The following code works :
$d1 = new DateTime("12/31/2015");
which corresponds to the 31th of December 2015.
I take out some date from a database, with the following format : day/month/year. So for example, I get :
31/12/2015 - 31th December 2015
02/06/2015 - 2nd June 2015
29/03/2015 - 29 March 2015
....
The following code didn't work :
$d2 = new DateTime("31/12/2015");
The nature of my data are : string, and I would like to get the timestamp (this is my final goal but not the matter in this case) for each of these dates.
Question : Can we initialize DateTime with day-month-year order instead of month-day-year ?
Requirement : Use of DateTime object only (older object are not allowed like date()).
You need to format your date after:
$date = DateTime::createFromFormat('M/d/Y', '12/31/2015');
echo $date->format('d-m-Y');
look at this page, it could help you:
http://php.net/manual/fr/datetime.createfromformat.php
You can also select your date in french in SQL, for example:
select date_format(leChampDate, '%d/%m/%Y') as dateFrance
Related
I have a bootstrap datepicker into one of my form where I'm displaying the date into this format :
D. d MM yyyy (displayed : Mer. 23 Janvier 2019)
Since I can't save the date into my table in this format, I get the sent value with $_REQUEST before I'm saving it into my table column and want to change its format.
I tried :
$deliverydate = $_REQUEST['delivery_date'];
$deliverydate_conv = $deliverydate->format('Y-m-d');
or
$deliverydate_conv = $deliverydate->format('Y-mm-dd');
but when I
dd($deliverydate);
the value then I get an error :
Call to a member function format() on string
I tried also :
$deliverydate = $_REQUEST['delivery_date'];
$deliverydate_conv = date("m-d-Y", strtotime($deliverydate));
A date is returned but :
01-01-1970
My code is :
public function hook_before_add(&$postdata) {
# START POPULATE the deliverydate FIELD
# QUERY
# SQL : GET the deliverydate FIELD
$deliverydate = $_REQUEST['delivery_date'];
$deliverydate_conv = date("m-d-Y", strtotime($deliverydate));
dd($deliverydate);
# UPDATE THE deliverydate FIELD WITH THE RETURNED VALUE
DB::table('orders')
->where('orderID', '=', $id)
->update(array('deliverydate' => $deliverydate_conv));
# END POPULATE the deliverydate FIELD
}
I would like to convert my code into :
2019-01-23
in order to be able to save it into my date table column.
As you're trying to parse a localized date string, you're going to need to use a class from the Intl PHP extension, make sure it's installed.
You can use the IntlDateFormatter class to define a formatter that can understand French dates. Then you tell it the date format you're using and lastly parse the date. It will produce a Unix timestamp that you can use with date().
$formatter = new IntlDateFormatter("fr_FR", IntlDateFormatter::NONE, IntlDateFormatter::NONE);
$formatter->setPattern('eee dd MMMM y');
$time = $formatter->parse("Mer. 23 Janvier 2019");
$date = date('Y-m-d', $time);
You can change the pattern to another that suits your needs using these flags: http://userguide.icu-project.org/formatparse/datetime
date() uses these as its format http://php.net/manual/en/function.date.php
And you can test the code above in this site: http://www.writephponline.com
Applied to your case, you'd need to parse $deliverydate and use its return as the second argument to date().
I have a MySQL DB table with a column named "timestamp", a type of timestamp, and attribute of on update CURRENT_TIMESTAMP and a default of CURRENT_TIMESTAMP.
If I add a record to the table, specifying other values, but not the timestamp, then the timestamp is automatically added like 2016-12-28 17:02:26.
In PHP I query the table using the following query
SELECT * FROM history WHERE user_id = 9 ORDER BY timestamp ASC
The result of the query is saved into $rows and I use a foreach to create an array with some of the other values formatted. I am attempting to format the time stamp to UK type 24-hour date time: dd/mm/yy, HH:MM:SS.
I have tried both the date() and strftime() functions as follows:
$formatted_datetime = strftime("%d %m %y %H %M %S", $row["timestamp"]);
$formatted_datetime = date("d/m/y, H:i:s", $row["timestamp"]);
Both of these result in the following notice and the date time being output incorrectly like 01 01 70 00 33 36:
Notice: A non well formed numeric value encountered in /home/ubuntu/workspace/pset7/public/history.php on line 20
I am new to PHP and MySQL and so far none of the other questions or documentation I have seen have successfully addressed performing this conversion.I do not understand why strftime() does not work, nor how to do this properly?
To do this the OO (and most flexible) way use DateTime class and use the static createFromFormat method to instantiate a new DateTime object:
$new_datetime = DateTime::createFromFormat ( "Y-m-d H:i:s", $row["timestamp"] );
Now you can use the $new_datetime object to generate any string representation you'd like by calling the object's format method:
echo $new_datetime->format('d/m/y, H:i:s');
To boot, you since you've a DateTime object you can now also to any manner of transformation (like shifting timezones or adding days), comparison (greater or less than another DateTime), and various time calculations (how many days/months/etc... between this and another DateTime).
DateTime:http://php.net/manual/en/class.datetime.php
Learn it. Love it. Live it.
Normally in MySQL date timestamp save time as YYYY-MM-DD HH:MM:SS (2016-12-20 18:36:14) formate you can easily convert them as your wish using date formate but have to convert your input to time first. Following will do the trick
$formatted_datetime = date("d/m/y, H:i:s", strtotime($row["timestamp"]));
Why not make MySQL do the work? And do you really want mm/dd/yy, not dd/mm/yy?
SELECT *, DATE_FORMAT(timestamp, '%m/%d/%y, %T') formatted_date FROM ....
Then you can extract the formatted date as $row['formatted_date'].
See https://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
The date is of timestamp type which has the following format: ‘YYYY-MM-DD HH:MM:SS’ or ‘2008-10-05 21:34:02.’
$res = mysql_query("SELECT date FROM times;");
while ( $row = mysql_fetch_array($res) ) {
echo $row['date'] . "
";
}
The PHP strtotime function parses the MySQL timestamp into a Unix timestamp which can be utilized for further parsing or formatting in the PHP date function.
Here are some other sample date output formats that may be of practical use:
echo date("F j, Y g:i a", strtotime($row["date"])); // October 5, 2008 9:34 pm
echo date("m.d.y", strtotime($row["date"])); // 10.05.08
echo date("j, n, Y", strtotime($row["date"])); // 5, 10, 2008
echo date("Ymd", strtotime($row["date"])); // 20081005
echo date('\i\t \i\s \t\h\e jS \d\a\y.', strtotime($row["date"])); // It is the 5th day.
echo date("D M j G:i:s T Y", strtotime($row["date"])); // Sun Oct 5 21:34:02 PST 2008
I would use the Carbon class and its String Formatting
$carbon = Carbon::instance('2016-12-28 17:02:26');
Then you can format it the way you want.
I am trying to check if one date is equal than the other date, but I can't get the match because the date format coming from the form turns into a different order once it gets through the "parse" code.
I need to format this date to find the match, here is a sample code to show how I am trying:
...
// $ago will give me this date: 2016-12-09 00:00:00
$ago = Carbon\Carbon::today()->addDays(2); // Todays date + 2 days
//$request->datex has the date coming from a form with this format, '12-06-2016'.
// Once a parse $request->datex here, the date gets out of order:
$my_date = Carbon\Carbon::parse($request->datex);
// it shows the date like this, 2016-09-12 00:00:00 , I need it to be on this format: 2016-12-09 00:00:00
// then I could do this:
if ( $ago$ == $my_date ) {
dd($my_date.' is equal to: '.$ago );
}else{
dd(' Not equal!');
}
...
Thanks for looking!
Change this line
$my_date = Carbon\Carbon::parse($request->datex);
with this:
$my_date = Carbon::createFromFormat('m-d-Y', $request->datex)
I've assumed that your format '12-06-2016' means DAY-MONTH-YEAR
UPDATE
Tested my solution on my machine and it works, date is recognized properly:
When
$request->datex = '12-06-2016'
then
$my_date = \Carbon\Carbon::createFromFormat('m-d-Y', $datex);
gives me date like that: public 'date' => string '2016-12-06 18:52:09.000000' (length=26)
Date has been parsed properly. The thing that I've assumed just now. These dates won't be same cause of hours, minutes, seconds and milliseconds. To fix that just we have to compare dates that way:
if ( $ago->format('Y-m-d') == $my_date->format('Y-m-d') )
//do something awesome with our equal dates
PHP expects DD-MM-YYYY or MM/DD/YYYY formats.
If you always have a MM-DD-YYYY format, you could do this before parsing:
$request->datex = str_replace('-', '/', $request->datex);
I have a PHP date in a database, for example 8th August 2011. I have this date in a strtotime() format so I can display it as I please.
I need to adjust this date to make it 8th August 2013 (current year). What is the best way of doing this? So far, I've been racking my brains but to no avail.
Some of the answers you have so far have missed the point that you want to update any given date to the current year and have concentrated on turning 2011 into 2013, excluding the accepted answer. However, I feel that examples using the DateTime classes are always of use in these cases.
The accepted answer will result in a Notice:-
Notice: A non well formed numeric value encountered......
if your supplied date is the 29th February on a Leapyear, although it should still give the correct result.
Here is a generic function that will take any valid date and return the same date in the current year:-
/**
* #param String $dateString
* #return DateTime
*/
function updateDate($dateString){
$suppliedDate = new \DateTime($dateString);
$currentYear = (int)(new \DateTime())->format('Y');
return (new \DateTime())->setDate($currentYear, (int)$suppliedDate->format('m'), (int)$suppliedDate->format('d'));
}
For example:-
var_dump(updateDate('8th August 2011'));
See it working here and see the PHP manual for more information on the DateTime classes.
You don't say how you want to use the updated date, but DateTime is flexible enough to allow you to do with it as you wish. I would draw your attention to the DateTime::format() method as being particularly useful.
strtotime( date( 'd M ', $originaleDate ) . date( 'Y' ) );
This takes the day and month of the original time, adds the current year, and converts it to the new date.
You can also add the amount of seconds you want to add to the original timestamp. For 2 years this would be 63 113 852 seconds.
You could retrieve the timestamp of the same date two years later with strtotime() first parameter and then convert it in the format you want to display.
<?php
$date = "11/08/2011";
$time = strtotime($date);
$time_future = strtotime("+2 years", $time);
$future = date("d/m/Y", $time_future);
echo "NEW DATE : " . $future;
?>
You can for instance output it like this:
date('2013-m-d', strtotime($myTime))
Just like that... or use
$year = date('Y');
$myMonthDay = date('m-d', strtotime($myTime));
echo $year . '-' . $myMonthDay;
Use the date modify function Like this
$date = new DateTime('2011-08-08');
$date->modify('+2 years');
echo $date->format('Y-m-d') . "\n";
//will give "2013-08-08"
I try to calculate the easter date in php.
echo(date("2012: t.n.Y", easter_date(2012)).'<br>'); // 2012: 30.4.2012
This date is correct for the eastern orthodox churches. But I want the normal one!
My next try with the easter_days function:
function easter($year) {
$date = new DateTime($year.'-03-21');
$date->add(new DateInterval('P'.easter_days($year).'D'));
echo $year.": ".$date->format('t.m.Y') . "<br>\n";
}
easter(2012); // 2012: 30.4.2012
Tested oh PHP 5.2.6 and 5.3.6. I also tried to change the timezone with no success.
Your date format is wrong. t is the number of days in the given month (april = 30). Use d for day of the month:
echo(date("d.m.Y", easter_date(2012)).'<br>');
// will output: 08.04.2012
btw: orthodox easter date is April 15th this year.
If you want to use the DateTime class, the following will give you a DateTime object set to Easter. Use easter_date() instead of fiddling around with easter_days():
function easter($year, $format = 'd.m.Y') {
$easter = new DateTime('#' . easter_date($year));
// if your timezone is already correct, the following line can be removed
$easter->setTimezone(new DateTimeZone('Europe/Berlin'));
return $easter->format($format);
}
echo easter(2012); // 08.04.2012
echo easter(2012, 'd.m.Y H:i'); // 08.04.2012 00:00
Timezone
Setting the timezone is only necessary when the default timezone is wrong. Must be set afterwards as it is ignored in the constructor when a unix timestamp is provided.
If left out, the DateTime constructor may produce a wrong date (e.g. 07.04.2012 22:00 for 2012 instead of 08.04.2012 00:00)