How to pair those database rows? - php

Question

so, I have this database, I need to know how many profile.stateX-profile.licenseX have value and also to pair them. I am able to pull them in a array but I can't find the propper php code to get what I need.
Again, what I need to know is this:
1: how many profile.state1/2/3/4/5-profile.license1/2/3/4/5 pairs I have with value
2:output the pairs
This is the array returned form query:
<pre>
array(16) {
[0]=>
array(2) {
[0]=>
string(15) "profile.address"
[1]=>
string(10) "Bld. Indep"
}
[1]=>
array(2) {
[0]=>
string(21) "profile.certification"
[1]=>
string(7) "cert112"
}
[2]=>
array(2) {
[0]=>
string(16) "profile.license1"
[1]=>
string(5) "12345"
}
[3]=>
array(2) {
[0]=>
string(16) "profile.license2"
[1]=>
string(0) ""
}
[4]=>
array(2) {
[0]=>
string(16) "profile.license3"
[1]=>
string(0) ""
}
[5]=>
array(2) {
[0]=>
string(16) "profile.license4"
[1]=>
string(0) ""
}
[6]=>
array(2) {
[0]=>
string(16) "profile.license5"
[1]=>
string(0) ""
}
[7]=>
array(2) {
[0]=>
string(21) "profile.licensenumber"
[1]=>
string(7) "lice112"
}
[8]=>
array(2) {
[0]=>
string(14) "profile.school"
[1]=>
string(5) "nr, 2"
}
[9]=>
array(2) {
[0]=>
string(14) "profile.state1"
[1]=>
string(4) "Ohio"
}
[10]=>
array(2) {
[0]=>
string(14) "profile.state2"
[1]=>
string(0) ""
}
[11]=>
array(2) {
[0]=>
string(14) "profile.state3"
[1]=>
string(0) ""
}
[12]=>
array(2) {
[0]=>
string(14) "profile.state4"
[1]=>
string(0) ""
}
[13]=>
array(2) {
[0]=>
string(14) "profile.state5"
[1]=>
string(0) ""
}
[14]=>
array(2) {
[0]=>
string(18) "profile.user_state"
[1]=>
string(8) "Roumania"
}
[15]=>
array(2) {
[0]=>
string(11) "profile.zip"
[1]=>
string(3) "123"
}
}
</pre>
I hope this makes sense.

Answer 1

Assuming the database is MySQL:
SELECT t1.profile_key, t1.profile_value, t2.profile_key, t2.profile_value
FROM profile AS t1
JOIN profile AS t2 ON t2.profile_key = CONCAT('profile.license', SUBSTR(t1.profile_key, 14))
WHERE t1.profile_key LIKE 'profile.state%' AND t1.profile_value != ''
AND t2.profile_key LIKE 'profile.license%' AND t2.profile_value != ''
SUBSTR(t1.profile_key, 14) gets the number after profile.state in profile_key column. Then we use CONCAT() to append that to profile.license to get the profile_key for the paired row.