I have a php script that runs via a cron job.
I have an exec command in the script like so:
exec("ps -u bob -o user:20,%cpu,cmd | awk 'NR>1' | grep vlc | tr -s ' ' | cut -d ' ' -f 2",$cpu,$return)
This gets me the cpu form a process run by a specific user, if the process exists. When run via the command line I get say 21 or nothing at all depending on if the process is running or not. However, when running vai the PHP script, I get the following:
[0] => bob 0.0 /bin/sh -c php /home/bob/restart.php bob
[1] => bob 0.0 php /home/bob/restartStream.php bob
[2] => bob 0.0 sh -c ps -u bob -o user:20,%cpu,cmd | awk NR
It seems to be returning all the recent commands executed as opposed to the result of the command executed.
I have seen some posts which show the use of 2>&1 which I believe redirects the stdin and stdout or soemthing similar. However I have tried this in my command like so:
ps -u bob -o user:20,%cpu,cmd | awk 'NR>1' | grep vlc | tr -s ' ' | cut -d ' ' -f 2 2>&1
But it does not seem to make a difference. Can any give me any pointers as to why this is occurring and what can possibly be done to resolve this.
You need to clear out $cpu before you call exec. It appends the new output to the end of the array, it doesn't overwrite it.
You can also get rid of grep, tr, and cut and do all the processing of the output in awk
$cpu = array();
exec("ps -u bob -o user:20,%cpu,cmd | awk 'NR>1 && /vlc/ && !/awk/ {print $2}'",$cpu,$return);
The !/awk/ keeps it from matching the awk line, since that contains vlc.
Related
I'm trying to wipe sensitive history commands daily off my server via Laravel scheduler
When I run this code:
$schedule->exec(`for h in $(history | grep mysql | awk '{print $1-N}' | tac) ; do history -d $h ; done; history -d $(history | tail -1 | awk '{print $1}') ; history`)->{$interval}()->emailOutputTo($email)->environments('prod');
I get this error:
⚡️ app2020 php artisan schedule:run
ErrorException
Undefined variable: h
at app/Console/Kernel.php:44
Noted that this is a perfect working command
for h in $(history | grep mysql | awk '{print $1-N}' | tac) ; do history -d $h ; done; history -d $(history | tail -1 | awk '{print $1}') ; history
Note:
I know I can achieve it by adding the command above to the crontab, but the goal is to keep all cron activities organize in the Laravel project
Since bash and PHP use $ for their variable, how would one go above and make similar bash command works ?
Any hints, I will take.
You're wrapping your command in backticks, which will both interpolate variables and execute the value as a command. You want neither of these things.
Use single quotes to build the command, and then pass it to exec().
$cmd = 'for h in $(history | grep mysql | awk \'{print $1-N}\' | tac) ;';
$cmd .= ' do history -d $h ;';
$cmd .= 'done;';
$cmd .= 'history -d $(history | tail -1 | awk \'{print $1}\') ;';
$cmd .= 'history';
$schedule
->exec($cmd)
->{$interval}()
->emailOutputTo($email)
->environments('prod');
For a somewhat more efficient approach, you might try just editing the history file directly.
$cmd = 'sed -i /mysql/d "$HOME/.bash_history"';
There's no need to erase the last entry in the file, as it's a history of interactive shell commands.
Obviously the best thing to do would be not putting "sensitive" things in the command line. For MySQL, this can be done by adding credentials to the .my.cnf file.
What i want to achieve
I want to execute some script it it's process in not started on the server. so for that i am preparing the command in shell script and executing it in single line.
Command with php variable
$cmd = "if [[ `ps auxww | grep -v grep | grep ".$process_file." | grep '".$find."'` == '' ]] ; then ".$cmd2." fi";
echo $cmd."\n";
Executed command, once variables are replaced (what will actually run on bash):
if [[ `ps auxww | grep -v grep | grep /home/new_jig.php | grep 'test_51 1714052'` == '' ]] ; then php /home/new_jig.php test_51 1714052 & fi;
executing command
exec($cmd,$out,$res);
Please note that, I have also split the problem in to two statement and execute those. But it is time consuming. It is causing problems when I have more than 2000 in list, and the command is executed for all. This takes about 1 or more than 1 minute to reach to the last number.
I want to achieve this within 10 seconds. Please help me to reach optimum output.
Thanks
Jignesh
somehow I am able to make it execute with the following command
$process_file = phpfile which executing some functionality
$cmd2 = " php ".$process_file." 1212 >/dev/null 2>/dev/null & ";
$cmd11 ="if ps -auxw | grep -v grep | grep '".$process_file."' | grep '".$find."' &> /dev/null ; then echo 1;".$cmd2."; fi";
shell_exec($cmd11." >/dev/null 2>/dev/null &");
Before this: for 1100 request the process was taking about 60+ seconds
After this: it is getting completed between 20 to 30 seconds
I have just built 3 different versions of PHP from source on an Ubuntu server (alongside NGINX and MySQL 5.7). I am looking for a way to run php --ini for the currently running version. I know I have to add the location to the file PATH in .bashrc so I don't have to add the full path.
I have added this to my .bashrc which allows me to get the currently running PHP version, which then allows me to run the command:
# parallels#ubuntu:~$ ps aux | grep php
# root 6948 0.0 0.2 153724 4620 ? Ss 16:48 0:00 php-fpm: master process (/opt/php-7.0.0/etc/php-fpm.conf)
PHP_VERSION=$(ps aux | grep -o php-[[:digit:]].[[:digit:]].[[:digit:]])
export PATH="/bin:/usr/bin:/opt/$PHP_VERSION/bin:/sbin"
It works, but I am a bash novice and I'm thinking their might be a different way to do it. Would I be correct?
PHP_VERSION=$(php -v | tail -r | tail -n 1 | cut -d " " -f 2 | cut -c 1-3)
cd /usr/local/etc/php/$PHP_VERSION/
# cd /usr/local/etc/php/7.1/
This command works while running in PHP
<?php
echo PHP_VERSION;
You can get it in bash, like
PHP_VERSION=$(php -r "echo PHP_VERSION;")
Here is all of PHP Predefined Constants
I got it to work with the following commands:
# Full version
php -v | head -n 1 | cut -d " " -f 2
# Major.Minor version
php -v | head -n 1 | cut -d " " -f 2 | cut -f1-2 -d"."
should be able to get it done with awk.
php -v | awk 'NR<=1{ print $2 }'
print the second column from the first row of input.
I want to run only one proccess at a time. So I need to check. I found there was suggestions to use exec()
so I made test functions - one which sleeps 1 minute and one which tests if process is running.
public function test($a='', $b='') {
exec("ps ax | grep 'php -q /var/www/glab/index.php ajax/test2'", $pids);
if (count($pids) > 2) {
$exists = true;
echo 'exists' . count($pids);
print_r($pids);
}
}
And I get result:
exists3Array
(
[0] => 30680 pts/8 S+ 0:00 php -q /var/www/glab/index.php ajax/test2
[1] => 30684 ? S 0:00 sh -c ps ax | grep 'php -q /var/www/glab/index.php ajax/test2'
[2] => 30686 ? S 0:00 grep php -q /var/www/glab/index.php ajax/test2
)
I did not expect 3 processes but I see its ok. Can I be sure that my function is working ok - detecting running when there is > 2, am I not missing something? For example maybe if some user will run some program on linux maybe this will not work anymore?
Or can you sugesst some check which matches only the one process, without sh and grep? I mean exact string. I was trying but cannot make it work to match only one which I am searching.
Edit:
googled bit more and found more examples, adjusted and have this:
exec ('ps -efa | grep "php -q /var/www/glab/index.php ajax/test2" |grep -v "grep " | awk "{print $10 $NF}"', $pids);
print_r($pids);
When process runs:
Array
(
[0] => darius 2046 12877 5 09:23 pts/8 00:00:00 php -q /var/www/glab/index.php ajax/test2
)
It matches now 1 processs. Could you check if this is ok, am I not missing something?
I know this is simple but I just cant figure it out.
I have a bunch of files output by "svn st" that I want php to do a syntax check on the command line.
This outputs the list of files: svn st | awk '{print $2}'
And this checks a php script: php -l somefile.php
But this, or variants of, doesn't work: svn st | php -l '{print $2}'
Any ideas? Thanks!
Use xargs:
svn st | awk '{print $2}' | xargs -L 1 php -l
The xargs -L 1 command reads items from standard input, one per line, and runs the given command for each item separately. See the xargs(1) man page for more info.