I'm using Wordpress with UserPro, and want my menu to display the logged-in user's first name, linked to the user profile page.
The problem is that in my menu structure, the "Profile" menu option is supposed to have a sub-menu containing "edit profile", "submit", and "logout".
This is my current code:
/*earlier code, currently commented out, for function to
display username in menu using #profile_name# placeholder
function give_profile_name($atts){
echo userpro_profile_data('first_name', get_current_user_id());
}
add_shortcode('profile_name', 'give_profile_name');
add_filter( 'wp_nav_menu_objects', 'my_dynamic_menu_items' );
function my_dynamic_menu_items( $menu_items ) {
foreach ( $menu_items as $menu_item ) {
if ( '#profile_name#' == $menu_item->title ) {
global $shortcode_tags;
if ( isset( $shortcode_tags['profile_name'] ) ) {
// Or do_shortcode(), if you must.
$menu_item->title = call_user_func( $shortcode_tags['profile_name'] );
}
}
}
return $menu_items;
}
end of earlier code */
//currently in use, unlinked code
add_filter( 'wp_nav_menu_items', 'my_custom_menu_item');
function my_custom_menu_item($items)
{
if(is_user_logged_in())
{
$user=wp_get_current_user();
$name=$user->user_firstname;
$items .= '<li>'.$name.'';
}
return $items;
}
?>
I can fiddle around and try to add the sub-menu under the menu by fiddling with the code from Firebug, but that would mean manual edits to all the links in the functions.php, which would be tedious.
I want to be able to add, edit, remove, and redirect the sub-menu items easily via the Wordpress menu.
Please advise.
Okay, I found a solution (and it can be used for any theme, with any plugin as it only uses core WordPress functions).
In the menu, name the menu item where you want the user's name to appear with a place-holder (such as: #profile_name#, #user#, #random#, etc.)
Now, add the following code to the your child-theme's functions.php:
function give_profile_name($atts){
$user=wp_get_current_user();
$name=$user->user_firstname;
return $name;
}
add_shortcode('profile_name', 'give_profile_name');
add_filter( 'wp_nav_menu_objects', 'my_dynamic_menu_items' );
function my_dynamic_menu_items( $menu_items ) {
foreach ( $menu_items as $menu_item ) {
if ( '#profile_name#' == $menu_item->title ) {
global $shortcode_tags;
if ( isset( $shortcode_tags['profile_name'] ) ) {
// Or do_shortcode(), if you must.
$menu_item->title = call_user_func( $shortcode_tags['profile_name'] );
}
}
}
return $menu_items;
}
In case you're using your own place-holder, remember to replace #profile_name# with the name of your custom place-holder in the code above.
Apologies in case I've misused the term 'place-holder'.
Related
the question is just on the title, but well here's the problem i tried this code on my function.php which at first works fine, but suddenly i realized that the menus on footer changed to be the same as the header menus.
here is the code :
function wpc_wp_nav_menu_args( $args = '' ) {
if( is_user_logged_in() ) {
$args['menu'] = 'logged-out';
} else {
$args['menu'] = 'Main Menu';
}
return $args;
}
add_filter( 'wp_nav_menu_args', 'wpc_wp_nav_menu_args' );
What i want is to have a different header menus for user when they log in and log out, but the footer menus stays the same. i am currently learning how to add the conditional logic on the functions.php atm, but if there are other ways please let me know, thx in advance
Probably a bit late for a reply but I just did this in the Astra theme today, so thought I would share the know-how for others who might need it. It can easily be adjusted for any WordPress theme actually:
You can check the location of the menu and only change the menu in the location(s) you decide (in this example 'primary' and 'mobile_menu' which is what Astra theme calls the the main nav locations for desktop and mobile) :
function custom_wp_nav_menu_args( $args = '' ) {
if( $args['theme_location'] == 'primary' || $args['theme_location'] == 'mobile_menu' ) {
if( ! is_user_logged_in() ) {
$args['menu'] = 'logged-out';
}
}
return $args;
}
add_filter( 'wp_nav_menu_args', 'custom_wp_nav_menu_args' );
If you dont want to use the explicit position of the menu (in my case the nav was in a widget in the footer and not a set theme location), you can also do the same thing by using the id, name or slug of the menu. For example if you want to change the menu 'test-menu' for 'test-menu-logged-out' if the user is logged out, you can use this:
function custom_2_wp_nav_menu_args ( $args = '' ) {
$menu_slug = $args['menu']->slug;
if ( ! is_user_logged_in() && $menu_slug == 'test-menu' ){
$args['menu'] = 'test-menu-logged-out';
}
return $args;
}
add_filter( 'wp_nav_menu_args', 'custom_2_wp_nav_menu_args' );
i am new to WordPress and trying to find a way to add menus based on user roles. I have (guest user or non logged in user) vendor and subscriber roles. I want to display different primary menus depending on what role user is. Example code taken from https://wpcodeus.com/display-different-wordpress-menu-to-logged-in-users/
Example code not working
function nav_menu_args( $args = '' ) {
if( is_user_logged_in('vendor')) {
( 'primary-menu' == $args['theme_location'] ) {
$args['menu'] = 'VendorMenu';
}
}
else if
( is_user_logged_in('subscriber')) {
( 'primary-menu' == $args['theme_location'] ) {
$args['menu'] = 'SubscriberMenu';
}
}
else
(!is_user_logged_in) {
( 'primary-menu' == $args['theme_location'] ) {
$args['menu'] = 'PrimaryMenu';
}
}
return $args;
}
add_filter( 'wp_nav_menu_args', 'nav_menu_args' );
At the moment it changes all menus to vendor menu including primary top and footer, all menus have the same menu.
Any help or guidance in the right direction will be much appreciated.
I am adding the code in to the custom/child theme functions.php file.
you can use current_user_can() function to check user capabiltiy or role. see this link.
This worked for me (slightly different method but same outcome)
if ( current_user_can( 'subscriber' ) ) {
//display menu
}
if ( current_user_can( 'vendor' ) ) {
//display menu
}
I'm trying to disable Jetpack Carousel on a specific post ID using the following code in my functions.php
function djcoh_disable_carousel( $value ) {
wp_reset_query();
if ( is_page( 614 ) ) {
$value = true; // true to disable Carousel
}
// Return original or changed value
return $value;
}
add_filter( 'jp_carousel_maybe_disable', 'djcoh_disable_carousel' );
Here's the reference for jp_carousel_maybe_disable on GitHub
It seems that I'm unable to use is_page() within functions.php - though I thought I'd be able to by using wp_reset_query() as mentioned in the codex
What am I missing?!
The code you have is from a tutorial which is intended for running as a simple plugin. The reason your code doesn't currently work is because you are using it in the functions.php.
In it's current form your function is called as soon as it is read as part of the functions.php file. This is usually some time before the page is formed, and so you can't grab the page id with is_page{}.
Instead you should query the page and get it's id as follows:
function djcoh_disable_carousel( $value ) {
//get the global
global $post
echo "TEST PAGE ID: ".$post->ID;
//wp_reset_query();
if ( $post->ID == 614 ) {
$value = true; // true to disable Carousel
}
wp_reset_query();
// Return original or changed value
return $value;
}
add_filter( 'jp_carousel_maybe_disable', 'djcoh_disable_carousel' );
if that doesn't work try this:
function djcoh_disable_carousel( $value ) {
//get the global
global $wp_query;
$post_ID = $wp_query->post->ID;
echo "TEST PAGE ID: ". $post_ID;
//wp_reset_query();
if ( $post_ID == 614 ) {
$value = true; // true to disable Carousel
}
wp_reset_query();
// Return original or changed value
return $value;
}
add_filter( 'jp_carousel_maybe_disable', 'djcoh_disable_carousel' );
If none of the above work then your script is being called far too early in the process to grab the page id. So, the easiest option would be to simply place this script in it's own .php file and then upload that to the plugins root folder. Then activate it from the plugins menu.
The final option would be to create this as a filter or script and add the function call in the actual page template.
I managed this by using REQUEST_URI within a plugin file:
<?php
// No direct access
if ( ! defined( 'ABSPATH' ) ) exit;
if ( $_SERVER["REQUEST_URI"] === '/PAGE-SLUG/' ) {
add_filter( 'jp_carousel_maybe_disable', '__return_true' );
}
Change PAGE-SLUG for your slug and you are all set.
You can find info on REQUEST_URI in PHP's manuals:
'REQUEST_URI'
The URI which was given in order to access this page; for instance, '/index.html'.
It seems simplest to conditionally dequeue the Jetpack carousel script and stylesheet. The conditionals that you would typically use to control output would be available at the point in the request when the wp_footer action fires.
add_action( 'wp_footer', function() {
if ( is_page( $page ) ) {
wp_dequeue_script( 'jetpack-carousel' );
wp_dequeue_style( 'jetpack-carousel' );
}
}
Be certain to modify the is_page function to include the $page parameter or the condition will match all pages. Place the code in your theme's functions.php file and the Jetpack carousel should be disabled.
Hello friends,
i need little help in Wordpress. I am trying to hide the authorbox that appears under the post for specific user only.
Example if post i am looking into is posted by admin, then i want to hide the authorbox under post content that is posted by admin, but should show for all other users ? i tried different functions but not able to success on this.
I want to completly hide the authorbox, i know it can be done with css code that is
.author-box { display:none;}
but this hides the overall authorbox of complete them, i just want to hide the authorbox on the posts that are made by admin ?
i am using genesis framework, so please suggest if any help you can make here.
Thanks
In your theme's functions.php file, add something like this:
function remove_my_post_metabox() {
global $post;
// If the post author ID is 1, then remove the meta box
// You would need to find the ID of the author, then put it in place of the 1
if ( $post->post_author == 1) {
remove_meta_box( 'authordiv','post','normal' ); // Author Metabox
}
}
add_action( 'add_meta_boxes', 'remove_my_post_metabox' );
If you need to find out the role of the author, and truly do it based on the role (admin, for example), then it would be more like this:
function remove_my_post_metabox() {
global $post;
// If there's no author for the post, get out!
if ( ! $post->post_author) {
return;
}
// Load the user
$user = new WP_User( $post->post_author );
// Set "admin" flag
$is_admin = FALSE;
// Check the user roles
if ( !empty( $user->roles ) && is_array( $user->roles ) ) {
foreach ( $user->roles as $role ) {
if ( $role == 'administrator' ) {
$is_admin = TRUE;
}
}
}
// Lastly, if they ARE an admin, remove the metabox
if ( $is_admin ) {
remove_meta_box( 'authordiv','post','normal' ); // Author Metabox
}
}
add_action( 'add_meta_boxes', 'remove_my_post_metabox' );
I'm using a function to display logged-in user name in wordpress navigation menu and I would like to also display logged-in user avatar in the menu but couldn't find a way to do this. So I'm asking for some help :)
Here is the function I'm using for the name:
function my_dynamic_menu_items( $menu_items ) {
foreach ( $menu_items as $menu_item ) {
if ( '#current-username#' == $menu_item->title ) {
global $shortcode_tags;
if ( isset( $shortcode_tags['current-username'] ) ) {
// Or do_shortcode(), if you must.
$menu_item->title = call_user_func( $shortcode_tags['current-username'] );
}
}
}
return $menu_items;
}
add_filter( 'wp_nav_menu_objects', 'my_dynamic_menu_items' );
I have this code in my functions.php and I call it with #current-username# in a menu item, is there a way to customise this code to also output the avatar? Thanks for any help.
try this : echo get_avatar( $id_or_email, $size, $default, $alt );
you can display user name as like.
add_filter( 'wp_nav_menu_items', 'your_custom_menu_item', 10, 2 );
function your_custom_menu_item ( $items, $args ) {
$current_user = wp_get_current_user();
if(!empty($current_user->user_login))
$items .= '<li>'.$current_user->user_login.'</li>';
return $items;
}