How to check the value inside the SQL database in php [closed] - php

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<?php
$email = $_SESSION['eemailid'];
$query1 = mysql_query("SELECT * FROM attendance where email='$email'");
while($row = mysql_fetch_array($query1))
{
$status = $row['status'];
}
if ($status =='IN')
{
echo "Success";
}
else
{
echo "Failed";
}
?>
This is my phd code. I have a database named attendance in that i need to find a user my using email. After finding the user i have column called status in SQL. If the value of the status inside the column is "IN". I need to show Success. If the value is "OUT" i need to show Failed. here i am using email as session to find the current user. Can u please help me to do..
Thank You in advance.

Answer 1

Be sure you are connected to your database.
Be sure you have inserted correct data (username,password,ect.)
Please read this:
http://php.net/manual/en/function.mysql-connect.php
<?php
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully';
mysql_close($link);
?>
and then read this:
http://php.net/manual/en/function.mysql-query.php
<?php
$result = mysql_query("SELECT * FROM attendance where email='%s'"), mysql_real_escape_string($email));
if (!$result){
die('Invalid query: ' . mysql_error());
}
while($row = mysql_fetch_array($result)){
if ($row['status'] =='IN'){
echo "Success";
}
else {
echo "Failed";
}
}
?>

Answer 2

Try this way
<?php
$email = $_SESSION['eemailid'];
$result = mysql_query("SELECT * FROM attendance where email='"$email "'");
$status="";
while($row = mysql_fetch_array($result))
{
$status = $row['status'];
}
if ($status =='IN')
{
echo "Success";
}
else
{
echo "Failed";
}
?>

Answer 3

I'm not sure with your data in Database, but please double check follow these steps below:
$_SESSION['eemailid']; // eemailid or emailid? or email?
How many rows in your database with the column email equal to $email? What is the value of status column of the last row with email equal to $email? because your IF ELSE statement is out of WHILE loop

Answer 4

<?php
$email = $_SESSION['eemailid'];
$query1 = mysql_query("SELECT * FROM attendance where email='$email'");
while($row = mysql_fetch_array($query1))
{
$status = $row['status'];
}
if ($status =='IN')
{
echo "Success";
}
else if ($status == "OUT")
{
echo "Failed";
} else {
echo "Error"
}
?>
Use this code and tell us what happen. This could be a problem with your SQL query