I had a SELECT query like this at first..
($con,"SELECT * FROM users ORDER BY id ASC LIMIT 1");
But, I realized that I needed the newest user out of the groups 2, 3, 4, or 5 (excluding group 1). So in the end I only want one user showing that is the newest.
What is wrong with my SELECT query now that it would not show up anything?
//Newest Member
$member = mysqli_query($con,"SELECT * FROM users WHERE `group`=2, 3, 4,5 ORDER BY id ASC LIMIT 1");
$numrows_member = mysqli_num_rows($member);
if($numrows_member > 0){
while($row_member = mysqli_fetch_assoc($member)){
$memberid = $row_member['id'];
$member_username = $row_member['username'];
echo $member_username;
}
} else {
echo "No Members Found...";
}
You are looking for the IN operator. The syntax would be like this:
SELECT *
FROM users
WHERE `group` IN (2, 3, 4, 5)
ORDER BY id ASC
LIMIT 1;
There is a reference here.
Note: Based on your comment, if you are looking for the latest user you may want to order in DESC order instead, so that the largest id is put first. Even better (in my opinion), if you store the account_created_date you could order by that. Again, in descending order.
If you want to exclude a specific group, use != instead of trying to find one of the remaining groups:
SELECT * FROM users WHERE `group` != 1 ORDER BY id ASC LIMIT 1
Related
I got a little problem, I've got a database, in that database are different names, id, and coins. I want to show people their rank, so your rank has to be 1 if you have the most coins, and 78172 as example when your number 78172 with coins.
I know I can do something like this:
SELECT `naam` , `coins`
FROM `gebruikers`
ORDER BY `coins` DESC
But how can I get the rank you are, in PHP :S ?
You can use a loop and a counter. The first row from MySql is going the first rank,I.e first in the list.
I presume you want something like:
1st - John Doe
2nd - Jane Doe
..
..
right?
See: http://www.if-not-true-then-false.com/2010/php-1st-2nd-3rd-4th-5th-6th-php-add-ordinal-number-suffix
Helped me a while ago.
You could use a new varariable
$i = "1";
pe care o poti folosi in structura ta foreach,while,for,repeat si o incrementezi mereu.
and you use it in structures like foreach,while,for,repeat and increment it
$i++;
this is the simplest way
No code samples above... so here it is in PHP
// Your SQL query above, with limits, in this case it starts from the 11th ranking (0 is the starting index) up to the 20th
$start = 10; // 0-based index
$page_size = 10;
$stmt = $pdo->query("SELECT `naam` , `coins` FROM `gebruikers` ORDER BY `coins` DESC LIMIT {$start}, {$page_size}");
$data = $stmt->fetchAll();
// In your template or whatever you use to output
foreach ($data as $rank => $row) {
// array index is 0-based, so add 1 and where you wanted to started to get rank
echo ($rank + 1 + $start) . ": {$row['naam']}<br />";
}
Note: I'm too lazy to put in a prepared statement, but please look it up and use prepared statements.
If you have a session table, you would pull the records from that, then use those values to get the coin values, and sort descending.
If we assume your Session table is sessions(session_id int not null auto_increment, user_id int not null, session_time,...) and we assume that only users who are logged in would have a session value, then your SQL would look something like this: (Note:I am assuming that you also have a user_id column on your gebruikers table)
SELECT g.*
FROM gebruikers as g, sessions as s WHERE s.user_id = g.user_id
ORDER BY g.coins DESC
You would then use a row iterator to loop through the results and display "1", "2", "3", etc. The short version of which would look like
//Connect to database using whatever method you like, I will assume mysql_connect()
$sql = "SELECT g.* FROM gebruikers as g, sessions as s WHERE s.user_id = g.user_id ORDER BY g.coins DESC";
$result = mysql_query($sql,$con); //Where $con is your mysql_connect() variable;
$i = 0;
while($row = mysql_fetch_assoc($result,$con)){
$row['rank'] = $i;
$i++;
//Whatever else you need to do;
}
EDIT
In messing around with a SQLFiddle found at http://sqlfiddle.com/#!2/8faa9/6
I came accross something that works there; I don't know if it will work when given in php, but I figured I would show it to you either way
SET #rank = 0; SELECT *,(#rank := #rank+1) as rank FROM something order by coins DESC
EDIT 2
This works in a php query from a file.
SELECT #rank:=#rank as rank,
g.*
FROM
(SELECT #rank:=0) as z,
gebruikers as g
ORDER BY coins DESC
If you want to get the rank of one specific user, you can do that in mysql directly by counting the number of users that have more coins that the user you want to rank:
SELECT COUNT(*)
FROM `gebruikers`
WHERE `coins` > (SELECT `coins` FROM `gebruikers` WHERE `naam` = :some_name)
(assuming a search by name)
Now the rank will be the count returned + 1.
Or you do SELECT COUNT(*) + 1 in mysql...
Can someone advise on how to get around this problem?
I want to call the top 50 rows by id from my SHOUTBOX table, but display them in a div in ascending order (the most recent row (newest) at the bottom)
for example;
most recent row is id 200,
I want to call rows 150 - 200,
display them in the div like;
150,
151,
152,
.
.
.etc
.
.
200 <<< last line in DIV
my PHP code currently looks like this;
$recall=mysql_query("SELECT *, DATE_FORMAT(timepost,'%H:%i:%s') as timepost FROM shoutbox ORDER BY id DESC LIMIT 50");
while($comm=mysql_fetch_object($recall)){
if ($comm->poster == "System"){
print"<font color=#3399FF>$comm->timepost-<strong><a href='profile.php?viewuser=$comm->poster' target='iframecontent'><font color=#3399FF>$comm->poster</font></a></strong>: </font>";
echo replace($comm->post);
echo"<br>";
}
but it returns my data in the div like;
200,
199,
198,
.
.
.etc
.
.
150 <<< last line in DIV
Please can anyone help?
note: I am currently working through all my pages and converting all mySQL queries to PDO
For future reference, if you're converting to PDO there is the exact answer for reading backwards on this page without changing your query. http://www.php.net/manual/en/pdostatement.fetch.php.
For now this will work:
SELECT *, DATE_FORMAT(timepost,'%H:%i:%s') AS timepost FROM (SELECT * FROM shoutbox ORDER BY id DESC LIMIT 50) AS foo ORDER BY id ASC
Ok, try this:
$recall=mysql_query("SELECT *, DATE_FORMAT(timepost,'%H:%i:%s') as timepost FROM (SELECT * FROM shoutbox ORDER BY id DESC LIMIT 50) ORDER BY id ASC");
replace ORDER BY id DESC by ORDER BY id
You have wrong the order command, you have to put ASC instead of DESC Here is your correct query:
$recall=mysql_query("SELECT *, DATE_FORMAT(timepost,'%H:%i:%s') as timepost FROM shoutbox ORDER BY id ASC LIMIT 50");
while($comm=mysql_fetch_object($recall)){
if ($comm->poster == "System"){
print"<font color=#3399FF>$comm->timepost-<strong><a href='profile.php?viewuser=$comm->poster' target='iframecontent'><font color=#3399FF>$comm->poster</font></a></strong>: </font>";
echo replace($comm->post);
echo"<br>";
}
Change your query to:
$recall = mysql_query("SELECT *, DATE_FORMAT(timepost,'%H:%i:%s') as timepost
FROM shoutbox ORDER BY id ASC LIMIT 50");
ok so i coded in a news section and everytime i insert new news,its shows below the old one.
i want to make it ORDER BY id but make it start like backwards.i dont know how to explain but yeh
i want them to be ordered by the newest added by the id so if the 1st row that was inserted's id is 1 then i want it to show below the next id.
so row with id = 2 will be here
so row with id = 1 will be here
thats how i want it to be, instead of it being like this
so row with id = 1 will be here
so row with id = 2 will be here
.
Sorry for my bad explanation i hope this is understandable
heres my code so far
<?php
require("include/config.php");
$sqlnews = mysql_query("SELECT * FROM news ORDER BY id");
while($row = mysql_fetch_array($sqlnews)) {
$dbdate = $row['date'];
$dbnews = $row['news'];
echo "<h1><strong>$dbdate</strong></h1>";
echo "<div class='content'>$dbnews</div><br><br>";
}
?>
add DESC in your ORDER BY clause
SELECT * FROM news ORDER BY id DESC
by default, it is in ASC mode.
SELECT * FROM news ORDER BY id DESC
DESC is the descending keyword ASC is ascending
If you specify neither then default behaviour is ascending
Just use DESC keyword in your sql query.
$sqlnews = mysql_query("SELECT * FROM news ORDER BY id DESC");
However, it isn't really such a good idea to use id, because semantically, there is nothing preventing somebody from changing the sequence which counts up automatically assigning the ID.
Therefore, you should add a column created_at. Everytime you insert a row, you can use the SQL function NOW().
The advantage is that you can say:
SELECT * FROM news WHERE created_at <= NOW() ORDER BY created_at DESC
This means that you can schedule news items ahead of time, and it will automatically display when the date/time arrives!
$sqlnews = mysql_query("SELECT * FROM news ORDER BY id DESC");
try this:
just have to add
order by id DESC
Just replace your code by this code:
<?php
require("include/config.php");
$sqlnews = mysql_query("SELECT * FROM news ORDER BY id DESC");
while($row = mysql_fetch_array($sqlnews)) {
$dbdate = $row['date'];
$dbnews = $row['news'];
echo "<h1><strong>$dbdate</strong></h1>";
echo "<div class='content'>$dbnews</div><br><br>";
}
?>
So I'm trying to add a little bit of convenience to a CRUD by adding next and previous links to navigate between records in my database.
Here are my queries:
$id=$_GET['id'];
$id = $currentid;
$prevquery= "SELECT * FROM inventory WHERE id < $currentid ORDER BY id DESC LIMIT 1";
$prevresult = mysql_query($prevquery);
$nextquery= "SELECT * FROM inventory WHERE id > $currentid ORDER BY id ASC LIMIT 1";
$nextresult = mysql_query($nextquery);
?>
Here is my HTML:
Previous
Next
Now I tested these queries in PHPMyAdmin and they produced the result I wanted, but I can't get my hyperlinks to actually be supplied with the correct IDs... they're just blank after the =. What am I doing wrong?
mysql_query() returns a result set (resource). To get the actual rows from the result set, you need to use a function like mysql_fetch_row().
Your code for the "next" link would look something like:
PHP
$nextquery= "SELECT * FROM inventory WHERE id > $currentid ORDER BY id ASC LIMIT 1";
$nextresult = mysql_query($nextquery);
if(mysql_num_rows($nextresult) > 0)
{
$nextrow = mysql_fetch_row($nextresult);
$nextid = $nextrow['id'];
}
HTML
Next
and the previous link would be done similarly.
Obligatory note: For new code, you should seriously consider using PDO.
Advanced note:
You could combine your queries into a single query like:
SELECT
(
SELECT id
FROM inventory WHERE id < $currentid ORDER BY id DESC LIMIT 1
) AS previd,
(
SELECT id
FROM inventory WHERE id > $currentid ORDER BY id ASC LIMIT 1
) AS nextid
And then adjust the logic accordingly.
Okay, It took a little bit but I figured it out...
PHP
$prevquery= "SELECT * FROM inventory WHERE id < $currentid ORDER BY id DESC LIMIT 1";
$prevresult = mysql_query($prevquery) or die(mysql_error());
while($prevrow = mysql_fetch_array($prevresult))
{
$previd = $prevrow['id'];
}
$nextquery= "SELECT * FROM inventory WHERE id > $currentid ORDER BY id ASC LIMIT 1";
$nextresult = mysql_query($nextquery) or die(mysql_error());
while($nextrow = mysql_fetch_array($nextresult))
{
$nextid = $nextrow['id'];
}
HTML
Previous
Next
Thanks for the help, I think it put me on the right course. I'll look into that PDO stuff for the future. I'm just now starting to get a hang of the old MYSQL/PHP syntax and now all the sudden there's a new format... tough to keep up with it all!
The resultant code has a culprit at the very beginning and end of the table. Your code will "die" as you ordered. Instead you might check the query results ($prevresult, $nextresult) and decide NOT to show a link for previous or next item.
SELECT
IFNULL(
(SELECT id FROM inventory WHERE id < $currentid ORDER BY id DESC LIMIT 1 ) , (SELECT id FROM inventory ORDER BY id DESC LIMIT 1 )
) AS previd ,
IFNULL(
(SELECT id FROM inventory WHERE id > $currentid ORDER BY id ASC LIMIT 1 ),
(SELECT id FROM inventory ORDER BY id ASC LIMIT 1 )
) AS nextid
I want to get all rows count in my sql.
Table's first 2 columns look like that
My function looks like that
$limit=2;
$sql = "SELECT id,COUNT(*),dt,title,content FROM news ORDER BY dt DESC LIMIT " . $limit;
$stmt = $this->db->prepare($sql);
$stmt->execute();
$stmt->bind_result($id, $total, $datetime, $title, $content);
$stmt->store_result();
$count = $stmt->num_rows;
if ($count > 0) {
while ($stmt->fetch()) {
Inside loop, I'm getting exact value of $total, but MySQL selects only 1 row - row with id number 1. (and $count is 1 too)
Tried this sql
SELECT id,dt,title,content FROM news ORDER BY dt DESC LIMIT 2
All goes well.
Why in first case it selects only 1 row? How can I fix this issue?
for ex my table has 5 rows. I want to get 2 of them with all fields, and get all rows count (5 in this case) by one query.
Remove COUNT(*). You will only ever get 1 row if you leave it in there.
Try adding GROUP BY dt if you want to use COUNT(*) (not sure why you're using it though).
EDIT
Fine, if you insist on doing it in a single call, here:
$sql = "SELECT id,(SELECT COUNT(id) FROM news) as total,dt,title,content FROM news ORDER BY dt DESC LIMIT " . $limit;
This is likely cause by the variable $limit being set to 1, or not being set and mysql defaulting to 1. Try changing your first line to
$sql = "SELECT id,COUNT(*),dt,title,content FROM news ORDER BY dt DESC";
EDIT
Change to:
$sql = "SELECT SQL_CALC_FOUND_ROWS,id,dt,title,content FROM news ORDER BY dt DESC LIMIT " . $limit;
And then use a second query with
SELECT FOUND_ROWS( )
to get the number of rows that match the query
This totally wreaks of a HW problem... why else besides a professor's retarded method to add complexity to a simple problem would you not want to run two queries?
anyways.... here:
SELECT id, (SELECT COUNT(*) FROM news) AS row_count, dt, title, content FROM news ORDER BY dt DESC LIMIT