MySQL Math on "join" function - php

Not too sure how to explain this, but, basically I have two tables, and I need to do some math on their values. I am having issues with anything other than addition (which it does automatically).
This is the MySQL statement that I am using.
select snippet_id, count(snippet_id) as cnt
from snippets_likes join snippets_engagement on snippet_id = snippets_engagement.snip_id
group by snippet_id
order by cnt desc
This statements pulls the total number of likes + engagements.
However, I want to have it equal likes + ( engagements/1000 ).
Table construction
CREATE TABLE `IOTunes`.`snippets_engagement` (
`ID` int(10) unsigned NOT NULL AUTO_INCREMENT,
`snip_id` int(10) unsigned NOT NULL DEFAULT '0',
`artist_id` int(10) unsigned NOT NULL DEFAULT '0',
`snip_timestamp` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`engagement_type` int(10) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=6694 DEFAULT CHARSET=latin1;
CREATE TABLE `IOTunes`.`snippets_likes` (
`ID` int(10) unsigned NOT NULL AUTO_INCREMENT,
`snippet_id` int(10) unsigned NOT NULL DEFAULT '0',
`artist_id` int(10) unsigned NOT NULL DEFAULT '0',
`snippet_like` int(10) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=197 DEFAULT CHARSET=latin1;
I have tried so many different formulas, but, cannot get this to work. Any pointers?

Try this statement:
SELECT snippet_id, SUM(cnt) AS cnt
FROM (
SELECT snippet_id, COUNT(1) AS cnt
FROM snippets_likes
GROUP BY snippet_id
UNION
SELECT snippet_id, COUNT(1)/1000 AS cnt
FROM snippets_engagement
GROUP BY snippet_id
) AS subQ
GROUP BY snippet_id
ORDER BY cnt DESC
or if you insist on a join...
select sl.snippet_id, count(DISTINCT sl.ID) + count(DISTINCT se.ID)/1000 as cnt
from snippets_likes AS sl join snippets_engagement AS se
on sl.snippet_id = se.snip_id
group by snippet_id
order by cnt desc
I wouldn't recommend the join though, you'll only get values for "snippets" that have at least one "like" and one "engagement".

Related

MySQL Select rows where the user has not voted yet (contest app)

I have a photo contest app where users can vote. I would like to select all of the contests where the logged in user has not voted yet.
So I have two tables.
The "contest" table :
CREATE TABLE `contest` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`user_id` int(11) NOT NULL,
`category_id` int(11) NOT NULL,
`title` varchar(255) NOT NULL,
`desc` text NOT NULL,
`created_date` datetime NOT NULL,
`started_date` datetime NOT NULL,
`nb_user_min` int(11) NOT NULL,
`nb_photo_max` int(11) NOT NULL,
`nb_photo_per_user` int(11) NOT NULL,
`duration` int(11) DEFAULT NULL,
`status` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
The "contest_vote" table :
CREATE TABLE `contest_vote` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`pic_id` int(11) DEFAULT NULL,
`contest_id` int(11) DEFAULT NULL,
`user_id` int(11) DEFAULT NULL,
`date` datetime DEFAULT NULL,
`ip` varchar(100) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
So to be clear, I want to get the number (or the list) of contests where the user has not voted yet. So I have tried with a LEFT JOIN but it doesn't return the good set of result. Here it the query I have until now :
SELECT DISTINCT c.id, c.title, cv.user_id
FROM contest c
LEFT JOIN contest_vote cv
ON cv.contest_id = c.id AND cv.user_id != ?
GROUP BY contest_id
("?" represents the user_id parameter).
Can you help me to solve this?
This is pretty simple do with a subquery. Just grab all contest without where user is voted like this:
SELECT DISTINCT c.id, c.title
FROM contest c
WHERE c.id NOT IN (SELECT DISTINCT cv.contest_id FROM contest_vote cv WHERE cv.user_id = ?)
Try this one :
SELECT DISTINCT c.id, c.title, cv.user_id
FROM contest c
LEFT JOIN contest_vote cv ON cv.contest_id = c.id AND cv.user_id != ? WHERE c.user_id = ?
GROUP BY contest_id

i want to use left and inner join in 3 tables in mysql?

these are my tables. first one is appusers table.
CREATE TABLE IF NOT EXISTS `appusers` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`email` varchar(50) NOT NULL,
`is_active` tinyint(2) NOT NULL DEFAULT '0',
`zip` varchar(20) NOT NULL,
`city` text NOT NULL,
`country` text NOT NULL,
`created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=23 ;
second table is stickeruses table.
CREATE TABLE IF NOT EXISTS `stickeruses` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`user_id` int(11) NOT NULL,
`sticker_id` int(11) NOT NULL,
`count` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=24 ;
Third table is Devices
CREATE TABLE IF NOT EXISTS `devices` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`user_id` int(11) NOT NULL,
`regid` varchar(300) NOT NULL,
`imei` varchar(50) NOT NULL,
`device_type` tinyint(2) NOT NULL,
`notification` tinyint(2) NOT NULL DEFAULT '1',
`is_active` tinyint(2) NOT NULL DEFAULT '0',
`activationcode` int(6) NOT NULL,
`created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=28 ;
I Want to find the Sum(stickeruses.count) and COUNT(devices.id) for all appusers.
Here is my query.
SELECT `Appuser`.`id`, `Appuser`.`email`, `Appuser`.`country`, `Appuser`.`created`,
`Appuser`.`is_active`, SUM(`Stickeruse`.`count`) AS total, COUNT(`Device`.`id`)
AS tdevice
FROM `stickerapp`.`appusers` AS `Appuser`
LEFT JOIN `stickerapp`.`stickeruses` AS `Stickeruse`
ON (`Stickeruse`.`user_id`=`Appuser`.`id`)
INNER JOIN `stickerapp`.`devices` AS `Device`
ON (`Device`.`user_id`=`Appuser`.`id`)
WHERE `Appuser`.`is_active` = 1
GROUP BY `Appuser`.`id`
LIMIT 10
When I am applying each join separately the results are right, but I want to combine both joins. And when I am doing it then results are wrong. please help.
When mixing JOIN and LEFT JOIN it is a good idea to use parentheses to make it clear what your intent is.
I don't know what you need, but these syntaxes might give you different results:
FROM a LEFT JOIN ( b JOIN c ON b..c.. ) bc ON a..bc..
FROM ( a LEFT JOIN b ON a..b.. ) ab JOIN c ON ab..c..
Also, you can rearrange them do FROM a JOIN c LEFT JOIN b (plus parentheses) or any of several other arrangements. Granted, some pairs rearrangements are equivalent.
Also, beware; aggregates (such as SUM()) get inflated values when JOINing. Think of it this way: first the JOINs get all appropriate combinations of rows from the tables, then the SUM adds them up. With that in mind, see if this works better:
SELECT a.`id`, a.`email`, a.`country`, a.`created`, a.`is_active`,
( SELECT SUM(`count`)
FROM stickerapp.stickeruses
WHERE user_id = a.id
) AS total,
( SELECT COUNT(*)
FROM stickerapp.devices
WHERE user_id = a.id
) AS tdevice
FROM stickerapp.`appusers` AS a
WHERE a.`is_active` = 1
GROUP BY a.`id`
LIMIT 10

Improve speed of MySQL query [closed]

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
EDIT:
I reworked the query as follows:
SELECT
a.title, count(*),at.search_code
FROM
`qitz3_attributes_type` at
left join
qitz3_attributes a
on
a.attribute_type_id = at.id
left join
qitz3_attributes_property ap
on
ap.attribute_id = a.id
left join
qitz3_helloworld h
on
h.id = ap.property_id
where
at.id in (1,2,8,9,11)
and
a.search_filter = 1
and
h.area=506
and
h.expiry_date >= '2013-02-20 13:28:04'
group by
a.title
order by search_code
This seems much faster but I am still getting a using temporary and using filesort on the explain...
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE at range PRIMARY PRIMARY 4 NULL 5 Using where; Using temporary; Using filesort
1 SIMPLE a ref PRIMARY,Attribute type ID,Search filter,Attribute ... Attribute type ID 4 password.at.id 6 Using where
1 SIMPLE ap ref Property ID,Attribute ID,Attribute Property Attribute Property 4 password.a.id 142 Using where; Using index
1 SIMPLE h eq_ref PRIMARY,Area indexes,Expiry date PRIMARY 4 password.ap.property_id 1 Using where
ENDEDIT
I am working on a search component for a site I am developing and while it is all working there are a couple of queries that I would like to see running a touch faster.
In order to populate a set of search filters (display the count of the number of properties that have each facility or are of a particular type) I am using the following two queries. The first will get a list of IDs that I then plug into the second query as follows:
Based on the following info can anyone suggest a more efficient way to do this? I would really like to speed the first query up as it seems a little slow compared to the others.
Is 150ms actually that slow? 15ms would be better...
Thanks,
Adam
Query 1 (takes around 150ms):
SELECT h.id, h.parent_id, h.level, h.title as property_title, h.area, h.region, h.department, h.city,
LEFT(h.description, 250) as description, h.thumbnail, h.occupancy, h.swimming, g.path, (single_bedrooms + double_bedrooms + triple_bedrooms + quad_bedrooms + twin_bedrooms) as bedrooms, c.title as location_title, ( select min(tariff)
from qitz3_tariffs
where id = h.id ) as price, e.title as tariff_based_on, f.title as base_currency, a.title as property_type, a2.title as accommodation_type, ( select count(*)
from qitz3_reviews
where property_id = h.id
group by h.id ) as reviews
FROM qitz3_classifications c
LEFT JOIN qitz3_helloworld h
on c.id = h.area
LEFT JOIN qitz3_attributes_property ap
ON ap.property_id = h.id
LEFT JOIN qitz3_attributes_type at
ON at.id = ap.attribute_id
LEFT JOIN qitz3_attributes a
ON a.id = ap.attribute_id
LEFT JOIN qitz3_attributes_property ap2
ON ap2.property_id = h.id
LEFT JOIN qitz3_attributes_type at2
ON at2.id = ap2.attribute_id
LEFT JOIN qitz3_attributes a2
ON a2.id = ap2.attribute_id
LEFT JOIN qitz3_attributes e
ON e.id = h.tariff_based_on
LEFT JOIN qitz3_attributes f
ON f.id = h.base_currency
LEFT JOIN qitz3_classifications g
ON g.id = h.city
WHERE a.attribute_type_id = 1
AND a2.attribute_type_id = 2
AND c.id = 506
AND h.expiry_date >= '2013-02-20 12:05:13'
AND h.id > 1
Explain:
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY c const PRIMARY PRIMARY 4 const 1
1 PRIMARY h ref PRIMARY,Area indexes,Expiry date Area indexes 4 const 615 Using where
1 PRIMARY ap ref Property ID,Attribute ID Property ID 4 password.h.id 21 Using where
1 PRIMARY at eq_ref PRIMARY PRIMARY 4 password.ap.attribute_id 1 Using index
1 PRIMARY a eq_ref PRIMARY,Attribute type ID PRIMARY 4 password.ap.attribute_id 1 Using where
1 PRIMARY ap2 ref Property ID,Attribute ID Property ID 4 password.ap.property_id 21 Using where
1 PRIMARY at2 eq_ref PRIMARY PRIMARY 4 password.ap2.attribute_id 1 Using index
1 PRIMARY a2 eq_ref PRIMARY,Attribute type ID PRIMARY 4 password.ap2.attribute_id 1 Using where
1 PRIMARY e eq_ref PRIMARY PRIMARY 4 password.h.tariff_based_on 1
1 PRIMARY f eq_ref PRIMARY PRIMARY 4 password.h.base_currency 1
1 PRIMARY g eq_ref PRIMARY PRIMARY 4 password.h.city 1
3 DEPENDENT SUBQUERY qitz3_reviews ref Property ID Property ID 4 password.h.id 1 Using index; Using temporary; Using filesort
2 DEPENDENT SUBQUERY qitz3_tariffs ref Property ID Property ID 4 password.h.id 2
Query 2 (takes around 30ms):
SELECT a.id,count(attribute_id) as count, a.title AS attribute, a.published, at.title as facility_type, at.search_code
FROM qitz3_attributes AS a
LEFT JOIN qitz3_attributes_type at
on at.id = a.attribute_type_id
LEFT JOIN qitz3_attributes_property ap
on ap.attribute_id = a.id
WHERE search_filter = 1
AND a.published = 1
AND property_id in (152843,103180,152845,4628,5653,3865,107553,155945,106029,107575,149052,837,104264,98635,98636,98637,98638,3667,106838,3672,157278,155743,157791,157792,151153,151155,100725,106109,157569,157576,107145,150666,103310,5780,3480,102041,154016,3490,154018,932,153518,151991,154041,154042,4288,5832,149451,157646,102094,148444,153822,157407,153839,151536,157393,157395,157428,157429,102236,104770,157378,157380,157381,157382,157383,157654,104768,103746,153683,150175,4618,101050,104942,157229,157230,98515,104771,104944,3612,148721,104212,5307,3432,156676,102706,404,5518,156359,5252,102697,5271,98979,101827,149524,102676,107551,5685,101736,156538,152703,4730,151881,95838,3759,149769,5269,98429,153729,5233,703,5579,98943,157433,3157,155661,107347,147545,147547,5216,106345,156533,93833,158091,96403,3491,968,158195,158196,157580,104148,3030,94686,154725,150582,103027,99062,102462,4384,5634,153874,157974,101669,47,105285,102481,102234,5749,156793,153748,96404,151467,154292,147645,97471,100551,102090,4841,3563,155643,4656,98424,157243,150601,157415,4701,102283,100719,100738,5643,98425,98972,103261,531,3105,98108,150592,5719,150616,157532,3974,3212,157581,97469,97470,149183,157638,149730,102114,156395,153621,102560,102913,94684,5609,157578,98423,98971,102151,146734,150585,104287,155296,104956,94592,102433,147575,156325,106344,101766,107058,106560,103026,157848,98973,4303,5620,149767,150563,4407,104268,97876,156784,156786,149922,701,154317,153821,102480,348,102778,102779,102780,102781,102479,352,103025,98677,5254,98697,3995,156322,100305,98532,3833,5374,150172,151435,102368,102380,157228,103171,147740,152870,103579,3870,104037,103016,4995,105104,157605,5811,955,147643,156648,107802,101502,94685,3569,148755,150293,4122,157013,157297,98676,156794,102848,157635,157640,95717,98980,102764,102777,102782,36,101765,154373,149829,154955,107683,158176,102557,157552,103163,5760,104627,153561,266,151335,151176,147620,147379,3085,155760,106339,151424,106759,5145,104990,97877,155495,5241,156407,156625,3236,152782,96066,147617,3860,4614,3497,147883,158207,102985,104622,101816,157275,149037,4792,149226,3496,101825,102538,150571,105015,97874,157391,158192,102562,155032,5383,102558,104194,156740,101446,147615,5815,107081,155992,97473,148817,945,101751,158074,4249,101792,4532,152828,104316,157319,156071,157508,157510,148836,4745,153823,157942,3859,157442,100017,102555,147629,149272,157845,151256,101481,154735,154737,157652,106232,97991,4660,3309,157597,407,157658,154152,157374,153385,148037,158214,100452)
GROUP BY a.id
This query gives a count of the number of properties with each attribute (e.g. Golf, Air conditioning, property type etc). The good thing about this is that only attributes are shown that have properties. So as the user drills down attributes with no properties are not shown. This is basically down to the first query where I get a list of the properties matching a particular set of attributes.
The tables are as follows:
--
-- Table structure for table qitz3_attributes
CREATE TABLE IF NOT EXISTS `qitz3_attributes` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`attribute_type_id` int(11) NOT NULL,
`title` varchar(75) NOT NULL,
`ordering` int(11) NOT NULL,
`state` tinyint(4) NOT NULL DEFAULT '1',
`published` int(11) NOT NULL,
`search_filter` bit(1) NOT NULL,
`language_code` varchar(6) NOT NULL DEFAULT 'en-GB',
PRIMARY KEY (`id`),
KEY `Attribute type ID` (`attribute_type_id`),
KEY `Search filter` (`search_filter`),
KEY `Published` (`published`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1522 ;
--
-- Table structure for table qitz3_attributes_property
CREATE TABLE IF NOT EXISTS `qitz3_attributes_property` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`property_id` int(11) NOT NULL,
`attribute_id` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `Property ID` (`property_id`),
KEY `Attribute ID` (`attribute_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=66261 ;
--
-- Table structure for table qitz3_attributes_type
CREATE TABLE IF NOT EXISTS `qitz3_attributes_type` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(75) NOT NULL,
`language_code` varchar(6) NOT NULL,
`field_name` varchar(25) NOT NULL,
`search_code` varchar(25) NOT NULL,
`state` int(11) NOT NULL DEFAULT '1',
`published` int(11) NOT NULL DEFAULT '1',
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=34 ;
--
-- Table structure for table qitz3_classifications
CREATE TABLE IF NOT EXISTS `qitz3_classifications` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`parent_id` int(10) unsigned NOT NULL DEFAULT '0',
`lft` int(11) NOT NULL DEFAULT '0',
`rgt` int(11) NOT NULL DEFAULT '0',
`level` int(10) unsigned NOT NULL DEFAULT '0',
`title` varchar(255) NOT NULL,
`description` text NOT NULL,
`path` varchar(255) NOT NULL DEFAULT '',
`alias` varchar(255) NOT NULL,
`access` tinyint(3) unsigned NOT NULL DEFAULT '0',
`published` int(11) NOT NULL,
`longitude` float(10,6) NOT NULL,
`latitude` float(10,6) NOT NULL,
PRIMARY KEY (`id`),
KEY `idx_left_right` (`lft`,`rgt`),
KEY `Alias index` (`alias`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=158052 ;
--
-- Table structure for table qitz3_helloworld (Property table)
CREATE TABLE IF NOT EXISTS `qitz3_helloworld` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`parent_id` int(10) NOT NULL DEFAULT '0',
`lft` int(11) NOT NULL DEFAULT '0',
`rgt` int(11) NOT NULL DEFAULT '0',
`level` int(10) unsigned NOT NULL,
`alias` varchar(250) NOT NULL DEFAULT '',
`access` tinyint(3) unsigned NOT NULL DEFAULT '0',
`path` varchar(255) NOT NULL DEFAULT '',
`title` varchar(120) NOT NULL,
`area` int(11) NOT NULL DEFAULT '0',
`region` int(11) NOT NULL DEFAULT '0',
`department` int(11) NOT NULL DEFAULT '0',
`city` int(11) NOT NULL DEFAULT '0',
`params` text NOT NULL,
`created_by` int(10) NOT NULL DEFAULT '0',
`created_on` datetime NOT NULL,
`modified` datetime DEFAULT NULL,
`expiry_date` date DEFAULT NULL,
`availability_last_updated_on` datetime DEFAULT NULL,
`modified_by` int(11) DEFAULT NULL,
`lang` varchar(5) NOT NULL DEFAULT 'en-GB',
`description` mediumtext NOT NULL COMMENT 'The summary and description for this accommodation',
`internal_facilities_other` varchar(1000) NOT NULL,
`external_facilities_other` varchar(1000) NOT NULL,
`activities_other` varchar(5000) NOT NULL,
`location_details` varchar(5000) NOT NULL,
`getting_there` varchar(5000) NOT NULL,
`thumbnail` varchar(150) NOT NULL,
`occupancy` int(11) DEFAULT NULL,
`single_bedrooms` int(11) NOT NULL,
`double_bedrooms` int(11) NOT NULL,
`triple_bedrooms` int(11) DEFAULT NULL,
`quad_bedrooms` int(11) DEFAULT NULL,
`twin_bedrooms` int(11) DEFAULT NULL,
`childrens_beds` int(11) DEFAULT NULL,
`cots` int(11) DEFAULT NULL,
`extra_beds` int(11) DEFAULT NULL,
`bathrooms` int(11) NOT NULL,
`toilets` int(11) DEFAULT NULL,
`swimming` int(11) NOT NULL,
`latitude` decimal(10,7) DEFAULT NULL,
`longitude` decimal(10,7) DEFAULT NULL,
`nearest_town` varchar(50) DEFAULT NULL,
`distance_to_coast` int(11) DEFAULT NULL,
`additional_price_notes` varchar(3000) DEFAULT NULL,
`base_currency` int(11) DEFAULT NULL,
`tariff_based_on` int(11) DEFAULT NULL,
`linen_costs` varchar(250) DEFAULT NULL,
`changeover_day` int(11) DEFAULT NULL,
`published` tinyint(4) NOT NULL DEFAULT '0',
`video` tinyint(4) NOT NULL DEFAULT '0',
PRIMARY KEY (`id`),
KEY `idx_left_right` (`lft`,`rgt`),
KEY `Area indexes` (`area`,`region`,`department`),
KEY `Expiry date` (`expiry_date`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=158249 ;
--
-- Table structure for table qitz3_reviews
CREATE TABLE IF NOT EXISTS `qitz3_reviews` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`property_id` int(11) NOT NULL,
`title` varchar(150) NOT NULL,
`review_text` varchar(4000) NOT NULL,
`date` date NOT NULL,
`rating` int(11) NOT NULL,
`guest_name` varchar(75) NOT NULL,
`guest_email` varchar(150) NOT NULL,
`state` tinyint(3) NOT NULL DEFAULT '0',
`published` tinyint(1) NOT NULL DEFAULT '0',
`created` datetime NOT NULL,
`created_by` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `Property ID` (`property_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=921 ;
--
-- Table structure for table qitz3_tariffs
CREATE TABLE IF NOT EXISTS `qitz3_tariffs` (
`tariff_id` int(11) NOT NULL AUTO_INCREMENT,
`id` int(11) NOT NULL COMMENT 'Denotes the property listing ID',
`start_date` date NOT NULL,
`end_date` date NOT NULL,
`tariff` int(11) NOT NULL COMMENT 'Price per booking period between the dates specified. dated spec',
PRIMARY KEY (`tariff_id`),
KEY `Property ID` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=9267 ;
Quick play, but trying to move the subselects out from the field list.
SELECT h.id, h.parent_id, h.level, h.title as property_title, h.area, h.region, h.department, h.city, LEFT(h.description, 250) as description, h.thumbnail, h.occupancy, h.swimming, g.path, (single_bedrooms + double_bedrooms + triple_bedrooms + quad_bedrooms + twin_bedrooms) as bedrooms, c.title as location_title,
Sub1.price,
e.title as tariff_based_on, f.title as base_currency, a.title as property_type, a2.title as accommodation_type,
Sub2.reviews
FROM qitz3_classifications c
LEFT JOIN qitz3_helloworld h on c.id = h.area
LEFT JOIN qitz3_attributes_property ap ON ap.property_id = h.id
LEFT JOIN qitz3_attributes_type at ON at.id = ap.attribute_id
LEFT JOIN qitz3_attributes a ON a.id = ap.attribute_id
LEFT JOIN qitz3_attributes_property ap2 ON ap2.property_id = h.id
LEFT JOIN qitz3_attributes_type at2 ON at2.id = ap2.attribute_id
LEFT JOIN qitz3_attributes a2 ON a2.id = ap2.attribute_id
LEFT JOIN qitz3_attributes e ON e.id = h.tariff_based_on
LEFT JOIN qitz3_attributes f ON f.id = h.base_currency
LEFT JOIN qitz3_classifications g ON g.id = h.city
LEFT JOIN ( SELECT id, MIN(tariff) AS price FROM qitz3_tariffs GROUP BY id) Sub1 ON Sub1.Id = h.id
LEFT JOIN ( SELECT property_id, COUNT(*) AS reviews FROM qitz3_reviews GROUP BY property_id ) as Sub2 ON Sub2.property_id = h.id
WHERE a.attribute_type_id = 1
AND a2.attribute_type_id = 2
AND c.id = 506
AND h.expiry_date >= '2013-02-20 12:05:13'
AND h.id > 1
When you need more speed in searching data you should take a look at Solr or Sphinx. With this index servers you can index your MySQL-Data and query them.
Its much more faster then MySQL.
There's quite a lot wrong in your first query:
The first 7 LEFT JOINs should be INNER JOINs. For qitz3_attributes you should consider normalizing the data less aggressively (use multiple columns instead of multiple rows to describe the data.

Help with sorting results from database (JOIN?) in php

Im upgrading my forum a bit, and want to change the way the topics is listed.
My topics is stored in this table:
CREATE TABLE `forum_emner` (
`id` INT(10) UNSIGNED NOT NULL AUTO_INCREMENT,
`type_forum` CHAR(9) NOT NULL,
`gjengid` INT(10) UNSIGNED NULL DEFAULT '0',
`sticky` TINYINT(1) UNSIGNED NULL DEFAULT '0',
`emne` VARCHAR(255) NOT NULL,
`innlegg` TEXT NOT NULL,
`brukerid_starter` MEDIUMINT(8) UNSIGNED NOT NULL,
`startet_dato` INT(10) UNSIGNED NOT NULL,
`antall_lest` INT(10) UNSIGNED NULL DEFAULT '0',
`antall_svar` INT(10) UNSIGNED NULL DEFAULT '0',
PRIMARY KEY (`id`),
INDEX `type_forum` (`type_forum`),
INDEX `gjengid` (`gjengid`),
INDEX `sticky` (`sticky`),
INDEX `brukerid_starter` (`brukerid_starter`)
)
COLLATE='latin1_swedish_ci'
ENGINE=MyISAM
ROW_FORMAT=DEFAULT
Answers to topics is stored in this table (emneid equals id in the forum_emner table):
CREATE TABLE `forum_svar` (
`id` INT(10) UNSIGNED NOT NULL AUTO_INCREMENT,
`emneid` INT(10) UNSIGNED NOT NULL,
`brukerid_av` MEDIUMINT(8) UNSIGNED NOT NULL,
`innlegg` TEXT NOT NULL,
`dato` INT(10) UNSIGNED NOT NULL,
PRIMARY KEY (`id`),
INDEX `emneid` (`emneid`),
INDEX `brukerid_av` (`brukerid_av`)
)
COLLATE='latin1_swedish_ci'
ENGINE=MyISAM
ROW_FORMAT=DEFAULT
dato is when the answer was posted (time() in php).
What i want: I want to sort the topics after the field, dato in forum_svar. The topic with the newest answer is on the top, and so on. But if a topic is created after the top topics last answer this topic should be on the top (how a forum actually works).
I've tried myself, but its not working as it should.
SELECT *, `forum_emner`.id AS UnikTradID FROM `forum_emner`
LEFT JOIN `forum_svar` ON (`forum_emner`.id = `forum_svar`.emneid)
WHERE `forum_emner`.type_forum = :type AND `forum_emner`.sticky = 0
ORDER BY `forum_svar`.dato DESC LIMIT :p1, :p2
Any help? :)
A side note: you should use AS as I do bellow to make the query look more readable.
And you shouldn't keep your MySQL field names in something other than English. What if you hire someone not speaking your language? :)
The first thing to do is to get the newest thread ids.
We can do that with such query:
SELECT MAX(fs.id) AS LastThreadId FROM forum_svar AS fs GROUP BY fs.emneid ORDER BY LastThreadId
Now we need to join this result set with the threads to get full thread information.
So we do it like this by putting the first query as a subquery here:
SELECT fs.* FROM forum_svar AS fs LEFT JOIN (SELECT MAX(fs.id) AS LastThreadId FROM forum_svar AS fs GROUP BY fs.emneid ORDER BY LastThreadId DESC) n ON (n.LastThreadId = fs.id) WHERE n.LastThreadId IS NOT NULL
This will now get you the newest threads. Enjoy! :)
P.S. Don't forget to accept the answer if it worked out!

This query/database is not working well together

Here's a query:
SELECT
*,
COUNT(*) as `numauth`
FROM `favorites` as `f1`
INNER JOIN `story` as `s1` ON `f1`.`story_id` = `s1`.`story_id`
WHERE `f1`.`story_id` != '".addslashes($_REQUEST['storyid'])."'
AND `f1`.`story_id` != '".addslashes($_REQUEST['storyid2'])."'
AND EXISTS (
SELECT 1 FROM `favorites` as `f2`
WHERE `story_id` = '".addslashes($_REQUEST['storyid'])."'
AND `f2`.`auth_id` = `f1`.`auth_id`)
AND EXISTS (
SELECT 1 FROM `favorites` as `f3`
WHERE `story_id` = '".addslashes($_REQUEST['storyid2'])."'
AND `f3`.`auth_id` = `f1`.`auth_id`)
AND NOT EXISTS (
SELECT 1 FROM `favorites` as `f4`
WHERE `story_id` =
'".addslashes($_REQUEST['exclude'])."'
`f4`.`auth_id` = `f1`.`auth_id`)
GROUP BY `f1`.`story_id`
ORDER BY `numauth` DESC, `story_words` DESC
And here's a description of the tables...
CREATE TABLE IF NOT EXISTS `favorites` (
`fav_id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`auth_id` int(10) unsigned NOT NULL,
`story_id` int(10) unsigned NOT NULL,
PRIMARY KEY (`fav_id`),
UNIQUE KEY `auth_id_2` (`auth_id`,`story_id`),
KEY `auth_id` (`auth_id`),
KEY `story_id` (`story_id`),
KEY `fav_id` (`fav_id`,`auth_id`,`story_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1577985 ;
CREATE TABLE IF NOT EXISTS `story` (
`story_id` int(10) unsigned NOT NULL,
`story_title` varchar(255) NOT NULL,
`story_desc` text NOT NULL,
`story_authid` int(8) unsigned NOT NULL,
`story_authname` varchar(255) NOT NULL,
`story_fandom` varchar(255) NOT NULL,
`story_genre1` tinyint(2) unsigned NOT NULL,
`story_genre2` tinyint(2) unsigned NOT NULL,
`story_created` int(10) unsigned NOT NULL,
`story_updated` int(10) unsigned NOT NULL,
`story_reviews` smallint(5) unsigned NOT NULL,
`story_chapters` smallint(3) unsigned NOT NULL,
`story_rating` tinyint(2) unsigned NOT NULL,
`story_words` mediumint(7) unsigned NOT NULL,
`story_chars` varchar(255) NOT NULL,
UNIQUE KEY `story_id` (`story_id`),
KEY `story_authid` (`story_authid`),
KEY `story_fandom` (`story_fandom`),
KEY `story_authid_2` (`story_authid`,`story_fandom`),
KEY `story_id_2` (`story_id`,`story_authid`),
KEY `story_id_3` (`story_id`,`story_words`),
KEY `story_id_4` (`story_id`,`story_fandom`,`story_words`),
KEY `story_id_5` (`story_id`,`story_reviews`,`story_words`),
KEY `story_words` (`story_words`),
KEY `story_reviews` (`story_reviews`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
Now I've done a fair bit of optimizing to get the query down to this. I'm running on a dedicated server but the query is still taking 5-7 seconds, which is unacceptable. We're looking at about 800,000 records on favorites and 400,000 records on stories, and I'm lost at this point on where to look to next for improvements.
It seems a bit daunting, so even if someone can point me in the right direction I'll be happy.
EXPLAIN with sample inputs:
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY s1 ALL story_id,story_id_2,story_id_3,story_id_4,story_id... NULL NULL NULL 129429 Using where; Using temporary; Using filesort
1 PRIMARY f1 ref story_id story_id 4 fanfic_jordanl_ffrecs.s1.story_id 2 Using where
4 DEPENDENT SUBQUERY f4 eq_ref auth_id_2,auth_id,story_id auth_id_2 8 fanfic_jordanl_ffrecs.f1.auth_id,const 1 Using index
3 DEPENDENT SUBQUERY f3 eq_ref auth_id_2,auth_id,story_id auth_id_2 8 fanfic_jordanl_ffrecs.f1.auth_id,const 1 Using index
2 DEPENDENT SUBQUERY f2 eq_ref auth_id_2,auth_id,story_id auth_id_2 8 fanfic_jordanl_ffrecs.f1.auth_id,const 1 Using index
try this:
SELECT f1.*, s1.*, COUNT(*) as `numauth`
FROM `favorites` as `f1`
INNER JOIN `story` as `s1` ON `f1`.`story_id` = `s1`.`story_id`
INNER JOIN (
SELECT auth_id
FROM favorites
WHERE story_id IN ('".addslashes($_REQUEST['storyid'])."', '".addslashes($_REQUEST['storyid2'])."', '".addslashes($_REQUEST['exclude'])."')
GROUP BY auth_id
HAVING Count(IF(story_id = '".addslashes($_REQUEST['exclude'])."', 1, NULL)) = 0 AND Count(*) = 2
) fv ON f1.auth_id = fv.auth_id
WHERE `f1`.`story_id` != '".addslashes($_REQUEST['storyid'])."'
AND `f1`.`story_id` != '".addslashes($_REQUEST['storyid2'])."'
GROUP BY `f1`.`story_id`
ORDER BY `numauth` DESC, `story_words` DESC
Since you are selecting * but not grouping by auth_id, what exactly are you trying to do?
--- UPDATE
since you do not need all the fav info for the stories, this query should perform better:
SELECT s.*, fv.cnt
FROM story s
JOIN (
SELECT fv.story_id, COUNT(*) cnt
FROM favorites fv
JOIN (
SELECT auth_id
FROM favorites
WHERE story_id IN ('".addslashes($_REQUEST['storyid'])."', '".addslashes($_REQUEST['storyid2'])."', '".addslashes($_REQUEST['exclude'])."')
GROUP BY auth_id
HAVING Count(IF(story_id = '".addslashes($_REQUEST['exclude'])."', 1, NULL)) = 0 AND Count(*) = 2
) ufv ON fv.auth_id = ufv.auth_id
WHERE story_id != '".addslashes($_REQUEST['storyid'])."' AND story_id != '".addslashes($_REQUEST['storyid2'])."'
GROUP BY fv.story_id
ORDER BY COUNT(*) DESC
LIMIT 25
) fv ON s.story_id = fv.story_id
ORDER BY fv.cnt DESC, `story_words` DESC

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