I have built my website in a way so that the actual database files are positioned as follows
root/
root/httpdocs <- public folder
root/databasefolder/actual_files_here/some_photo.jpg
How can I implement so that the php can view/load a photo from that databasefolder and echo it with tag. I simply tried "../databasefolder/" in a tag, but it doesn't work (of course it doesn't), since it's from hidden folder.
I tried Base64 which works in other browsers, but not with Internet Explorer, due to that silly kb limit.
In your HTML:
<img src="image.php?image=some_photo.jpg" />
And a php script that echoes your image.
header('Content-type: image/jpeg');
echo imagejpeg('root/databasefolder/actual_files_here/' . $_GET['image']);
You can use the get parameter "image" to load whatever image you need from that folder.
Related
I am using PHP to upload images in my web application. The images are stored in some directory on the server while their paths are stored directly in MySQL database.
The upload goes very well and images get in the folder but the problem is accessing thoses images with their path field stored in the database : i am not yet able to find the correct form of the path i should use, now am using the realPath and dirname functions to help me get the path so finally an example of path is C:\wamp\www\webroot\img.png (since am on Windows using wampserver) So when i do something like :
<img src="$image->path" />
i get no image shown in the browser and when i inspect it i get the expected code like :
<img src="C:\wamp\www\webroot\img.png" />
which means that this path format is not correct to show the image.
I have tried many things : i took the same path and acced it with the browser and it showed me the image (with the file protocol automatically) so i added file:// to the image path but nothing was new. I have also tried to acces it as a web url and with that it goes will for example it shows the image when putting
localhost/webroot/img.png
But what i need exactly is being able to store and retrive the image file again. So is it a file system probelm ? is the code platform independant ?
I will be very grateful for any help
Thank you.
You can't show an image with its path, but with its URL.
In PHP, we use to save the filename only in MySQL and after, you display the image with <img src="path/to/img/<?php echo $image->filename; ?>" />
That's all!
Add the file protocal to your path.
<img src="file:///<?php echo $image->path; ?>" />.
The best thing you could have to done is save the image in a folder inside your project/website folder. Then save the path to the image from the root folder in the DB.
Example: I uploaded a an image of filename "image.png" inside "Img" folder in the Website Root Folder. Then I will save "Img/image.png" inside my DB.
So anytime I want to reference the image, I will just use
<img src="/<?php echo $image->path; ?>" />
Or
<img src="<?php echo $image->path; ?>" />
Sorry for wasting your time, i have solved the problem. It was an issue with how my application is accessed. It should be accessed from only a directory called web so every path should be referenced from that directory !!.
I have this problem, i have this script in php that creates a image on the fly, the problem is that the outputted image on the browser is allright, but i need to change it's name.
Ex: Index.php
<?php $url = "http://www.somesite.com/cls/image_scrc?_aaa=qJ7VgSxWBLG3FfNQVB%2BKI58kfHQulPHZLuLYaZAG6Tk%3D&_ab=3ctGTf547wdsAGjY%2F5FASE%2BpBnbQEAcrhbJzCHQ7mGs%3D&_acb=89e62acf3b4d254abf0c3ab30d6ebb33" ?>
<img src="<?php echo $url ?>" />
The image_scrc.php is the file that creates the image, and as you can see i have several data that is passed by the get method.
In the image_scrc.php i have tryed
header('Content-type: image/jpg');
header('Content-Disposition:inline; filename="'.$random_name_jpeg.'"');
but the html link is is always appearing like this
http://www.somesite.com/cls/image_scrc?_aaa=qJ7VgSxWBLG3FfNQVB%2BKI58kfHQulPHZLuLYaZAG6Tk%3D&_ab=3ctGTf547wdsAGjY%2F5FASE%2BpBnbQEAcrhbJzCHQ7mGs%3D&_acb=89e62acf3b4d254abf0c3ab30d6ebb33
if i select the image on browser and then select copy image link it copies just like this also.
however, when I save the image it assumes the random_name.jpg, but only on save!
i've tried everything, even htaccess rules but nothing seems to work !!
it's this possible to acomplish? transform this
http://www.somesite.com/cls/image_scrc?_aaa=qJ7VgSxWBLG3FfNQVB%2BKI58kfHQulPHZLuLYaZAG6Tk%3D&_ab=3ctGTf547wdsAGjY%2F5FASE%2BpBnbQEAcrhbJzCHQ7mGs%3D&_acb=89e62acf3b4d254abf0c3ab30d6ebb33
to this
http://www.somesite.com/cls/random_name.jpg
i cant have the image on the server side! and must be displayed on the fly
Thanks in advance.
<img src="d:/Tulips.jpg" >
</img>
<img src="file:///d:Tulips.jpg">
How to retrieve and show images from another drive using src attribute in <img> tag?
If the image is in the same folder it works but when the source of the image is on another drive it's not working.
jpgYou can't put your file system path in the src unless you open it from your desktop or your computer. You can try to pass the file as base64 encoded strings. I'm showing how to do it in PHP because you tagged this question with PHP
$image = file_get_contents('d:/Tulips.jpg');
$image_codes = base64_encode($image);
And in your html put it like this.
<image src="data:image/jpg;charset=utf-8;base64,<?php echo $image_codes; ?>" />
Try
<img src="file:///d:/Tulips.jpg">
You were missing a slash after your drive lettter.
The reason is you are doing the inevitable.
HTML markups cannot read data from the local disk drives, you need to put them in a folder or access it from the same directory for this to work.
Since, when you publish your website images are to be accessed from the folders of your webserver, accessing from a hard-drive directly (not possible via HTML though) puts you under potential risks.
I'm completely new to PHP and I'm writing a page which displays some images from my hard drive.
I've tried different syntaxes and none of them worked out for me ...
I've tested
echo '<img src="/var/www/netbeans/PhpProject2/Plate.jpg" alt ="Test" />';
and It didn't show anything for me .... I've tested this code Also and it didn't worked for me too, I've attached My monitor screen page below. as you can see it seems that my images are not found. I've pasted every address of my images in my browser separately and I was able to see them but when I add them in src argument of img function I'm not able to see them!
What do you think might be the source of problem .... I need to work on a project which needs to be fast enough in working with images.. what do you think I should use ? is "
Try to remove the /var/www. Path should be the http path not the file physical path.
echo '<img src="/netbeans/PhpProject2/Plate.jpg" alt ="Test" />';
I have created a form which takes in images into a folder. I have only one image per folder and I want to display the image from the specified folder.
Say I've uploaded one picture to folder name uploads. Now I want to retrieve that image from the folder and display it.
How do I do that?
When a file is uploaded with your form, it becomes a file on your server, immediately. The web server puts it in a temporary directory and PHP tells you where it was put through the $_FILES array. You can immediately access this file, you can move it somewhere within your website's documents, and you can immediately print out an <img> tag pointing to where the file was put.
Stop writing "an img tag won't work" as that is exactly how you display the image.
Read the PHP manual page "Handling file uploads":
http://php.net/manual/en/features.file-upload.php
The PHP manual should always be the first place you go when you're trying to do something you haven't done before.
<img src="/path/to/the/upload/folder/<?php echo $filename; ?>"/>
or:
echo '<img src="/path/to/the/upload/folder/'.$filename.'"/>";
First you should have the image and path (or user) names in PHP variables. Then use an IMG tag to display them like :
<img src="some_path/uploads/<?php echo $username . '/' . $imagename; ?>">
you can't do it without knowing the name of the image file.
<?php
header('Content-Type:image/jpeg');
readfile('path_to_your/image.jpg');