Extracting several elements using php - php

Question

I have these two tables in my database :
table_A: table_B:
id user id user
1 Mike 1 Mike
2 Dan 2 Dan
3 Tom 3 Tom
4 Lina 4 Lina
5 Cynthia
6 Sam
And i'm using this SQL query, to detect which users in table_B do not exist in table_A, and select those users (not existing in table A) ids:
SELECT table_B.id FROM table_B WHERE table_B.id NOT IN (SELECT table_A.id FROM table_A);
And i'm using this php script to put the ids in a variable $not:
$sql=" SELECT table_B.id FROM table_B WHERE table_B.id NOT IN (SELECT table_A.id FROM table_A)";
$result = mysqli_query($con,$sql);
if (!$result) {
printf("Error: %s\n", mysqli_error($con));
exit();
}
while($row = mysqli_fetch_array($result)){
$not=$row[0];
}
Now if i want to extract 2 elements with my sql query:
SELECT table_B.id, table_B.name FROM table_B WHERE table_B.id NOT IN (SELECT table_A.id FROM table_A);
How can i place both, each in a variable using the above script, so i'll be able to insert each element in a different table in the database?

Answer 1

You can put the values in a multidimensional array.
$not = array();
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
$not[] = array(
"id" => $row['id'],
"name" => $row['name']
);
}
echo $not[0]['id']; //Returns 5
echo $not[0]['name']; //Returns Cynthia
echo $not[1]['id']; //Returns 6
echo $not[1]['name']; //Returns Sam

Answer 2

in your query define table_B.id as user_id and table_B.name as user
then in your php use mysqli_fetch_object like this
while($row = mysqli_fetch_object($result)){
$not= $row;
//or if you want to store all the results use $not[] = $row; and define $not as array
}