Undefined variable while fetching data from mysqli - php

Question

I'm new to php n I'm trying to make a phone to timezone converter.
I'm getting the error undefined variable '$result' on line 49
How do I resolve it.
Also if you can find out any other mistakes I've made
Please chck for errors I'm making
Phone number:
<button type="submit" name="submit" action="submit">
Submit
</button>
</form>
<?php
$servername = "127.0.0.1";
$username = "root";
$password = "";
$ccode=$_POST["phone"];
// Create connection
$db = new mysqli($servername, $username, $password);
// Check connection
if ($db->connect_error) {
die("Connection failed: " . $db->connect_error);
}
$pattern = '/^\(?[\d]{1,4}\)?( |-)?/';
if(preg_match($pattern, $ccode, $matches))
{
$code = $matches[0];
} else $code = substr($ccode, 0, 4);
$q = "SELECT nicename FROM country.country WHERE phonecode=$code";
if($query = $db->query($q))
{
$record = $query->fetch_assoc();
} else echo "<br/>NO RECORD";
echo '<pre>';print_r($record);
if (empty($_POST["phone"]))
{
echo "<p>Please write a Phone Number!</p>";
}
$abb = "SELECT zone_id FROM zone INNER JOIN country on country.country_code = zone.country_code
WHERE country.country_name = " . $record['nicename'];
if($query = $db->query($abb))
{
$result = $query->fetch_assoc();
} else echo "<br/>NO RECORD";
echo '<pre>';print_r($result);
?>
</body>
Thanks for the help!

Answer 1

I believe this way it will works. I'm not sure about $code, if he contains the right information, you can check that by echo'ing the $code.
if(preg_match($pattern, $ccode, $matches))
{
$code = $matches[0];
} else { $code = substr($ccode, 0, 4); }
$q = "SELECT nicename FROM country WHERE phonecode=$code";
if($query = $db->query($q))
{
$record = $query->fetch_assoc();
echo '<pre>';
print_r($record);
} else { echo "<br/>NO RECORD"; }
$abb = "SELECT zone_id FROM zone INNER JOIN country on country.country_code = zone.country_code
WHERE country.country_name = '" . $record['nicename'] . "'";
if($query = $db->query($abb))
{
$result = $query->fetch_assoc();
echo '<pre>';
print_r($result);
//Here $result will exist!
} else { echo "<br/>NO RECORD"; }
// You had your $result here, and here, the result may not exist,
// depending if the query succeeded or not.
// Same counts for the query above.
There were 2 problems as far as I can tell.
1 was that you tried to print $record, while $record may not have existed, and the same counts for $result.
2 was the zone-query, if you check if a column/field equals a certain string, then make sure the string has quotes around itself. So country_name='something'. You didn't have these quotes around $record['nicename'], so whatever came out of $record['nicename'], he thought it was a column/field, but not a value to check upon.