MySql Password_verify() not working? - php

Question

during registration, the user's password is saved in the database as an encrypted BCRYPT password.
My question is: Why can't I verify the encrypted database password with the entered password?
CODE:
<?php //POST VARIABLES
$submit = $_POST['login_submit'];
$username = $_POST['login_username'];
$password = $_POST['login_password'];
$email = $_POST['login_email'];
require 'password_config.php';
if(isset($submit)){
require 'db/connect.php';
//PASSWORD VERIFYING
$pass_query = "SELECT password FROM users WHERE email='$email'";
$queried = mysql_query($pass_query);
while($row = mysql_fetch_array($queried)){
$user_pass = $row['password'];
$veri_password = password_verify($password, $user_pass);
}
//CHECKING NUM ROWS
$sql = "SELECT id, username FROM users WHERE password='$veri_password' AND email='$email'";
$entered_user = mysql_query($sql);
$num_rows = mysql_num_rows($entered_user);
//ERRS ARRAY DECLARED
$errors = array();
//FURTHER VERIFYING
if( $num_rows != 1 )
{
$errors[] = '-Account does not exist ';
}
elseif( $num_rows == 1 )
{
session_start();
while($row = mysql_fetch_array($entered_user)){
$_SESSION['key'] === true;
$_SESSION['id'] = $row['id'];
$_SESSION['email'] = $email;
$_SESSION['user'] = $row['username'];
$_SESSION['pass'] = $password;
header('Location: profile.php');
exit();
}
}
}
?>
I'm receiving an error that says 'account does not exist' even when I enter valid information.
Thanks,
-Eugene
EDIT CHANGED TO THIS:
<?php //POST VARIABLES
$submit = $_POST['login_submit'];
$username = $_POST['login_username'];
$password = $_POST['login_password'];
$email = $_POST['login_email'];
require 'password_config.php';
if(isset($submit)){
require 'db/connect.php';
//PASSWORD VERIFYING
$pass_query = "SELECT password FROM users WHERE email='$email'";
$queried = mysql_query($pass_query);
while($row = mysql_fetch_array($queried)){
$user_pass = $row['password'];
$veri_password = password_verify($password, $user_pass);
}
if($veri_password === true){
//CHECKING NUM ROWS
$sql = "SELECT id, username FROM users WHERE password='$user_pass' AND email='$email'";
$entered_user = mysql_query($sql);
$num_rows = mysql_num_rows($entered_user);
//ERRS ARRAY ESTABLISHED
$errors = array();
//FURTHER VERIFYING
if( $num_rows != 1 )
{
$errors[] = '-Account does not exist ';
}
elseif( $num_rows == 1 )
{
session_start();
while($row = mysql_fetch_array($entered_user)){
$_SESSION['key'] === true;
$_SESSION['id'] = $row['id'];
$_SESSION['email'] = $email;
$_SESSION['user'] = $row['username'];
$_SESSION['pass'] = $password;
header('Location: profile.php');
exit();
}
}
}
}
?>

Answer 1

change to:
$sql = "SELECT id, username FROM users WHERE email='$email'";
Also change:
$veri_password = password_verify($password, $user_pass);
to
if(!password_verify($password, $user_pass)){
echo 'invalid password';
exit;
}
anyway, your code is vulnerable to sql injection. please consider using prepared statements in your queries or escape input strings with mysql_real_escape_string. . And also it is recommended to use mysqli or pdo instead of procedural methods