List data on page2 from a link on page1 - php

Question

page1, the code, below, works fine and lists recipe names i.e. BBQ Pork etc
<form action="recipe_show.php" method="post">
<?php
$result = mysql_query("SELECT recipe_name FROM recipes ORDER BY recipe_name ASC"); // Run the query
if ($result) { // If it ran OK, display the records
// Table header
echo '<table>
<td align="left"><b>Recipe Name</b></td>
</tr>';
// Fetch and print all the records
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo '<tr>
<td>'. $row['recipe_name'] .'</td>
</tr>';
}
echo '</table>'; // Close the table
mysql_free_result ($result); // Free up the resources
} else { // If it did not run OK
// Message
echo '<p class="error">The current recipe_name could not be retrieved. We apologize for any inconvenience.</p>';
// Debugging message
echo '<p>' . mysql_error($dbcon) . '<br><br />Query: ' . $q . '</p>';
} // End of if ($result)
mysql_close($dbcon); // Close the database connection.
?></p>
</form>
</div>
When I click the link, from page1, it opens page2. I get the headings but not the data for the BBQ Pork link. Below is the code on page2.
<form action="" method="post">
<?php
$recipe = mysql_real_escape_string($_GET['recipe_name']); //if using mysql
$myresult = "SELECT * FROM recipes WHERE recipe_name = '".$recipe. "'";
$num = mysql_num_rows($myresult);
for ($i = 0; $i < $num; $i++){
$row = mysql_fetch_array($myresult, MYSQL_ASSOC);
$row = (($i % 2) == 0) ? "table_odd_row" : "table_even_row";
echo "<tr row=".$row.">";
}
if ($myresult) { // If it ran OK, display the records
echo '<table>
<td width="250" align="center"><b>Recipe Name</b></td>
<td width="250" align="left"><b>Instructions</b></td>
<td width="250" align="left"><b>Directions</b></td>
<td width="250" align="left"><b>Notes</b></td>
</tr>';
while ($row = mysql_fetch_array($myresult, MYSQL_ASSOC)) {
echo '<tr>
<td align="left">' . $row['recipe_name'] . '</td>
<td align="left">' . $row['ingredients'] . '</td>
<td align="left">' . $row['directions'] . '</td>
<td align="left">' . $row['notes'] . '</td>
</tr>';
}
echo '</table>'; // Close the table
mysql_free_result ($myresult); // Free up the resources
} else {
echo '<p row="error">The current Recipe could not be retrieved. We apologize for any inconvenience.</p>';
echo '<p>' . mysql_error($dbcon) . '<br><br />Query: ' . $q . '</p>';
} ($myresult)
mysql_close($dbcon); // Close the database connection.
?>
Hope I have correctly set this out? Many thanks, in advance, for help and guidence