insert data into database from array - php

Question

i need to add data to database from array(table). but this POST.php is not working properly. so can you guys please give me any solution for this.
this is the error that it give.
Illegal string offset 'h_name' in C:\wamp\www\confirm\post.php on line 11
line 11 is: VALUES ('$row[h_name]', '$row[room]', '$row[nors]', '$row[nights]', '$row[euro]', '$row[date]', '09090')";
all inserted value give that error. Array to string conversion
Thank you.
</br>
<h4 id="italic">Hotel Details :</h4>
</br>
<div class="reqtable">
<table>
<tr ><td>Hotel Name</td><td>Room Type</td><td>Number of Rooms</td><td>Nights</td><td>EURO</td><td>Date</td></tr>
<tr><td><?php
include "conn.php";
$query = "SELECT h_id, h_name FROM hotels";
$result = mysqli_query($conn, $query) or die(mysqli_error($conn)); // Run your query
echo '<select name="list[h_name]" id="h_name" ">';
echo '<option value=""> Choose a Hotel </option>';
while($row = mysqli_fetch_assoc($result)) {
echo '<option value="'.$row['h_id'].'">'.$row['h_name'].'</option>';
}
echo '</select>';/
?>
</td>
<td>
<?php echo '
<select name="list[room]" id="room" >
<option value="">Choose a Room Type</option>
<option value="1">Single Room</option>
<option value="2">Double Room</option>
<option value="3">Triple Room</option>
<option value="4">Family Room</option>
<option value="5">Custom Room</option>
</select>';
?>
</td>
<td><input type="text" name="list[nors]" placeholder="Number of Rooms"></td>
<td> <input type="text" class="zxc" nname="list[nights]" placeholder="Nights"></td>
<td><input type="text" name="list[euro]" placeholder="euro"></td>
<td><input type="date" name="list[date]" placeholder="Date"></td>
<td><pre> </pre></td>
<td><input type='button' class='AddNew' value='Add new item'></td></tr>
<tr><td>Total</td><td></td><td></td><td><input name="result" id="result"></td><td></td><td></td></tr>
</table>
</div>
</br>
<input type="submit" id="submit" name="submit" value="Register" color="red" style="width: 77px; height: 50px"></div>
</form>
post.php(php process)
<?php
include "conn.php";
print_r($_POST['list']);
foreach ($_POST as $row) {
$query = "INSERT INTO reqhotels (reqh_h_name, reqh_rtype, reqh_nor, reqh_nights, reqh_euro, reqh_date, reqh_req_no)
VALUES ('$row[h_name]', '$row[room]', '$row[nors]', '$row[nights]', '$row[euro]', '$row[date]', '09090')";
$result = mysqli_query($conn, $query) or die(mysqli_error($conn));
if($result > 0) {
echo"successfull";
}
else {
echo"fail";
}
}
?>
EDIT : ported from answer to question : Aug.05
this is my html codes. (html table). in here used a jquery to add some extra rows to this table. so i want to insert all data to database.
table columns:
rq_h_name, rq_rtype, rq_nors, rq_nights, rq_euro, rq_date
<form action="post.php" method="POST" id="register-form" novalidate="novalidate">
</br>
<h4 id="italic">Hotel Details :</h4>
</br>
<div class="reqtable">
<table>
<tr >
<td>Hotel Name</td>
<td>Room Type</td>
<td>Number of Rooms</td>
<td>Nights</td>
<td>EURO</td>
<td>Date</td>
</tr>
<tr>
<td>
<?php
include "conn.php";
$query = "SELECT h_id, h_name FROM hotels";
$result = mysqli_query($conn, $query) or die(mysqli_error($conn)); // Run your query
echo '<select name="list[0][]" id="h_name" ">';
echo '<option value=""> Choose a Hotel </option>';
while($row = mysqli_fetch_assoc($result)) {
echo '<option value="'.$row['h_id'].'">'.$row['h_name'].'</option>';
}
echo '</select>';
?>
</td>
<td>
<?php echo '
<select name="list[0][]" id="room" >
<option value="">Choose a Room Type</option>
<option value="1">Single Room</option>
<option value="2">Double Room</option>
<option value="3">Triple Room</option>
<option value="4">Family Room</option>
<option value="5">Custom Room</option>
</select>';
?>
</td>
<td><input type="text" name="list[0][]" placeholder="Number of Rooms"></td>
<td> <input type="text" class="zxc" name="list[0][]" placeholder="Nights"></td>
<td><input type="text" name="list[0][]" placeholder="euro"></td>
<td><input type="date" name="list[0][]" placeholder="Date"></td>
<td><input type='button' class='AddNew' value='Add new item'></td></tr>
<tr>
<td>Total</td>
<td><input name="result" id="result"></td>
</tr>
</table>
</div>
</br>

Answer 1

probably you want to do the following
foreach ($_POST['list'] as $row) {
or similar instead of current
foreach ($_POST as $row) {
In your current manner you have an array in array so and the array could not be substituted directly to a string. I'm not sure this will exactly work, but that's the idea you shoud follow and shows the problem you have. Your code is a bit messy so I'won't guarantee you have no other errors.