I'm having trouble with inserting the values from this array. Here example:
$arr = json_decode($_POST['dynfields'], true);
//{"dynfields":{"dynfields[0][DescRepair]":"Desc repair","dynfields[0][NestParts]":"Parts","dynfields[0][EdPrice]":"10","dynfields[0][DateRepair]":"2015-07-20","dynfields[1][DescRepair]":"Desc repair","dynfields[1][NestParts]":"Parts","dynfields[1][EdPrice]":"5","dynfields[1][DateRepair]":"2015-07-20"}}
foreach ($arr as $key => $fieldArray ) {
foreach($fieldArray as $k => $v) {
echo $k . " - " . $v . "<br>"; // result: dynfields[0][DescRepair] - Desc repair
dynfields[0] [NestParts] - Parts
dynfields[0][EdPrice] - 10
dynfields[0][DateRepair] - 2015-07-20
dynfields[1][DescRepair] - Desc repair
dynfields[1][NestParts] - Parts
dynfields[1][EdPrice] - 5
dynfields[1][DateRepair] - 2015-07-20
}
//$query = mysqli_query($mysqli, "INSERT INTO repair (DescRepair, NestParts, EdPrice, DateRepair) VALUES ('?', '?', '?', '?')") or die(mysqli_error($mysqli));
}
This is my code, but I don't know how to insert the value in db. Can you give me any suggestions. Thanks.
I did not understand very well your code, but at first your json is bad, on post, this is an example of right json:
{
"dynfields": [
{
"DescRepair": "Desc repair",
"NestParts": "Parts",
"EdPrice": "10",
"DateRepair": "2015-07-20"
},
{
"DescRepair": "Desc repair",
"NestParts": "Parts",
"EdPrice": "5",
"DateRepair": "2015-07-20"
}
]
}
Then you can make a foreach with the dynfields data:
$myvar = json_decode($json,true);
$data = $myvar['dynfields'];
foreach(array_keys($data) as $index){
var_dump($data[$index]);
}
then you will get something like this (var_dump):
array (size=4)
'DescRepair' => string 'Desc repair' (length=11)
'NestParts' => string 'Parts' (length=5)
'EdPrice' => string '10' (length=2)
'DateRepair' => string '2015-07-20' (length=10)
array (size=4)
'DescRepair' => string 'Desc repair' (length=11)
'NestParts' => string 'Parts' (length=5)
'EdPrice' => string '5' (length=1)
'DateRepair' => string '2015-07-20' (length=10)
$query = mysqli_query($mysqli, "INSERT INTO repair (DescRepair, NestParts, EdPrice, DateRepair) VALUES ('?', '?', '?', '?')") or die(mysqli_error($mysqli))
relace each ? with {$arr['xxxxx']} Where xxxxx are your array keys
make sure to well-escape the variables to prevent SQL Injection
Hint: you can use PDO or prepared statements
Related
So I have been doing my research and no method seems to parse my file correctly. I have tried these two codes, my data is being inserted into sql however it is inserted 3 times with the first insertion being fine while the other 2 are blank. Here is my JSON file and code:
JSON:
[
{
"Comments": {
"Manufacturer": "--E",
"Model": "----- ----- ----",
"BIOSFamily": "---",
"BIOSDate": --/--/---8",
"SerialNumber": "---------"
}
},
{
"#ComputerSystem.v1-----------ystem": {
"/redfish/v1/Systems/1/": {
"AssetTag": " ",
"Bios": {
"#odata.id": "/redfish/v1/systems/1/bios/"
},
"BiosVersion": "U----------------)",
"Boot": {
"BootSourceOverrideMode": "-----y",
"BootSourceOverrideTarget": "None",
"BootSourceOverrideEnabled": "Disabled",
"BootSo-----------arget#Redfish.AllowableValues": [
"None",
"Cd",
"Hdd",
"Usb",
"Utilities",
"Diags",
"BiosSetup",
"Pxe",
"UefiShell"
]
Code:
<?php
$connect = mysqli_connect("reserve1",
"root", "","server_31");
$filename = "-----.json";
$data = file_get_contents($filename);
$array = json_decode($data, true);
foreach($array as $row)
{
$sql = "INSERT INTO servers (Model,
Manufacturer, BIOSFamily,
BIOSDate,
SerialNumber) VALUES
('".$row["Comments"]["Model"]."' ,
'".$row["Comments"]
["Manufacturer"]."',
'".$row["Comments"]
["BIOSFamily"]."','".$row["Comments"]
["BIOSDate"]."','".$row["Comments"]
["SerialNumber"]."')";
mysqli_query($connect, $sql);
}
echo "Data in";
?>
ERROR:" Notice: Undefined index: Comments "
other forloops i have tried are:
foreach($data as $Comments)
{
$sql =" INSERT INTO
'servers'('Manufacturer','Model',
'BIOSFamily','BIOSDate',
'SerialNumber'), VALUES('{$Comments-
>Manufacturer}', '{$Comments-
>Model}',
'{$Comments->BiosFamily}',
'{$Comments->BiosDate}',
'{$Comments-
>SerialNumber}')";
}
ERROR:" Notice: Trying to get property of non-object in"
To reiterate: the first method does get my info onto sql but does so 3 times with the last 2 entries being blank. The second method does not insert anything into my table.
EDIT:
so i tried vardump, using the file itself all i got was NULL, copy and pasting the contents and labeling it $json= ' content ' in the script i get..
C:\Users\Administrator\Desktop\Reserve1\newtry\NEWJSONP.php:16:
array (size=1)
0 =>
object(stdClass)[1]
public 'Comments' =>
object(stdClass)[2]
public 'Manufacturer' => string 'HPE' (length=3)
public 'Model' => string '-------------' (length=20)
public 'BIOSFamily' => string '---' (length=3)
public 'BIOSDate' => string '--/--/----' (length=10)
public 'SerialNumber' => string '-------' (length=10)
C:\Users\Administrator\Desktop\Reserve1\newtry\NEWJSONP.php:17:
array (size=1)
0 =>
array (size=1)
'Comments' =>
array (size=5)
'Manufacturer' => string '---' (length=3)
'Model' => string '------ ----------' (length=20)
'BIOSFamily' => string '---' (length=3)
'BIOSDate' => string '--/--/----' (length=10)
'SerialNumber' => string '-------' (length=10)
Simply index in your foreach loop the first item since $array object maintains Comments only in first position. See 0 index from var_dump output:
array (
0 =>
array (
'Comments' =>
array (
'Manufacturer' => '--E',
'Model' => '----- ----- ----',
'BIOSFamily' => '---',
'BIOSDate' => ' --/--/-- - 8 ',
'SerialNumber' => '---------',
),
),
1 =>
array (
'#ComputerSystem.v1-----------ystem' =>
...
Therefore, iterate through the Comments array and use parameterization for readability:
$connect = new mysqli($servername, $username, $password, $dbname);
// PREPARED STATEMENT
$sql = "INSERT INTO servers (Model, Manufacturer, BIOSFamily, BIOSDate, SerialNumber)
VALUES(?, ?, ?, ?, ?)";
// INDEX FIRST ITEM AT 0
foreach($array[0] as $row) {
$stmt = $connect->prepare($sql);
// BIND PARAMETERS (NO COMMENTS INDEX)
$stmt->bind_param("sssss", $row["Model"],
$row["Manufacturer"],
$row["BIOSFamily"],
$row["BIOSDate"],
$row["SerialNumber"]);
// EXECUTE STATEMENT
$result = $stmt->execute();
}
To explain the scenario:
I have this table in MySQL DB
+-------------------------------------------------------------------------+
| message_id | client_id | admin_id | message | date_posted | read_status |
+-------------------------------------------------------------------------+
I am selecting all the messages and grouping them in a 2D Array for the same client so that the result migh look like
$messages = array(
"4" => array ("338", "4", "1", "message1", "20170904 120803", "0"),
"5" => array ("339", "5", "1", "message2", "20170904 120807","0")
);
The result I'm getting is similar but each value in the array is duplicated
array (size=12)
'message_id' => string '22' (length=2)
0 => string '22' (length=2)
'client_id' => string '14' (length=2)
1 => string '14' (length=2)
'admin_id' => string '1' (length=1)
2 => string '1' (length=1)
'message' => string 'hii I'm new to this' (length=19)
3 => string 'hii I'm new to this' (length=19)
'date_posted' => string '2017-04-22 17:17:13' (length=19)
4 => string '2017-04-22 17:17:13' (length=19)
'read_status' => string '0' (length=1)
5 => string '0' (length=1)
This is my query
$grouped_messages = array();
foreach ($connect->query("SELECT DISTINCT * FROM request ORDER BY client_id") as $row) {
var_dump($row);
$client_id = $row['client_id'];
if (!isset($grouped_messages[$client_id])) {
$grouped_messages[$client_id] = array();
}
$grouped_messages[$client_id][] = $row;
}
foreach ($grouped_messages as $client_id => $client_messages) {
echo '<div>';
echo '<p>Messages for client #' . $client_id . '</p>';
foreach ($client_messages as $message) {
foreach($message as $column) {
echo $column;
}
}
echo '</div>';
}
Any Ideas on why that is happening?
PS The same client can have multiple messages meaning multiple rows in this table that's what the code it puts all those messages from the same client into the associative array!
Fetching both numeric and text keys is a default behaviour of PDO fetch.
You can change it, in your case this should be done by setting attribute PDO::ATTR_DEFAULT_FETCH_MODE to PDO::FETCH_ASSOC:
$connect->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
Or you can do it when you instantiate new PDO object.
More modes here.
i try show data using PDO. But i get Error "Trying to get property of non-object".
i have a simple script.
public function tampilUserId($user_id)
{
$sql = "SELECT $this->user.*, $this->provinsi.*
FROM $this->user
INNER JOIN $this->provinsi
ON $this->user.provinsi_id=$this->provinsi.provinsi_id
WHERE user_id=:user_id";
$stmt = db::prepare($sql);
$stmt->bindParam(':user_id', $user_id);
$stmt->execute();
return $stmt->fetchAll(PDO::FETCH_OBJ);
}
And this
echo $results->email_user;
print_r($result);
result
Notice: Trying to get property of non-object in C:\xampp\htdocs\laporan_app\user_views\profile.php on line 35
stdClass Object ( [user_id] => 45 [nama_dpn_user] => [nama_blkng_user] => [username_user] => adi [password_user] => $2y$10$p/8gF5BcQSooQUKRlEAiPuOSy4o1RMeXA5Ul8GTZNYZi/4wcOP3Ja [email_user] => adi#gmail.com [level_user] => mahasiswa [img_user] => [_dir_img_user] => [_size_img_user] => [provinsi_id] => [universitas_id] => )
And i try this script
echo $results['email_user'];
print_r($results);
result
Notice: Undefined index: email_user in C:\xampp\htdocs\laporan_app\user_views\profile.php on line 35
stdClass Object ( [user_id] => 45 [nama_dpn_user] => [nama_blkng_user] => [username_user] => adi [password_user] => $2y$10$p/8gF5BcQSooQUKRlEAiPuOSy4o1RMeXA5Ul8GTZNYZi/4wcOP3Ja [email_user] => adi#gmail.com [level_user] => mahasiswa [img_user] => [_dir_img_user] => [_size_img_user] => [provinsi_id] => [universitas_id] => )
Please help me, thanks before.
Merdeka! :D
In case your SQL query not contain any error its mean data was successfully pulled from database. So in your tampilUserId($user_id) function, its returning set of array from $stmt->fetchAll(PDO::FETCH_OBJ). Like below:
/* Sample from Sakila database */
array (size=603)
0 =>
object(stdClass)[11]
public 'address_id' => string '1' (length=1)
public 'address' => string '47 MySakila Drive' (length=17)
public 'address2' => null
public 'district' => string 'Alberta' (length=7)
public 'city_id' => string '300' (length=3)
public 'postal_code' => string '' (length=0)
public 'phone' => string '' (length=0)
public 'last_update' => string '2014-09-25 22:30:27' (length=19)
1 =>
object(stdClass)[12]
public 'address_id' => string '2' (length=1)
public 'address' => string '28 MySQL Boulevard' (length=18)
public 'address2' => null
public 'district' => string 'QLD' (length=3)
public 'city_id' => string '576' (length=3)
public 'postal_code' => string '' (length=0)
public 'phone' => string '' (length=0)
public 'last_update' => string '2014-09-25 22:30:09' (length=19)
more elements...
All you need to do is looping your function returned value first whereever you call it. Short example from your case:
//I dont know you put it under class or not.
$data = $YourClass->tampilUserId($user_id);
foreach ($data as $item) {
echo $item->email_user);
}
Note:
You can manually echoing your data without looping and its bad practice because you dont know the length of the array. So this is just gusessing. Taken from your case it would be.
$data = $YourClass->tampilUserId($user_id);
$data[0]->email_user; //If an object
$data[0]['email_user']; //If an array
Update:
There is suspicious thing on your query. The variable $this->user is not look like column name to me(unsure) If yes, so you have small mistake on your query. Secondly, as you said the result is null its mean something wrong or data you search not exist. I put this sample running inner join query.
Example:
Lets said i had 2 table. 1st is address and 2nd is city
|address table|
|city table|
So your sql query for joining table(from image above) should be:
SELECT adr.address_id, adr.address, adr.district, adr.city_id, c.city_id,
c.city FROM address AS adr INNER JOIN city AS c ON adr.city_id = c.city_id
WHERE c.city_id = 300 #using city id
Output:
Bring it to PHP
<?php
$pdo= new PDO('mysql:dbname=sakila;host=localhost:3306', 'user', password');
$city_id = 300; // manual set
$sql = 'SELECT adr.address_id, adr.address, adr.district, adr.city_id,
c.city_id, c.city FROM address AS adr INNER JOIN city AS c ON
adr.city_id = c.city_id WHERE c.city_id = :city_id';
$stmt = $_this->db->prepare($sql);
$stmt->bindParam(':city_id', $city_id);
$stmt->execute();
$data = $stmt->fetchAll(PDO::FETCH_OBJ);
?>
var_dump($data) giving a result:
Great, as it come as (object(stdClass)) so we can loop it through the array & then accessing it using -> sign.
<?php
$i = 1;
foreach ($data as $d) {
echo '<dl>';
echo '<dt>Adress '.$i++.':</dt>';
echo '<li>Address id: '.$d->address_id.'</li>';
echo '<li>Address: '.$d->address.'</li>';
echo '<li>District: '.$d->district.'</li>';
echo '<li>City id: '.$d->city_id.'</li>';
echo '<li>City name: '.$d->city.'</li>';
echo '</dl>';
}
?>
Result in browser:
Hope this will resolve your problem.
I've spent hours looking at this and just don't see the mistake.
6 columns, 6 ?'s, 6 array elements.
The insert works fine the update is the problem!
Btw. is this a good way to deal with insert on duplicate update?
$userId = 13;
foreach($tableKey as $table=>$value){
foreach($value as $key=>$val){
$array_of_parameters[$key] = $val;
$fields[] = sprintf("%s=?", $key);
}
$field_list = join(', ', $fields);
try{
$update = "UPDATE `$table` SET $field_list WHERE id=$userId";
$stmt = $db->prepare($update);
echo $stmt->debugDumpParams();
$stmt->execute($array_of_parameters);// here's where I get error!
if($stmt->rowCount() == 0){
$insert = "INSERT INTO `$table` (".implode(',', array_keys($value)).") VALUES (:".implode(',:', array_keys($value)).")";
$stmt = $db->prepare($insert);
echo $stmt->debugDumpParams();
$stmt->execute($array_of_parameters);
}
}
}
Here's the debug and $array_of_parameters
array
'user' => string 'somebody' (length=3)
'first' => string 'some' (length=7)
'last' => string 'body' (length=4)
'zoneId' => string 'zone' (length=4)
'email' => string 'tst#me.net' (length=21)
'head' => string '1' (length=1)
SQL: [80] UPDATE `user` SET user=?, first=?, last=?, zoneId=?, email=?, head=? WHERE id=13 Params: 0
And of course the error
Warning: PDOStatement::execute() [pdostatement.execute]: SQLSTATE[HY093]: Invalid parameter number: parameter was not defined
Try calling array_values on $array_of_parameters before executing the statement.
For unnamed parameters, execute probably expects numeric (default) keys in your parameters array. Populate $array_of_parameters in order without keys, then try it.
My result set come from a group/count query:
SELECT m.type, COUNT(m.type)
FROM sent_message m
WHERE m.user_id = :user_id
AND (m.sent_at >= :start_date OR m.sent_at <= :end_date)
GROUP BY m.type
And it's in the form of
an array nested into another array:
array (size=2)
0 =>
array (size=2)
'type' => string 'sms' (length=3)
'count' => string '1' (length=1)
1 =>
array (size=2)
'type' => string 'email' (length=5)
'count' => string '9' (length=1)
Is there any way to easily check if a given type index exists without looping? For avoiding this:
$resultSet = $repository->getAllCount(); // Returns the nested array
$viewBag = array('sent_sms_count' => 0, 'sent_email_count' => 0); // Init
foreach($resultSet as $result) :
if('sms' == strtolower($result['type'])
$viewBag['sent_sms_count'] = $result['count'];
if('email' == strtolower($result['type'])
$viewBag['sent_email_count'] = $result['count'];
endforeach;
There's no way I'm aware of without looping. But you can re-index the SQL results into a format you like:
foreach ($resultSet as $result) {
$viewBag['sent_' . strtolower($result['type']) . '_count'] = $result['count'];
}