I have a session variable that is updated when a link is clicked which adds GET variables to the current URL:
<?php
$_SESSION['test'] = 0;
if (isset($_GET['do'] && $_GET['do'] == 'this')) {
$_SESSION['test'] = $_SESSION['test'] + 1;
}
echo $_SESSION['test'];
?>
Click me
When the link is clicked, the new session value that is echoed is still 0.
Why? How do I get this to echo the updated value? (1)
EDIT: Yes, session_start() is included at the top of the page.
change it to be like this:
<?php
session_start();
if(!array_key_exists('test', $_SESSION)){
$_SESSION['test'] = 0;
}
if(array_key_exists('do', $_GET) && $_GET['do'] === 'this') {
$_SESSION['test']++;
}
echo $_SESSION['test'];
?>
Click me
I like array_key_exists() more than isset because the key can exist being null and still pass the test:
From the php docs: "isset() does not return TRUE for array keys that correspond to a NULL value, while array_key_exists() does."
You also were using isset incorrectly to test the contents of $_GET['do']. To top things off, you didn't start the session on each page load.
session_start() will initialize the $_SESSION variable and fill it with the appropriate contents. Since this was not in your code, the $_SESSION variable never had your 'do' key.
The second-to-last problem you had was the very first line, you were always setting the 'test' key to 0 causing the outcome to always be 1 after clicking Click me
and finally, you didn't close the php tag prior to outputting raw HTML which should have given you an error
Maybe you have not paste the whole code but here is how it should have been done.
<?php
session_start();
$_SESSION['test'] = 0;
if (isset($_GET['do']) && $_GET['do'] == 'this') {
$_SESSION['test'] += 1;
}
echo $_SESSION['test'];
?>
Click me
You need to start with session_start() Google to learn more about it.
You have put everything in the isset() Google isset() to learn more about it.
you need to close php tags before you can insert raw HTML. Inside HTML you can execute php with <?php ?> tags.
Hope this helps.
As mentioned before, you have everything wrapped in isset() should be
isset($_GET['do'])
not
isset($_GET['do']
Also, you're session is always being set to 0 on each page refresh. You need to only set $_SESSION['test'] = 0 if $_SESSION['test'] has not been set yet.
if (!isset($_SESSION['test'])) {
$_SESSION['test'] = 0;
}
You are missing session_start() at the top of your script. You're also not assigning the session if it doesn't previously exist, you're continuously setting it to 0 before incrementing.
Related
How to access the incremented value of session on the same page where we have defined the initial value of session, I am using this method for incrementation of value but on another page
<?php
$_SESSION['indexValue'] = 1;
?>
This is my test.php page where i have decrelaed the inital value of session.
<?php
$Incrementvalue = $_SESSION['indexValue'];
$counter = (int)$Incrementvalue;
if ($counter=$counter) {
$counter++;
$_SESSION['indexValue'] = $counter;
}
echo "$_SESSION['indexValue']";
?>
This is my getdata.php page where I have implmented the increment value function. Now i have to pass this increment value of Session again on test.php page . How can I perform this?
your code seems not to be thought off
first of all, you need to call session_start() at beginning
then you can access everyewhere your $_SESSION variable (if you call session_start() before)
if ($counter=$counter) {
$counter++;
$_SESSION['indexValue'] = $counter;
}
this seems useless
$_SESSION['indexValue']++;
is enough
First of all there are few errors in code like
if ($counter=$counter) should be if ($counter == $counter)
And
echo "$_SESSION['indexValue']" should be echo $_SESSION['indexValue'].
Now answer to your question is that session is accessible anywhere throughout the project/application. So you need not to pass it , just access it as $_SESSION['indexValue'].
Hey guys I'm trying to pass a php variable to another page. I tried it with sessions but no result.
newspaper.php
$newspaper= $newspaper['newspath'];
print_r($newspaper);
this outputs:
path/to/the/newspaper.
Now I want to use the variable in the second page.
newspaperviewer.php
echo $newspaper;
$SESSION = $newspaper;
I tried the first one but no result. The second one seems to be faulty.
Hope you guys can help me out.
Session is what you are looking for. A session variable can store a value and use this value on all pages of your project.
First thing to do is to start session on each file on your project. You can do this like this example
<?php
session_start(); //declare you are starting a session
$_SESSION['newspaper'] = "New York Times"; //Assign a value to the newspaper session
?>
On the other file you can use the value of the session by trying something like this
<?php
session_start(); //always start session don't forget!!
echo $_SESSION['newspaper'];
// This will echo New York Times
?>
Store the variable after starting session on page A, like so:
// FIRST PAGE (foo.php)
session_start();
$_SESSION['name'] = 'Jack';
Now, on the second page (or any page that you want to have access to $_SESSION, simply do the same but pull the variable.
// SECOND PAGE (bar.php)
session_start();
$name = $_SESSION['name'];
$_SESSION['name'] = null; // Or use session_unset() to delete all SESSION vars.
And that's how you pass variables using $_SESSION.
Please use this code to set session
<?php
// Start the session
session_start();
?>
<!DOCTYPE html>
<html>
<body>
<?php
// Set session variables
$_SESSION["favcolor"] = "green";
$_SESSION["favanimal"] = "cat";
echo "Session variables are set.";
?>
</body>
</html>
You can write like this
newspaper.php
session_start();
$newspaper= $newspaper['newspath'];
$_SESSION['newspaper'] = $newspaper;
Now you can use this session variable in
newspaperviewer.php
session_start();
$newspaper = $_SESSION['newspaper'];
echo $newspaper;
session_unset(); // remove all session variables
First
newspaper.php
$newspaper= $newspaper['newspath'];
//print_r($newspaper);
session_start(); //it starts your session here
$_SESSION['newspaper']=$newspaper; //it sets a session variable named as newspaper
Second
$newspaper= isset($_SESSION['newspaper'])?$_SESSION['newspaper']:''; //checks and sets value
echo $newspaper; //outputs value
For more see session_start
http://php.net/manual/en/session.examples.basic.php
First you will need to start the session by using session_start() at the top of your page. Second, a session variable is written like this: $_SESSION['foo'].
I suggest you read these pages to get a better understanding of what's going on.
http://php.net/manual/en/reserved.variables.session.php
http://www.w3schools.com/php/php_sessions.asp
I'm trying to get a session variable to alternate between 0 and 1 on each page load.
So first time page loads
$_SESSION['turn'] = 0;
Second time
$_SESSION['turn'] = 1;
Third time
`$_SESSION['turn'] = 0;`
and so on.
Then I can call that variable later in the page.
I can't work out how to do this. I've tried a simple IF function but can't get it to work.
First the session must be started on any page wishing to make use of the session array. session_start()
Next you have to remember that initially the session variable you are using will not exist the first time you attempt to use it
So
<?php
session_start();
if ( !isset($_SESSION['turn']) ) {
// does not exist yet, so create with 0
// you may want to initialize it to 1, thats up to you
$_SESSION['turn'] = 0;
} else {
$_SESSION['turn'] = $_SESSION['turn'] == 0 ? 1 : 0;
}
Try this where the page is loaded.
$_SESSION['turn']=1-$_SESSION['turn'];
code:
<?php
session_start();
echo $_SESSION['turn'];
$_SESSION['turn']=1-$_SESSION['turn'];
?>
Edit : RiggsFolly !isset() is correct. mine misses it and it will give errors in log. and the first value is not 0
I have following problem, I am trying to set cookies without any success. setcookie(); function returns true so it looks like it setting cookie however when I am trying to access it on the same or following page I get error 'Undefined Index....'
<?
session_start();
ob_start();
echo setcookie("order",$_SESSION['cart'],time()+3600,'/',NULL);
//added to see if Cookie is set
echo "<br/>";
var_dump($_COOKIE);
exit();
if($_GET['paypal'] == 1){
header("Location: /paypal-express-checkout/process.php");
}else{
header("Location: /insert_order.php");
}
ob_end_flush();
exit();
?>
next page follows like this
<?php
session_start();
include_once("../includes/inc_config.php");
include_once("../order.php");
include_once("config.php");
include_once("paypal.class.php");
#region POST
if(!isset($_GET['token'])) //Post Data received from product list page.
{
//Mainly we need 4 variables from an item, Item Name, Item Price, Item Number and Item Quantity.
if(!isset($_COOKIE['order'])){
exit();
}
$paypal_data = '';
$ItemTotalPrice = 0;
$order = unserialize($_COOKIE['order']);
print_r($order);
exit;
You are setting the domain value to NULL. Try leaving the NULL away:
echo setcookie("order",$_SESSION['cart'],time()+3600,'/');
OR set it to your domain:
echo setcookie("order",$_SESSION['cart'],time()+3600,'/',".yourdomain.com");
I would var_dump or print_r the $_COOKIE variable before I make a decision that it's not getting passed through. Holding that thought once you setcookie something gets registered into the $_COOKIE variable for sure.
I agree with the statements above since you only can access $_COOKIE on the next refresh but there is another way to do it to make your form or page more interactive.
I would register the cookie and use a php page refresh (display a working... div while thats happening) then come back to the page and try to do what you originally tried doing. Very basic but pretty much straight forward.
I think this code should echo "first" in first usage and after refresh it should echo timestamp,but it will show first every time,where is my problem?
I set cookie permition on always.
if (isset($_SESSION['TestSession']))
{
echo ($_SESSION['TestSession']);
}
else
{
echo "first";
$_SESSION['TestSession'] = time();
}
Have you placed
session_start();
at the top of your page?
To start a session, first session_start() should be called. Otherwise $_SESSION won't be set, and you will initialize it every time.