My php has connected to my database however when I try to insert the data, I get the query is not okay response.
if(isset($_POST['Register'])) {
session_start();
$FName = $_POST['First_Name'];
$LName = $_POST['Last_Name'];
$Email = $_POST['Email'];
$PW = $_POST['Password'];
$query = "INSERT INTO user (Fname, Lname, Email, Password) VALUES('{$FName}', '{$LName}', '{$Email}', '{$PW}')";
$result=mysqli_query($con, $query);
if($result){
echo "Query is successfully executed";
}else{
echo "Query is not ok";
}
}
?>
This is my connection code but it tells me that I am successfully connected.
$con = mysqli_connect("localhost", "*******","*******");
mysqli_select_db('batman',$con);
if ($con->connect_error) {
die("Connection failed: " . $con->connect_error);
}
echo "Connected successfully";
?>
The database matches all of the inputs and the table name is user so I cannot figure out why it will not insert into the database.
Use error_reporting(E_ALL); at startup
&
use simple $Fname instead {$Fname}
Also check input type="submit" and name=" is name Register"
Maybe you could try to make a class with the script, because I think the problem is the connection that you use , because you are not calling for the connection function when you execute the query.
Regards!
Related
If I want to add content to the table using "INSERT INTO", I don't get an error message and the table is not filled. I'm new with PHP. explanations would be nice. The database runs on XAMPP.
I don't know what to try. I've already used another table, but it doesn't work. The user should have full access to the table. The names also match.
<?php
$username = $_POST["username"];
$passwort = $_POST["passwort"];
$mail = $_POST["mail"];
$passwort2 = $_POST["passwort2"];
$pass = sha1($passwort);
$db = mysqli_connect("localhost", "phptest1", "o84XM5wxo65QBjkF", "phptest1");
if($passwort == $passwort2) {
echo "Password is correct.";
$db = "INSERT INTO user (Username, Mail, Password) VALUES ('$username', '$mail', '$pass')";
} else if(!($passwort == $passwot2)) {
echo "Password is not correct";
} ?>
The variable $db actually contains information about the connection. You cannot insert a query into your database the way you are trying to
You can use $db (in your case) in order to check whether the connection has been correctly established or not and then if everything works correctly you can user mysqli_query() to inject the query into your database.
You can do it like so:
<?php
if(isset($_POST['submit'])){ //You have to check if your submit button is pressed
$username = $_POST["username"];
$passwort = $_POST["passwort"];
$mail = $_POST["mail"];
$passwort2 = $_POST["passwort2"];
$pass = sha1($passwort);
$db = mysqli_connect("localhost", "phptest1", "o84XM5wxo65QBjkF", "phptest1");
if(!$db){
die('Connection could not be established! Check provided information');
}
if($passwort == $passwort2) {
echo "Password is correct.Inserting query now";
$query = "INSERT INTO user (Username, Mail, Password) VALUES ('$username', '$mail', '$pass')";
$result = mysqli_query($db, $query); //keep $result for debugging purposes.
} else {
die("Password is not correct");
} //no need for else if as there are only 2 conditions.
if(!$result){ //check if query was successful.
die('Query Error');
}
echo "Query Updated successfully";
}
?>
This code is really simplistic and for testing purposes only.
I just wanted to show you the way you can send queries to your database. You better use other encryption techniques i.e. crypt() and of course functions like mysqli_real_escape_string() when retrieving data from users, in order to avoid potential injection attacks.
Check this post for more info about preventing injections.
Hope that helps.
i am getting error no database is selected can anybody correct the code.
I am trying to learn php and mysql. So i tried making a database using
phpmyadmin and connect it with my php. Here is a simple example where I try to see if the database is working.
<?php
//Get values passe from form in donateform.html.
$link;
$Name = $_POST['Name'];
$Mobile = $_POST['Mobile'];
$Email = $_POST['Email'];
$Donating =isset($_POST['Donating']);
$Address = isset($_POST['Address']);
//To prevent mysql injection
$Name = stripcslashes($Name);
$Mobile = stripcslashes($Mobile);
$Email = stripcslashes($Email);
$Donating = stripcslashes($Donating);
$Address = stripcslashes($Address);
//connect to the server and select database.
$link=mysqli_connect("localhost", "gooddeeds", "");
mysqli_select_db($link,"donaters");
$Name = mysqli_real_escape_string($link,$Name);
$Mobile = mysqli_real_escape_string($link,$Mobile);
$Email = mysqli_real_escape_string($link,$Email);
$Donating = mysqli_real_escape_string($link,$Donating);
$Address = mysqli_real_escape_string($link,$Address);
//Query the database for user
$result =mysqli_query($link,"INSERT INTO donaters (Name, Mobile, Email, Donating, Address) VALUES ('$Name', '$Mobile', '$Email', '$Donating', '$Address')")
or die("Failed to query daabase".mysqli_error($link));
if(mysqli_query($result)){
echo "Records inserted successfully.";
} else{
echo "ERROR: Could not able to execute $sql. ".mysqli_error($link);
}
?>
and i get
Database query failed::: No database selected
which means this part of code
//connect to the server and select database.
$link=mysqli_connect("localhost", "gooddeeds", "");
mysqli_select_db($link,"donaters");
is not working (i put a different number of these ":" in each if. Any help would be appreciated! Thank you!
You can try with following as databasename.tablename (gooddeeds.donaters)
INSERT INTO gooddeeds.donaters (Name, Mobile, Email, Donating, Address) VALUES ('$Name', '$Mobile', '$Email', '$Donating', '$Address')
This is by the first example in the php documentation. Try the the conditional to check connection.
$link = mysqli_connect("127.0.0.1", "my_user", "my_password", "my_db");
if (!$link) {
echo "Error: Unable to connect to MySQL." . PHP_EOL;
echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
exit;
}
I have this code and I am using the latest version of XAMPP:
filename: store.html
<!DOCTYPE html>
<html>
<body>
<form action="store.php" method="post">
User input: <input type="text" name="userinput"><br>
<input type="submit">
</form>
</body>
</html>
filename: store.php
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "database";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
$input = $_POST["userinput"];
$sql = "INSERT INTO table_1 (s_num)
VALUES ('$input')";
?>
Whatever I do, no data is added to the database. Please help. Thank you.
The problem here is that you never executed the query.
$sql = mysqli_query($conn,"INSERT INTO table_1 (s_num)
VALUES ('$input')");
if(!sql){
echo "Error: " . mysqli_error($conn);
}
else{
echo "Success";
}
Reference:
http://php.net/manual/en/mysqli.query.php
Your present code is open to SQL injection if user-input (other than yourself) ever gets involved.
Use prepared statements, or PDO with prepared statements, they're much safer.
Plus, seeing you are running this from your own machine, make sure you are accessing as http://localhost/file.php as opposed to file:///file.php.
You are not executing your sql insertcode.
After this line:
$sql = "INSERT INTO table_1 (s_num)
VALUES ('$input')";
Add these line:
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
newbie here! I have made a simple form on my site
warning message
I can't seem to figure out what i've done wrong.
This is the php code:
<?php
$servername = "localhost";
$dbusername = "charityh_root";
$dbpassword = "";
$dbname = "charitydb";
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$state = $_POST['state'];
$email = $_POST['email'];
//$password = $_POST['password'];
//$sha1password = sha1($password);
//Create connection
$conn = new mysqli($servername, $dbusername, $dbpassword, $dbname);
//Check connection
If ($conn -> connect_error) {
die("Connection failed:" . $conn -> connect_error);
}
Line 17 is $conn = newmysqli($...
any idea guys?
Mysql database wizard
Connecting to database now although when i enter in the details (first name, last name, state and email) i get the message first name can not be left blank...
if (empty($fname)) {
Echo "First name can not be blank. Please press back and correct the
issue";
die();
}
if (empty($lname)) {
Echo "Last name can not be blank. Please press back and correct the issue!";
die();
}
if (empty($state)) {
Echo "State can not be blank. Please press back and correct the issue!";
die();
}
if (empty($email)) {
Echo "Email can not be blank. Please press back and correct the issue!";
die();
}
$sql = "INSERT INTO charityh_database (First_Name, Last_Name, State, Email)
VALUES ('$fname', '$lname', '$state', '$email')";
if ($conn->query($sql) === TRUE) {
echo "Thank You";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close ();
?>
$dbusername = "charityh_root";
$dbpassword = "";
Seems like you are using the same username and password as you were using in your local server. You need to replace them with the username and password crazy domain's.
Since as far as I know Crazy Domain deosn't allows a blank password.
EDIT
Besides that I can see the database name you have mentioned in the codes is "charitydb"; which should be something like charityh_database.(By looking at your recent edit this is a wild guess)
The error indicates your username and password do not have access to the database.
Have you checked the database will allow you to connect, using the username and password?
I'm trying to display a message upon a successful user registration however what I have doesn't seem to be working and just submits/refreshes the page. No message pops up even though data has successful been entered into the SQL database. Any tips or ideas?
<?php
require('php/connect.php');
if (isset($_POST['username']) && isset($_POST['password'])){
$username = $_POST['username'];
$email = $_POST['email'];
$password = $_POST['password'];
$query = "INSERT INTO `user` (username, password, email) VALUES ('$username', '$password', '$email')";
$result = mysql_query($query);
if($result){
echo $msg = "Successful Registration!";
}
}
?>
Learning PHP currently so sorry if there's a really obvious answer here!
Edit: Forgot to include echo. Just needed a second pair of eyes, sorry guys. Thanks for the tips!
First of all have this on consideration:
If you're getting started on PHP, please stop using mysql. It's deprecated, instead, you can use either PDO or MySQLi
As for your issue, your message is not being printed. Please make sure you echo the $msg variable:
$msg = "Successful Registration!";
echo $msg;
In mysqli a standard connection would be:
$DBConnect = new mysqli('serverName', 'userName', 'userPassword', 'dbName');
And that's it, that's all you need to start querying your database using mysqli.
For a mysql connection, try debugging it, see if there's a connection:
$connection = mysql_connect('localhost', 'userName', 'userPassword');
if (!$connection) {
die('Could not connect: ' . mysql_error());
}
Try to echo message
if($result)
{
echo $msg = "Successful Registration!";
}
<?php
echo "Successfully registered!";
?>