submit(). This happens prior to the actual submission, so you can change the action url.
<form id="fromID" action="action_page01.php" method="post" target="_blank" accept-charset="UTF-8" enctype="application/x-www-form-urlencoded" autocomplete="off" novalidate>
<input type="submit" value="Submit">
</form>
// jQuery
$( "#fromID" ).submit(function( event ) {
$('#fromID').attr('action', 'action_page02.php');
});

Passing variable data between jQuery and PHP using AJAX shorthand

I'm trying to create a search feature that searches a database based on the criteria a user has entered. Right now, I'm just trying to get the jQuery variable data into PHP. I've decided to use the shorthand AJAX $.post method because this is just a demo project. I know there are numerous similar questions like mine, but I have yet to find an answer to any of them that I can use.
So what I'm trying to do is, the user will click on a drop down menu and select an option. AJAX then sends the selected value to the PHP file and the PHP will eventually perform a database search based on what was selected. The issue is, in PHP, I'm getting a string of "Search" when the data is parsed and I echo it but when I do a console log on the variable that was sent, I'm getting the correct text. Can anyone tell me where I'm going wrong?
Here's what I have so far.
AJAX
$("#search_form").on("submit", function(ev){
ev.preventDefault();
$.post("../php/test.php", $(this).serialize(), function(data){
console.log(data);
})
})
PHP
ob_start();
require("../includes/header.php");
$criteria = $_POST["search"];
ob_clean();
echo $criteria;
HTML
<form id="search_form" method="post">
<fieldset id="search_by">
<div class="select" name="searchBy" id="searchBy">
<p>Search By...</p>
<div class="arrow"></div>
<div class="option-menu">
<div class="option">Airport Identifier</div>
<div class="option">Top Rated</div>
<div class="option">Instructor</div>
<div class="option">Malfunctions/Maneuvers</div>
</div>
</div>
<input type="text" name="search" id="search" />
<input type="submit" class="button" value="Search_Now" />
</fieldset>
As Requested
Here is a fiddle of the drop down menu to show how it works.
http://jsfiddle.net/xvmxc0zo/
Your form is being submitted via default form submission; the ajax call is misplaced, it should be within the submit handler, which should prevent default form submission.
Note that I have removed both name and id attributes from the submit button; you do not need them. Just let the submit button do it's job and listen for the submit event on the form where you would then use event.preventDefault(); to make sure the form does not submit, then you can make your ajax call.
$("#searchBy").on("click", ".option", function(){
$('#search').val( $(this).text() );
});
$('form').on('submit', function(e) {
e.preventDefault();
$.post("../php/test.php", $(this).serialize(), function(data){
//jsonData = window.JSON.parse(data);
console.log( data);
})
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<form>
<fieldset id="search_by">
<div class="select" name="searchBy" id="searchBy">
<p>Search By...</p>
<div class="arrow"></div>
<div class="option-menu">
<div class="option">Airport Identifier</div>
<div class="option">Top Rated</div>
<div class="option">Instructor</div>
<div class="option">Malfunctions/Maneuvers</div>
</div>
</div>
<input type="hidden" name="search" id="search" />
<input type="text" name="search_text" id="search_text" />
<input type="submit" class="button" value="Search" />
</fieldset>
</form>
In your PHP use echo $criteria; instead of echo json_encode($criteria);.
I'd suggest to use the way of jQuery documentation to check changes in your drop down.
$( "select" ).change(function () {
$( "select option:selected" ).each(function() {
$.post("../php/test.php", {search: $(this).text()}, function(data){
jsonData = window.JSON.parse(data);
});
});
})
You are getting "Search" on the PHP side because that is the value of your submit button.
You want the post to occur when you click on an option? Try adjusting your selector as follows:
$("#searchBy .option").on("click", function () {
var search = $(this).text().trim();
$.post("../php/test.php", { search: search }, function (data) {
jsonData = window.JSON.parse(data);
})
});
I think your header.php is provoking the error. I created a test file myself with your code and that works perfectly fine:
<?php
if($_POST)
{
ob_start();
//require("../includes/header.php");
$criteria = $_POST["search"];
ob_clean();
echo json_encode($criteria);
exit;
}
?>
<fieldset id="search_by">
<div class="select" name="searchBy" id="searchBy">
<p>Search By...</p>
<div class="arrow"></div>
<div class="option-menu">
<div class="option">Airport Identifier</div>
<div class="option">Top Rated</div>
<div class="option">Instructor</div>
<div class="option">Malfunctions/Maneuvers</div>
</div>
</div>
<input type="text" name="search_text" id="search_text" />
<input type="submit" name="search" id="search" class="button" value="Search" />
</fieldset>
<script src="http://code.jquery.com/jquery-1.11.1.min.js"></script>
<script>
$("#searchBy").on("click", ".option", function(){
var search = $(this).text();
$.post("<?=$_SERVER['PHP_SELF']?>", {search: search}, function(data){
jsonData = window.JSON.parse(data);
console.log(jsonData); //Prints the correct string
})
});
</script>

$_POST for text in DIV elements

Because of my web style, i don't want to use input & textarea and get information by using $_POST[] and i need to get information that is in DIV element.
For example , I want to get information in this :
<div class="mine" name"myname">
this is information that i want to get and put into database by PHP !
</div>
and :
$_POST[myname];
But i can't do it with $_POST , How can i do it ??
And if this method can't do this , do you know any other method to get information from DIV like this ?
you can call a onsubmit function and make a hidden field at the time of form submission like this
HTML
need to give a id to your form id="my_form"
<form action="submit.php" method="post" id="my_form">
<div class="mine" name"myname">
this is information that i want to get and put into database by PHP !
</div>
<input type="submit" value="submit" name="submit" />
</form>
Jquery call on submit the form
$(document).ready(function(){
$("#my_form").on("submit", function () {
var hvalue = $('.mine').text();
$(this).append("<input type='hidden' name='myname' value=' " + hvalue + " '/>");
});
});
PHP : submit.php
echo $_POST['myname'];
You can use this method. First, with javascript get content of <div>
Code:
<script type="text/javascript">
var MyDiv1 = Document.getElementById('DIV1');
</script>
<body>
<div id="DIV1">
//Some content goes here.
</div>
</body>
And with ajax send this var to page with get or post method.
You would need some JavaScript to make that work, e.g. using jQuery:
$.post('http://example.org/script.php', {
myname: $('.mine').text()
});
It submits text found inside your <div> to a script of your choosing.
You can use following structure;
JS:
$(document).ready(function() {
$("#send").on("click", function() {
$.ajax({
url: "your_url",
method: "POST",
data: "myname=" + $(".mine").text(),
success: function(response) {
//handle response
}
})
})
})
HTML:
<div class="mine" name"myname">
this is information that i want to get and put into database by PHP !
</div>
<input type="button" name="send" id="send" value="Send"/>
You can see a simulation here: http://jsfiddle.net/cubuzoa/2scaJ/
Do this in jquery
$('.mine').text();
and post data using ajax.
Put the content of DIV in a variable like below:
var x = document.getElementById('idname').innerHTML;

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