Hide a <li tab if a condition is met [duplicate] - php

Question

This question already has answers here:
Hiding a Div using php
(6 answers)
Closed 1 year ago.
I have a foreach look that checks if user has a picture or not. If the user doesn't have the picture I want to hide a <li> tab that shows the picture.
Inside my else how do I say, for this user hide tab 2?
I tried using echo 'id="tabHeader_2" style:"visibility:hidden"; but that doesn't work. I need a reference to that tab2, don't I?
<div id="picture<?php echo $i ?>" style="display: none;">
<?php
$picture = $user->pic;
if(isset($picture))
{
// show picture.
}
else
{
// hide tab2
}
?>
</div>
Then the list of tabs:
<div class="profiles">
<div id="tabContainer">
<div class="tabs">
<ul>
<li id="tabHeader_1"> Profile </li>
<li id="tabHeader_2"> Picture </li>
</ul>
</div>
<div id="tabsContent">
<div class="tabpage" id="tabpage_1"></div>
<div class="tabpage" id="tabpage_2"></div>
</div>
<script src="<?php echo Yii::app()->theme->baseUrl; ?>/js/tabs.js"></script>
</div>
</div>
Picture of what the page looks like:

Answer 1

I am not 100% sure about your code, but you are using isset() which would not be correct, because you set the variable right behind that check so it will be set 100% of the time. You will want to check empty() or is_file() perhaps, depends on what is in that variable.
<!-- This display: none seems strange if you are going to show the wrapped elements -->
<div id="picture<?php echo $i ?>" style="display: none;">
<?php
$picture = $user->pic;
if(!empty($picture)) {
// show picture.
}
else {
// hide tab2
}
?>
</div>
If you put the real code, it would be easier to see how you are laying out your elements.

Answer 2

Do Like This :-
<div class="tabs">
<ul>
<?php
$i = 1;
foreach($yourarray as $key => $value){
if(isset($value) && $value != '')
?>
<li id="tabProfileHeader<?php echo $i;?>"> Profile </li>
<li id="tabPictureHeader<?php echo $i;?>"> Picture </li>
<?php
$i++;
}
?>
</ul>
</div>