So, I have the following php:
<?php echo get_post_meta($post->ID,'dfd_ModificationTimestamp',true); ?>
It outputs dates as the following: 13/06/2015 11:02:18
I am not sure how to change it to "3 days ago" or "2 month ago" etc.
Any suggestions?
Thanks!
I think you are looking for the wordpress function human_time_diff
Example:
//Get your date
$date = get_post_meta($post->ID,'dfd_ModificationTimestamp',true);
//Convert it to a unix time stamp
$timestamp = strtotime($date);
//Print a nice string showing how long ago that was
echo human_time_diff( $timestamp, current_time('timestamp') ) . ' ago';
Use this:
$dateString = get_post_meta($post->ID,'dfd_ModificationTimestamp',true);
/* #var \DateTime $date */
$date = DateTime::createFromFormat('d/m/Y H:i:s', $dateString);
Now $date is DateTime object. You can modify it as you wish.
For example, you need 3 days ago from your date value(13/06/2015 11:02:18)
$date->modify('-3 days'); // $date becomes 10/06/2015 11:02:18
or if you need 2 months ago from your date value(13/06/2015 11:02:18)
$date->modify('-2 months'); // $date becomes 13/04/2015 11:02:18
To print $date value after modify, use:
echo $date->format('d/m/Y H:i:s');
See http://php.net/manual/en/class.datetime.php for more custom information.
I know you tagged this PHP but you can do this with javascript using the timeago plugin.
<abbr class="timeago" title="2008-07-17T09:24:17Z">July 17, 2008</abbr>
is converted into
<abbr class="timeago" title="July 17, 2008">7 years ago</abbr>
You need to format the time in ISO_8601 format too, something like this would do it:
echo (new DateTime('17 Oct 2008'))->format('c');
Sources:
http://timeago.yarp.com/
How to display a date as iso 8601 format with PHP
Related
I have a timestamp stored in a session (1299446702).
How can I convert that to a readable date/time in PHP? I have tried srttotime, etc. to no avail.
Use PHP's date() function.
Example:
echo date('m/d/Y', 1299446702);
strtotime makes a date string into a timestamp. You want to do the opposite, which is date. The typical mysql date format is date('Y-m-d H:i:s'); Check the manual page for what other letters represent.
If you have a timestamp that you want to use (apparently you do), it is the second argument of date().
I just added H:i:s to Rocket's answer to get the time along with the date.
echo date('m/d/Y H:i:s', 1299446702);
Output: 03/06/2011 16:25:02
$timestamp = 1465298940;
$datetimeFormat = 'Y-m-d H:i:s';
$date = new \DateTime();
// If you must have use time zones
// $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki'));
$date->setTimestamp($timestamp);
echo $date->format($datetimeFormat);
result: 2016-06-07 14:29:00
Other time zones:
Africa
America
Antarctica
Arctic
Asia
Atlantic
Australia
Europe
Indian
Pacific
Others
If you are using PHP date(), you can use this code to get the date, time, second, etc.
$time = time(); // you have 1299446702 in time
$year = $time/31556926 % 12; // to get year
$week = $time / 604800 % 52; // to get weeks
$hour = $time / 3600 % 24; // to get hours
$minute = $time / 60 % 60; // to get minutes
$second = $time % 60; // to get seconds
If anyone wants timestamp conversion directly to a DateTime object, there's a simple one-liner:
$timestamp = 1299446702;
$date = DateTime::createFromFormat('U', $timestamp);
Following #sromero comment, timezone parameter (the 3rd param in DateTime::createFromFormat()) is ignored when unix timestamp is passed, so the below code is unnecessary.
$date = DateTime::createFromFormat('U', $timestamp, new DateTimeZone('UTC'); // not needed, 3rd parameter is ignored
You may check PHP's manual for DateTime::createFromFormat for more info and options.
Try this one:
echo date('m/d/Y H:i:s', 1541843467);
$epoch = 1483228800;
$dt = new DateTime("#$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s'); // output = 2017-01-01 00:00:00
In the examples above "r" and "Y-m-d H:i:s" are PHP date formats, other examples:
Format Output
r ----- Wed, 15 Mar 2017 12:00:00 +0100 (RFC 2822 date)
c ----- 2017-03-15T12:00:00+01:00 (ISO 8601 date)
M/d/Y ----- Mar/15/2017
d-m-Y ----- 15-03-2017
Y-m-d H:i:s ----- 2017-03-15 12:00:00
Try it.
<?php
$timestamp=1333342365;
echo gmdate("Y-m-d\TH:i:s\Z", $timestamp);
?>
You can try this:
$mytimestamp = 1465298940;
echo gmdate("m-d-Y", $mytimestamp);
Output :
06-07-2016
Unless you need a custom date and time format, it's easier, less error-prone, and more readable to use one of the built-in date time format constants:
echo date(DATE_RFC822, 1368496604);
echo date("l M j, Y",$res1['timep']);
This is really good for converting a unix timestamp to a readable date along with day. Example:
Thursday Jul 7, 2016
echo 'Le '.date('d/m/Y', 1234567890).' à '.date('H:i:s', 1234567890);
I have used this:
<?php echo date('d/m/Y H:i a', $row['start_time']); ?>
I can add x week to my date
//$ultima_azione <--- 2015/07/15
//$data['intervallo'] <---- 5
$mydate = date("Y-m-d",strtotime($ultima_azione." +".$data['intervallo']." weeks"));
now how can i give a day starting from that week
example:
//$mydate + "next Monday" -----> final date
and this ve to work like, if today is Monday and i add weeks to jump to an other Monday and then i select the next Monday the week don't ve to change
The simplest way would be to use strtotime. It can do date calculations based on a textual representation of the delta:
$mydate = strtotime('+3 weeks');
It also accepts a second parameter, which is a timestamp to start from when doing the calculation, so after you get the offset in weeks, you can pass the new date to a second calculation:
// Get three weeks from 'now' (no explicit time given)
$mydate = strtotime('+3 weeks');
// Get the Monday after that.
$mydate = strtotime('next Monday', $mydate);
See strtotime documentation for more examples of notations that you can use.
I would highly recommend using PHP's built-in DateTime class for any date and time logic. It's a much better API than the older date and time functions and creates much cleaner and easier to read code.
For example:
// Current date and number of weeks to add
$date = '2015/07/15';
$weeks = 3;
// Create and modify the date.
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('next monday');
// Output the new date.
echo $dateTime->format('Y-m-d');
References:
DateTime.
DateTime::createFromFormat
DateTime::add
DateTime::modify
DateInterval::createFromDateString
DateTime::format
Are you looking for something like this?
$today = time();
$weeks = 2;
// timestamp 2 weeks from now
$futureWeeks = strtotime("+ ".$weeks." weeks");
// the next monday after the timestamp date
$futureMonday = strtotime("next monday",$futureWeeks);
echo date("Y-m-d", $futureMonday);
// or in one line
echo date("Y-m-d", strtotime("next monday", strtotime("+ ".$weeks." weeks")));
PHP is using an unix timestamp for date calculations. Functions as date() and strtotime() using a timestamp as an optional second parameter. This is used a reference for formatting and calculations. If no timestamp is passed to the function the current timestamp is used (time()).
I have the answer here. This will show the next wednesday every 2 weeks and the first date to start from would be the 10th.
I have also added in an estimated delivery which would be 6 weeks after that date.
We will be placing our next order for this on:
<?php
$date = '2020/05/26';
$weeks = 2;
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('wednesday');
echo $dateTime->format('d/m/Y');
?>
Expected delivery for the next order will be:
<?php
$date = '2020/05/26';
$weeks = 2;
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('+42 days next wednesday');
echo $dateTime->format('d/m/Y');
?>
If anyone can confirm this is correct that would be great.
I just hope this question won't be marked as a duplicate because I've seen similar questions on stackoverflow but they all talk about adding days to the date, The problem here is that i want to add some particular months to a particular date which is gotten from my database I've tried adding it using strtotime() but the date just returns 1st January 1970, the code looks like this
<?php echo date('jS F Y', strtotime("$date +1 month")); ?>
//This is the value of date
$date = $student->date;
How to I add months to this particular date? Please note that the date is a timestamp in my database.Thanks
You have a Unix timestamp, not an actual date. Here I use the DateTime class to create a datetime object using that Unix timestamp. Then I can add a month to it and format the output.
$date = new DateTime('#'.$student->date);
$date->modify('+1 month');
echo $date-format('jS F Y');
If you want to stick to using date() and strtotime() you would use this:
echo date("jS F Y", strtotime("+1 month", $student->date));
strtotime() would take the starting date as the second parameter and then how you wish to modify it as your first parameter.
You should check out the documentation here,
But the just of it is the $date->add function. It allows you to add any amount of time to a timestamp using a DateInterval. Its a little tricky to get used to but here are a couple of examples:
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "\n";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "\n";
?>
which outputs:
2000-01-01 10:00:30
2007-06-05 04:03:02
The date interval is formatted in years months days hours minuets seconds, simply put in the amount you want and it will add it, so in your case:
<?php
$date->add(new DateInterval('P1M'));
echo $date->format('Y-m-d H:i:s') . "\n";
?>
PHP's strtotime() function allows for a second parameter that allows you to set a relative date.
If you would like to add a month to tomorrow, here's how:
<?php
echo date("jS F Y", strtotime("+1 month", strtotime("2014-10-09")));
// returns: 9th November 2014
Im trying to add a certain amount of days to a timestmp using this in PHP:
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate);
$endDate2 = strtotime('+1 day',$endDate);
echo $endDate2;
but its displaying: 1216526400
any ideas?
Try:
echo date("Y-m-d H:i:s",$endDate2);
Or (for just the date):
echo date("Y-m-d",$endDate2);
You can find documentation about how to format your string here: http://php.net/manual/en/function.date.php
You should be using DateTime for working with dates. It's timezone friendly.
$datetime = new DateTime('2008-06-20');
$datetime->modify('+1 day');
echo $datetime->getTimestamp();
strtotime() converts the date into a unix timestamp which is the number of seconds since January 1st 1970. If you want a date output you have to run the finished timestamp through date() first.
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate.' +1 day');
echo date("Y-m-d", $endDate);
strtotime creates a Unix timestamp so if you want to be presented with a formatted date, you need to pass the timestamp as an argument to the date function as follows:
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate);
$endDate2 = strtotime('+1 day',$endDate);
echo date('Y-m-d', $endDate2);
Additionally, there are a wide variety of parameters you can use in the date function if you want to display additional information.
e.g.: echo date('Y-m-d H:i:s', $endDate2); or echo date('Y-m-d h:i:s a', $endDate2);, etc.
Sooooo close, just take your timestamp and convert it back into date format using date("desired format",$endDate2);
DateTime is a very nice way to deal with dates. You can try like this:
$capturedDate = '2008-06-20';
$date = DateTime::createFromFormat('Y-m-d', $capturedDate)->modify('+1 day');
echo $date->getTimestamp();
I have a timestamp stored in a session (1299446702).
How can I convert that to a readable date/time in PHP? I have tried srttotime, etc. to no avail.
Use PHP's date() function.
Example:
echo date('m/d/Y', 1299446702);
strtotime makes a date string into a timestamp. You want to do the opposite, which is date. The typical mysql date format is date('Y-m-d H:i:s'); Check the manual page for what other letters represent.
If you have a timestamp that you want to use (apparently you do), it is the second argument of date().
I just added H:i:s to Rocket's answer to get the time along with the date.
echo date('m/d/Y H:i:s', 1299446702);
Output: 03/06/2011 16:25:02
$timestamp = 1465298940;
$datetimeFormat = 'Y-m-d H:i:s';
$date = new \DateTime();
// If you must have use time zones
// $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki'));
$date->setTimestamp($timestamp);
echo $date->format($datetimeFormat);
result: 2016-06-07 14:29:00
Other time zones:
Africa
America
Antarctica
Arctic
Asia
Atlantic
Australia
Europe
Indian
Pacific
Others
If you are using PHP date(), you can use this code to get the date, time, second, etc.
$time = time(); // you have 1299446702 in time
$year = $time/31556926 % 12; // to get year
$week = $time / 604800 % 52; // to get weeks
$hour = $time / 3600 % 24; // to get hours
$minute = $time / 60 % 60; // to get minutes
$second = $time % 60; // to get seconds
If anyone wants timestamp conversion directly to a DateTime object, there's a simple one-liner:
$timestamp = 1299446702;
$date = DateTime::createFromFormat('U', $timestamp);
Following #sromero comment, timezone parameter (the 3rd param in DateTime::createFromFormat()) is ignored when unix timestamp is passed, so the below code is unnecessary.
$date = DateTime::createFromFormat('U', $timestamp, new DateTimeZone('UTC'); // not needed, 3rd parameter is ignored
You may check PHP's manual for DateTime::createFromFormat for more info and options.
Try this one:
echo date('m/d/Y H:i:s', 1541843467);
$epoch = 1483228800;
$dt = new DateTime("#$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s'); // output = 2017-01-01 00:00:00
In the examples above "r" and "Y-m-d H:i:s" are PHP date formats, other examples:
Format Output
r ----- Wed, 15 Mar 2017 12:00:00 +0100 (RFC 2822 date)
c ----- 2017-03-15T12:00:00+01:00 (ISO 8601 date)
M/d/Y ----- Mar/15/2017
d-m-Y ----- 15-03-2017
Y-m-d H:i:s ----- 2017-03-15 12:00:00
Try it.
<?php
$timestamp=1333342365;
echo gmdate("Y-m-d\TH:i:s\Z", $timestamp);
?>
You can try this:
$mytimestamp = 1465298940;
echo gmdate("m-d-Y", $mytimestamp);
Output :
06-07-2016
Unless you need a custom date and time format, it's easier, less error-prone, and more readable to use one of the built-in date time format constants:
echo date(DATE_RFC822, 1368496604);
echo date("l M j, Y",$res1['timep']);
This is really good for converting a unix timestamp to a readable date along with day. Example:
Thursday Jul 7, 2016
echo 'Le '.date('d/m/Y', 1234567890).' à '.date('H:i:s', 1234567890);
I have used this:
<?php echo date('d/m/Y H:i a', $row['start_time']); ?>