I have this:
$previousMonth = new DateTime('2019-12-31');
$previousMonth->modify('-1 month');
My understanding is '-1 month' should modify the object regardless of number of days in that month, or?
Naturally what should I get or expect to get is end of Nov(2019-11-30) but what I get is first of December(the same month).
BTW if I change the date to '2019-12-30'(one day prior) then it will be end of Nov.
If my initial assumption is not correct, then what is the best alternative to reliably calculate the previous month?
Any thoughts?
The simplest and easiest way to get the last month in php is
$previousMonth = date("Y-n-j", strtotime("last day of previous month"));
Same as been suggested on other thread Getting last month's date in php
$date = "2019-12-31 00:00:00";
echo date('Y-m-d', strtotime($date . '-1month'));
This prints out 2019-12-01 as the 31/11 does not exist.
The following doesn't answer your question but may help in the future. I like to use Carbon when working with dates. Your issue could be resolved quite simply with this.
https://carbon.nesbot.com/
It has many functions and is extremely simple to use, and it can be installed with Composer.
To get the last day of the previous month, you can get the first day of the current month and substract 1 second or 1 day :
$previousMonth = new DateTime('2019-12-31');
$previousMonth->modify($previousMonth->format('Y-m-01')); // date is 2019-12-01 00:00:00
$previousMonth->modify('-1 sec');
echo $previousMonth->format('Y-m-d H:i:s') . PHP_EOL; // Outputs 2019-11-30 23:59:59
$previousMonth->modify('+1 sec'); // set back the original date 2019-12-01 00:00:00
$previousMonth->modify('-1 day');
echo $previousMonth->format('Y-m-d H:i:s'); // Outputs 2019-11-30 00:00:00
I want to get the previous months date range with PHP. I have tried below function to get last month's date range.
$last_month_start_date = date('Y-m-d',strtotime('first day of last month'));
$last_month_end_date = date('Y-m-d',strtotime('last day of last month'));
echo $last_month_start_date.' - '.$last_month_end_date;
Output: 2019-09-01 - 2019-09-30
but how can I get previous month's date range with PHP?
can anybody help me with this?
To get Last to Last Month: If current month is October then below output gives first and last date of August
$last_to_last_start_date = $last_month_start_date = date('Y-m-d',strtotime('first day of last month -1 month'));
// outout 2019-08-01
$last_to_last_end_date = $last_month_end_date = date('Y-m-d',strtotime('last day of last month -1 month'));
// outout 2019-08-31
echo $last_to_last_start_date .' - '.$last_to_last_end_date ;
//Output : 2019-08-01 - 2019-08-31
Create a date-time object that is two months behind, then use a modifier of first/last day of this month. The this month modifier works on the month of the object, so if the object's date is in August, it will look for the first and last days of August.
This means that you can provide any value for -2 months (like February, -1 month) and it will get the start and end-dates for that month.
$start = new DateTime("-2 months");
$end = clone $start;
$start->modify("first day of this month");
$end->modify("last day of this month");
echo $start->format("Y-m-d")." - ".$end->format("Y-m-d");
In October 2019, this outputs,
2019-08-01 - 2019-08-31
Live demo at https://3v4l.org/udGtE
I have used the below PHP function to get the previous month,
$currmonth = date('m', strtotime('-1 month'));
It was working fine and I was getting the value of 04 till yesterday. On today May 31st (Last day of the month May), I noticed the function returns the current month only. That is 05. Is there any other alternate function which returns the previous month accurately.
Try strtotime("first day of last month").
The first day of is the important part as detailed here.
Literally ask strtotime for the 'first day of the previous month' this makes sure it selects the correct month:-
$currmonth = date("m", strtotime("first day of previous month"));
You can use OOP with DateTime class and modify method:
$now = new DateTime();
$previousMonth = $now->modify('first day of previous month');
echo $previousMonth->format('m');
strtotime() works accurately. The problem is what you ask it to return.
"-1 month" is not the same as "previous month". It is the same as "subtract 1 from current month then normalize the result".
On 2017-05-31, subtracting 1 from current month gets 2017-04-31 which is not a valid date. After normalization, it becomes 2017-05-01, hence the result you get.
There are more than one way to get the value you need. For example:
// Today
$now = new DateTime('now');
// Create a date interval string to go back to the first day of the previous month
$int = sprintf('P1M%dD', $now->format('j')-1);
// Get the first day of the previous month as DateTime
$fdopm = $now->sub(new DateInterval($int));
// Verify it works
echo($fdopm->format('Y-m-d'));
// On 2017-05-31 it should print:
// 2017-04-01
If you just need to get the month number of previous month, the following should suffice.
$m = idate("m") - 1;
// wrap to previous year
if ($m < 1) {
$m = 12 - abs($m) % 12;
}
This works with arbitrary number of subtracted months.
Right now if you where to use strtotime('1 month') on January 31st you would get march 1st but I wondering if there is a simple way that if I where to run that same script on the same day instead of getting march 1st I could get February 28. Is this possible? Any suggestions would be greatly appreciated.
Thanks
EDIT:
Sorry I think I did not explain this properly, I want to be able to always get 30 days except for months where that day dont exists. So for instance if it is January 31st I want to be able to get February 28th but if it was January 10 I want February 10.
You could try a more verbose text:
$date = new DateTime('last day of next month');
echo $date->format('Y-m-d');
// => 2014-10-31
EDIT:
To answer your updated question, you can start with next month and compare it to last day of next month. If next month is larger than last day of next month, use last day of next month instead:
$date = new DateTime('next month');
if ($date > ($end = new DateTime('last day of next month'))) {
$date = $end;
}
I need to get previous month and year, relative to current date.
However, see following example.
// Today is 2011-03-30
echo date('Y-m-d', strtotime('last month'));
// Output:
2011-03-02
This behavior is understandable (to a certain point), due to different number of days in february and march, and code in example above is what I need, but works only 100% correctly for between 1st and 28th of each month.
So, how to get last month AND year (think of date("Y-m")) in the most elegant manner as possible, which works for every day of the year? Optimal solution will be based on strtotime argument parsing.
Update. To clarify requirements a bit.
I have a piece of code that gets some statistics of last couple of months, but I first show stats from last month, and then load other months when needed. That's intended purpose. So, during THIS month, I want to find out which month-year should I pull in order to load PREVIOUS month stats.
I also have a code that is timezone-aware (not really important right now), and that accepts strtotime-compatible string as input (to initialize internal date), and then allows date/time to be adjusted, also using strtotime-compatible strings.
I know it can be done with few conditionals and basic math, but that's really messy, compared to this, for example (if it worked correctly, of course):
echo tz::date('last month')->format('Y-d')
So, I ONLY need previous month and year, in a strtotime-compatible fashion.
Answer (thanks, #dnagirl):
// Today is 2011-03-30
echo date('Y-m-d', strtotime('first day of last month')); // Output: 2011-02-01
Have a look at the DateTime class. It should do the calculations correctly and the date formats are compatible with strttotime. Something like:
$datestring='2011-03-30 first day of last month';
$dt=date_create($datestring);
echo $dt->format('Y-m'); //2011-02
if the day itself doesn't matter do this:
echo date('Y-m-d', strtotime(date('Y-m')." -1 month"));
I found an answer as I had the same issue today which is a 31st. It's not a bug in php as some would suggest, but is the expected functionality (in some since). According to this post what strtotime actually does is set the month back by one and does not modify the number of days. So in the event of today, May 31st, it's looking for April-31st which is an invalid date. So it then takes April 30 an then adds 1 day past it and yields May 1st.
In your example 2011-03-30, it would go back one month to February 30th, which is invalid since February only has 28 days. It then takes difference of those days (30-28 = 2) and then moves two days past February 28th which is March 2nd.
As others have pointed out, the best way to get "last month" is to add in either "first day of" or "last day of" using either strtotime or the DateTime object:
// Today being 2012-05-31
//All the following return 2012-04-30
echo date('Y-m-d', strtotime("last day of -1 month"));
echo date('Y-m-d', strtotime("last day of last month"));
echo date_create("last day of -1 month")->format('Y-m-d');
// All the following return 2012-04-01
echo date('Y-m-d', strtotime("first day of -1 month"));
echo date('Y-m-d', strtotime("first day of last month"));
echo date_create("first day of -1 month")->format('Y-m-d');
So using these it's possible to create a date range if your making a query etc.
If you want the previous year and month relative to a specific date and have DateTime available then you can do this:
$d = new \DateTimeImmutable('2013-01-01', new \DateTimeZone('UTC'));
$firstDay = $d->modify('first day of previous month');
$year = $firstDay->format('Y'); //2012
$month = $firstDay->format('m'); //12
date('Y-m', strtotime('first day of last month'));
strtotime have second timestamp parameter that make the first parameter relative to second parameter. So you can do this:
date('Y-m', strtotime('-1 month', time()))
if i understand the question correctly you just want last month and the year it is in:
<?php
$month = date('m');
$year = date('Y');
$last_month = $month-1%12;
echo ($last_month==0?($year-1):$year)."-".($last_month==0?'12':$last_month);
?>
Here is the example: http://codepad.org/c99nVKG8
ehh, its not a bug as one person mentioned. that is the expected behavior as the number of days in a month is often different. The easiest way to get the previous month using strtotime would probably be to use -1 month from the first of this month.
$date_string = date('Y-m', strtotime('-1 month', strtotime(date('Y-m-01'))));
I think you've found a bug in the strtotime function. Whenever I have to work around this, I always find myself doing math on the month/year values. Try something like this:
$LastMonth = (date('n') - 1) % 12;
$Year = date('Y') - !$LastMonth;
date("m-Y", strtotime("-1 months"));
would solve this
Perhaps slightly more long winded than you want, but i've used more code than maybe nescessary in order for it to be more readable.
That said, it comes out with the same result as you are getting - what is it you want/expect it to come out with?
//Today is whenever I want it to be.
$today = mktime(0,0,0,3,31,2011);
$hour = date("H",$today);
$minute = date("i",$today);
$second = date("s",$today);
$month = date("m",$today);
$day = date("d",$today);
$year = date("Y",$today);
echo "Today: ".date('Y-m-d', $today)."<br/>";
echo "Recalulated: ".date("Y-m-d",mktime($hour,$minute,$second,$month-1,$day,$year));
If you just want the month and year, then just set the day to be '01' rather than taking 'todays' day:
$day = 1;
That should give you what you need. You can just set the hour, minute and second to zero as well as you aren't interested in using those.
date("Y-m",mktime(0,0,0,$month-1,1,$year);
Cuts it down quite a bit ;-)
This is because the previous month has less days than the current month. I've fixed this by first checking if the previous month has less days that the current and changing the calculation based on it.
If it has less days get the last day of -1 month else get the current day -1 month:
if (date('d') > date('d', strtotime('last day of -1 month')))
{
$first_end = date('Y-m-d', strtotime('last day of -1 month'));
}
else
{
$first_end = date('Y-m-d', strtotime('-1 month'));
}
If a DateTime solution is acceptable this snippet returns the year of last month and month of last month avoiding the possible trap when you run this in January.
function fn_LastMonthYearNumber()
{
$now = new DateTime();
$lastMonth = $now->sub(new DateInterval('P1M'));
$lm= $lastMonth->format('m');
$ly= $lastMonth->format('Y');
return array($lm,$ly);
}
//return timestamp, use to format month, year as per requirement
function getMonthYear($beforeMonth = '') {
if($beforeMonth !="" && $beforeMonth >= 1) {
$date = date('Y')."-".date('m')."-15";
$timestamp_before = strtotime( $date . ' -'.$beforeMonth.' month' );
return $timestamp_before;
} else {
$time= time();
return $time;
}
}
//call function
$month_year = date("Y-m",getMonthYear(1));// last month before current month
$month_year = date("Y-m",getMonthYear(2)); // second last month before current month
function getOnemonthBefore($date){
$day = intval(date("t", strtotime("$date")));//get the last day of the month
$month_date = date("y-m-d",strtotime("$date -$day days"));//get the day 1 month before
return $month_date;
}
The resulting date is dependent to the number of days the input month is consist of. If input month is february (28 days), 28 days before february 5 is january 8. If input is may 17, 31 days before is april 16. Likewise, if input is may 31, resulting date will be april 30.
NOTE: the input takes complete date ('y-m-d') and outputs ('y-m-d') you can modify this code to suit your needs.