Put the value of for loop inside array - php

I am trying to reate an array that contains all the odd numbers between 1 to 20,000. I Use the var_dump() at the end to display the array values without using loops.
For some reason it won't work out.
here's my code so far:
$array_variable = array();
for($i=1; $i<=20000; $i++){
if($i%2 == 1){ // if the remainder after division `$i` by 2 is one{
print_r($array_variable[$i]); // if odd, echo it out and then echo newline for better readability;
}
}
var_dump($array_variable);

You need to push the values to your array first:
$array_variable = array();
for($i=1; $i<=20000; $i++){
if($i%2 == 1){
$array_variable[] = $i;// or array_push($array_variable, $i);
}
}
var_dump($array_variable);
Otherwise your array stays empty.

This results in alot of undefined indexes because you're not adding anything to $array_variable.
Change the code to this:
$array_variable = array();
for($i=1; $i<=20000; $i++){
if($i%2 == 1){ // if the remainder after division `$i` by 2 is one{
$array_variable[] = $i; // $array_variable[] means adding something to the array
}
}
var_dump($array_variable); //dump all odd numbers
For better readability of the array you could use:
echo "<pre>";
print_r($array_variable);
echo "</pre>";

Your $array_variable is empty because you never add any elements to it. Try this instead:
$array_variable = range(1, 20000, 2);

$array_variable = array();
for($i=1; $i<=20000; $i++){
if($i%2 == 1){ // if the remainder after division `$i` by 2 is one{
array_push($array_variable, $i); //Push the variable into array
}
}
var_dump($array_variable); //dump all odd numbers

You are trying to print an element it does not exist since the array is empty.
If you insist on using an array use this code, you notice you assign a value to the array elements: ( and also if you want to display it on a new line in browser, use echo commented out): (if interested about more: what is the difference between echo and print_r
<?php
$array_variable = array();
for($i=1; $i<=20000; $i++){
$array_variable[$i]=$i;//assignment
if($i%2 == 1){ // if the remainder after division `$i` by 2 is one{
print_r($array_variable[$i]); // if odd, echo it out and then echo newline for better readability;
//echo $array_variable[$i].'<br>';
}
}
var_dump($array_variable);
?>

Related

Php array display array element 4 per line [duplicate]

This question already has answers here:
Selecting multiple array elements
(3 answers)
Closed 1 year ago.
Hey GUys Im beginner to php programming here here i have 15 element in array . i want to display first 4 array element in first line and then second 4 array of element in nextline . i dont know how to achive it here is my code help me on this. thanks in advance
<?php
$arry=array('a','b','c','d','e','f','g','h','i','j','k','l','m','n','o');
echo $nr_elm = count($arry); // gets number of elements in $arry
$nr_col = 4; // Sets the number of text Per Line
// If the array has elements
if ($nr_elm > 0)
{
// Traverse the array with FOR
for($i=0; $i<$nr_elm; $i++)
{
echo $textInLine= $arry[$i]. ' | ';
// If the number of columns is completed for a line (rest of division of ($i + 1) to $nr_col is 0)
// Closes the current line, and begins another line
$col_to_add = ($i+1) % $nr_col;
if($col_to_add == 0) { $textInLine .= '/n'; }
}
}
echo $textInLine;
?>
Use array_chunk for this:
$array = array('a','b','c','d','e','f','g','h','i','j','k','l','m','n','o');
$size = 4;
foreach (array_chunk($array, $size) as $chunk) {
echo implode(' ', $chunk) . PHP_EOL;
}
Another solution without using array_chunk is using modulo:
$array = array('a','b','c','d','e','f','g','h','i','j','k','l','m','n','o');
$size = 4;
$counter = 0;
foreach ($array as $character) {
echo $character;
// echo new line after every 4th character, a space after the others
echo (++$counter % $size === 0) ? PHP_EOL : ' ';
}
Chunk the array and implode the items in the chunk.
$arry=array('a','b','c','d','e','f','g','h','i','j','k','l','m','n','o');
$chunks = array_chunk($array, 4);
foreach($chunks as $chunk){
echo implode(" ", $chunk) . "</br>\n";
}
Array_chunk splits the array in to pieces of the size you define.
The resulting array is multidimensional with the items in the subarray.
Implode takes the items in the subarray and adds the delimiter (" ") in between each item and makes it a string.
Use array_chunk, it will Split an array into chunks
<?php
$arry=array('a','b','c','d','e','f','g','h','i','j','k','l','m','n','o');
$arr = array_chunk($arry, 4, true);
foreach($arr as $value) {
echo implode(' ', $value) . PHP_EOL ;
}
?>
I don't know if the "15" is intentional, but if you want to remove it just remove the "echo".
I also recommend to use empty() to verify if your array is empty or not, just like this :
if (!empty($arry)) { //Code }
(notice the "!")
Now, for your main question what I would do is using a variable which increments up to 4, then you insert a line break with echo <br>; and reset the variable to 0.
The code should look something like this :
$c = 0;
for($i=0; $i<$nr_elm; $i++)
{
echo $arry[$i];
$c ++;
if ($c >= 4) {
echo "<br>";
$c = 0;
}
}
I hope this helped you

PHP replace every 2nd

<?php
$fact_BB = array("[start]", "[mid]", "[end]");
$fact_HTML = array("<tr><td class='FactsTableTDOne'><p>", "</p></td><td class='FactsTableTDTwo'><p>", "</p></td></tr>");
$str_Facts = str_replace($fact_BB, $fact_HTML, $row['facts']);
echo $str_Facts;
?>
Is it possible to switch between 2 $fact_HTML?
1. $fact_HTMLone = "code";
2. $fact_HTMLtwo = "code";
3. $fact_HTMLone = "code";
4. $fact_HTMLtwo = "code";
5. $fact_HTMLone = "code";
etc. etc.
Sure. With $fact_HTML[0], $fact_HTML[1], $fact_HTML[n] etc. you can access your $fact_HTML array. Using modulo of 2 you can always access every 2nd (or first and second) elements of the array.
To check if the element is even or odd you can use:
if ($n % 2 == 0) {
//even element
} else {
//odd element
}
Also you can use Modulo 2 ($n % 2) as n to iterate through the array in the same way. You can also combine both variants.
$count = 10; //number of facts
for ($n = 0; $n < $count; $n++) {
$fact_HTML[$n % 2] = $fact;
}
What you want to achieve is a replace of some strings. I'd suggest a solution like this:
<?php
$str_Facts = $row['facts'];
$replacements = array( "[start]" => "<tr><td class='FactsTableTDOne'><p>",
"[mid]" => "</p></td><td class='FactsTableTDTwo'><p>",
"[end]" => "</p></td></tr>" );
foreach ($replacements as $repkey => $repval) {
$str_Facts = str_replace($repkey,$repval,$str_Facts);
}
echo $str_Facts;
?>
If you want to go on with your approach, you'd loop through the arrays (you have to ensure that the both arrays have the same number of elements).
<?php
$str_Facts = $row['facts'];
for ($i=0;$i<count($fact_BB);$i++) {
//if you want to switch every uneven, do this:
if ($i%2!=0) continue;
$str_Facts = str_replace($fact_BB[$i],$fact_HTML[$i],$str_Facts);
}
echo $str_Facts;
?>

Issue with getting data when traversing through an array PHP with a variable

I asked a similar question earlier but I couldn't get a clear answer to my issue. I have a function "isParent" that gets 2 pieces of data. Each 1 of the 2 gets a string separating each value with a , or it just gets a plain int and then checks if the first value given is a parent of the second.
I pull the 2 bits of data in and explode them but when I go through my nested for loop and try to test
$toss = $arr1[$i];
print_r($toss);
It comes up blank. I have no idea what the issue is: Here is the full code of the function...
function isParent($parent, $child)
{
$parentArr = explode(',', $parent);
$childArr = explode(',',$child);
//Explode by Comma here. If array length of EITHER parentArr or childArr > 1 Then throw to an Else
if(count($parentArr) <= 1 && count($childArr) <= 1) //If explode of either is > 1 then ELSE
{
$loop = get_highest_slot(15);
for($i = $loop; $i > 0; $i--)
{
$temp = get_membership_from_slot($i,'id_parent','id_child');
if($temp['id_parent'] == $parent && $temp['id_child'] == $child)
{
return 1;
}
}
}
else //set up a for loop in here so that you traverse each parentArr value and for each iteration check all child values
{
$i = count($parentArr);
$c = count($childArr);
for(;$i >=0;$i--) //Loop through every parent
{
for(;$c >=0;$c--)
{
echo '<br>$i = ';
print_r($i);
echo '<br><br>Parent Arr at $i:';
$toss = $parentArr[$i];
echo $toss;
echo '<br>';
print_r($childArr);
echo '<br><br>';
if(isParent($parentArr[$i],$childArr[$c])) //THIS CAUSES AN INFINITE YES! Learn how to pull an array from slot
{
return 1;
}
}
}
}
return 0;
}
You are missing some code for the slot procedures. Apart from that, you probably need to use a different variable for the inner for loop. because $c will be 0 after the first iteration of $i.
Thanks for the help! The issue was in the recursive call back to the top of the function. It was tossed empty slots and when comparing 2 empty slots it returned a false positive. A quick !empty() check fixed it.

How to get rendomise value with condition with PHP?

I have an array of about 100 different random number like this:
$numbers=array(10,9,5,12, ..... .... ... ...);
now i want to make an array of random numbers from this array so that addition of selected numbers will be my given number. example: i may ask to get array of numbers such that, if i add all numbers it will be 100.
i am trying to do it in this way,
function rendom_num ($array,$addition)
{
//here is the code
}
print_r (rendome_num ($numbers,100));
i am not able to fiend the code for last 3 days!
Please use shuffle-
<?php
$numbers = range(1, 20);
shuffle($numbers);
foreach ($numbers as $number) {
echo "$number ";
}
?>
php.net
can use shuffle as #chatfun said or can try array_rand if want only some random values from your array
$value= array("Rabin","Reid","Cris","KVJ","John");
$rand_keys=array_rand($value,2);
echo "First random element = ".$value[$rand_keys[0]];
echo "<br>Second random element = ".$value[$rand_keys[1]];
Something like this should work. The breakdown is commented so you know what it's all doing.
function Randomizer($number = 100)
{
// This just generates a 100 number array from 1 to 100
for($i=1; $i <= 100; $i++) {
$array[] = $i;
}
// Shuffles the above array (you may already have this array made so you would need to input into this function)
shuffle($array);
// Assign 0 as base sum
$sum = 0;
// Go through the array and add up values
foreach($array as $value) {
// If the sum is not the input value and is also less, continue
if($sum !== $number && $sum < $number) {
// Check that the sum and value are not greater than the input
if(($sum + $value) <= $number) {
// If not, then add
$sum += $value;
$new[] = $value;
}
}
// Return the array when value hit
else
return $new;
}
// If the loop goes through to the end without a successful addition
// Try it all again until it does.
if($sum !== $number)
return Randomizer($number);
}
// Initialize function
$test = Randomizer(100);
echo '<pre>';
// Total (for testing)
echo array_sum($test);
// Array of random values
print_r($test);
echo '</pre>';

PHP multidimensional array

I have an array declared above the beginning of a for loop as: $array = array();.
Now, in the for loop I start inserting values into it.
At some point I make one of its index as another array as $array[$j]=array();
And insert some values like, $array[$j][$l] = id; and so on.
Now, when I use print_r ($array); inside the loop I get the expected value of the array.
But outside the loop this newly created array (2-D) is getting lost and I am getting only a 1-D array as an output.
Can someone please tell me where the problem could lie?
The following code works properly. Perhaps you are switching your variables as strager suggests.
<?php
$array = array();
for ($i = 0; $i < 10; $i+=1) {
if ($i == 5) {
$array[$i] = array('value 1', 'value 2');
} else {
$array[$i] = $i;
}
}
print_r($array);
?>

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