Output a part of URL in php - php

Question

So, I have dynamically generated pages that follows the following format:
http://example.com/name/first_name/last_name/John%2C+Smith
What is the php code to output the last part of the url?
so, it becomes like "John, Smith".
Thank you so much.
EDIT:
I realized that the URL is ended with another / and the answers given below does not pick it up. What change should I make?
http://example.com/name/first_name/last_name/John%2C+Smith/
EDIT 2:
So, the link is dynamically generated as the following:
href="http://example.com/name/first_name/last_name/<?php echo $full_name ?>"

Answer 1

Split the url, get the last fragment then URL decode it:
<?
$urlarray=explode("/",$url);
$end=$urlarray[count($urlarray)-1];
$end=urldecode($end);
//go on using $end then
?>

Answer 2

You could do this with a regex.
echo preg_replace_callback('~.*/(.*)~',
function($matches) {
return urldecode($matches[1]);
},
'http://example.com/name/first_name/last_name/John%2C+Smith');
Regex demo: https://regex101.com/r/bE3bO5/1
Output:
John, Smith
Update:
echo preg_replace_callback('~.*/(.+)~',
function($matches) {
return rtrim(urldecode($matches[1]), '/');
},
'http://example.com/name/first_name/last_name/John%2C+Smith/');

Answer 3

You can use parse_url with second parameter PHP_URL_PATH
$url = urldecode("http://example.com/name/first_name/last_name/John%2C+Smith");
$arr = array_filter(explode('/',parse_url($url, PHP_URL_PATH)));
print_r(end($arr));
Edited:
As per requirement for dynamic url you can use
$url = urldecode("http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]");