Alright, still new to Yii I am attempting to create a button in a column of CGridView. This button, when clicked, will take the user to the "view.php" page and display the information of the node they clicked on by passing in its ID.
I am frustrated that I cannot figure out how to simply add a link to the image that will direct my users. Here are some snippets of the code I have been working on for the past couple of days.
index.php
<?php echo CHtml::beginForm(); ?>
<?php
$pageSize = Yii::app()->user->getState('pageSize', Yii::app()->params['defaultPageSize']);
$this->widget('zii.widgets.grid.CGridView', array(
'id' => 'nodes-grid',
'dataProvider' => $model->search(),
'filter' => $model,
'columns' => array(
array(
'class' => 'CButtonColumn',
'template' => '{restart}',
'buttons' => array
(
'restart' => array
(
'label'=>'Restart this node',
'imageUrl'=>Yii::app()->baseUrl.'/images/refresh.png',
'options'=>array('id'=>'NB_bounce_Button'),
'url'=>array('view', 'id'=>$model->id),
)
),
),
/* 'id', */
'name',
'url',
'description',
'node_type',
'last_bounced',
//..
NodeBouncerController.php (View action)
/**
* Displays a particular model.
* #param integer $id the ID of the model to be displayed
*/
public function actionView($id) {
$this->render('view', array(
'model' => $this->loadModel($id),
));
}
The button is on the left. (Refresh green arrow)
What am I doing wrong? More specifically, am I using the buttons of CButtonColumn incorrectly? If so, how may I fix this?
My company uses: Yii v1.1.8.r3324
EDIT: [8/10/15]
It seems I may have been overcomplicating it. What I needed was to simply have an image-link that when clicked went to the view for that particular node that was clicked. Well, Gii auto-generates the particular view I needed and the code associated with it (as seen above).
My fix was to do away with the over complicated mess that I had and keep it simple. Use the template already provided for "view" and just alter it to my needs.
Like so:
/* 'id', */
array(
'class'=>'CButtonColumn',
'template'=>'{view}',
'buttons' => array
(
'view' => array
(
'label'=>'Restart this node',
'imageUrl'=>Yii::app()->baseUrl.'/images/refresh.png',
'options'=>array
(
'id'=>'NB_bounce_Button'
)
)
),
),
'name',
'url',
'description',
'node_type',
'last_bounced',
//....
It would be nice to know how to do this manually but I needed something to simply work for now and expand on it later for work.
I think the problem is url of the button. Because you did not include controllerID in the url. You should use this:
'url' => 'Yii::app()->createUrl("nodeBouncer/view", "id"=>$model->id)';
For creating url in yii, usually you should follow this pattern:
contollerID/actionID
Related
I'm developing a prestashop module and I'm trying to show a category tree in my backoffice configuration page.
I'm trying to follow this instructions below but I don't know exactly where to add this code.
It should be inside main module's php? or inside a separate .php file and call it from the main one (don't know how to do it either).
As much time I'm spending trying to figure out, how to implement the code in the link above, the more I think I'm losing my time.
I see that "use" files, and this JS, " /admin-dev/themes/new-theme/js/components/form/choice-tree.js " are not in any prestashop folders.
Well, you should invest some time and learn Symfony since this is what you need to build backend modules for Prestashop 1.7.
As a pointer, you need to create a form class extending the CommonAbstractType, add a build form method. e.g. :
public function buildForm(FormBuilderInterface $builder, array $options)
{
$this->context = Context::getContext();
$parents = [
['id_category' => 2, 'name' => 'Home', 'children' => $this->getSubCategories(1, true, 2)]
];
$builder->add('category', CategoryChoiceTreeType::class, [
'choices_tree' => $parents,
'choice_value' => 'id_category',
'choice_children' => 'children',
'choice_label' => 'name',
'disabled_values' => $disabledCategories,
'label' => 'Choose a category'
])
then add methods for retrieving the data to populate the form fields.
Then use this class in your controller and display the form:
$form = $this->createForm(YourFormForm::class);
Also add a processForm to process data.
As mentioned, this is not a copy/paste situation you need to understand the Symfony workflow.
The only way that I found to "paint" the categorytree in my configuration page is adding this code to the inputs form array:
Can anyone tell me how to retrieve users selection data to my database?
It does not work as any other form field.
array(
'type' => 'categories',
'label' => $this->l('Destination Category'),
'desc' => $this->l('Select ONE Category'),
'name' => 'CATEGORY_CATEGORY_TO',
'tree' => [
// 'selected_categories' => [],
'disabled_categories' => null,
'use_search' => false,
'use_checkbox' => false,
'id' => 'id_category_tree',
],
'required' => true
),
Well, it is SOLVED!!!! Finally it was very simple, but you must get the correct info for you particular case.
#Robertino's answer might be the best implementation, I don't know, but it became impossible to solve for me,
I uses this code below, and called $categoryTree from the form input. This input must be type=> categories_select
Thanks for your time, and for the help of another post from this forum.
$root = Category::getRootCategory();
//Generating the tree
$tree = new HelperTreeCategories('categories_1'); //The string in param is the ID used by the generated tree
$tree->setUseCheckBox(false)
->setAttribute('is_category_filter', $root->id)
->setRootCategory($root->id)
->setSelectedCategories(array((int)Configuration::get('CATEGORY_1'))) //if you wanted to be pre-carged
->setInputName('CATEGORY_1'); //Set the name of input. The option "name" of $fields_form doesn't seem to work with "categories_select" type
$categoryTree = $tree->render();
And the Form:
array(
'type' => 'categories_select',
'label' => $this->l('Category'),
'desc' => $this->l('Select Category '),
'name' => 'CATEGORY_1', //No ho podem treure si no, no passa la variable al configuration
'category_tree' => $categoryTree, //This is the category_tree called in form.tpl
'required' => true
In the index page of my site I have floating div-block with CGridView inside.
I need to use sort, filter, paging etc. options, but only via updating this only div and not refreshing the whole page.
Data rendering as it should, i'm stuck only with updating grid contents - all <a>'s have href, that sending user to specified view.
Here's the view for grid: (it's the only content of my views.users.usersGrid.php)
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider' => $model->search(),
'filter' => $model,
'ajaxUrl' => 'modules/subcntrl/usersGrid',
'ajaxUpdate' => 'users-grid',
'columns' => array(
array(
'name' => 'name',
'type' => 'raw',
'value' => 'CHtml::encode($data->name)'
),
array(
'class'=>'CButtonColumn',
),
),
));
It's called from views.users.users.php: <?php $this->actionUsersGrid(); ?>
Controller:
public function actionUsers() {
$this->renderPartial('users');
}
public function actionUsersGrid() {
if(!Yii::app()->request->isAjaxRequest) die('Url should be requested via ajax only');
$model = new Users();
$this->renderPartial('usersGrid',array(
'model' => $model,
));
}
Would appreciate any help
please use the third and fouth parameter in renderPartial method like this,
$this->renderPartial('users',array(),false,true);
it will solve your problem (setting the processOutput=true ) in the fourth parameter
please use the third and fouth parameter in renderPartial method like this,
$this->renderPartial('users',array(),false,true);
it will solve your problem (setting the processOutput=true ) in the fourth parameter
this is not working in my code. i am using like this in ma controler
$this->renderPartial('_searchQuote', array('model' => $model, 'month' => $month, 'user' => $user), false, $processOutput=false );
I am trying to use the TbEditableColumn and the type select to have a pulldown menu.
The pulldown menu I need is filled by a function that I call.
That is working for basic cases. But for a another column, the pulldown values are dependent from the row in which it is (grid-view).
So for example the function I want to call to fill the pulldown and pass the id of the current data is:
$model->getPulldownValues($data->id)
But that throws an error that the variable $data is not defined. The funny part is that outside the editable array, I can use $data as expected.
See example below:
Any ideas?
$this->widget('bootstrap.widgets.TbExtendedGridView', array(
'type' => 'striped bordered',
'id'=>'order-image-grid',
'dataProvider'=>$model->search(),
'ajaxUpdate'=>true,
'template' => "{items}\n{extendedSummary}",
'rowCssClassExpression'=>'"FMDBGridColumn".$data->order_error',
'columns'=>array(
array(
'class' => 'bootstrap.widgets.TbEditableColumn',
'name' => 'streets',
'htmlOptions'=>array('width'=>'150'),
'value' => 'CHtml::value($data, "street")',
'editable' => array(
'type' => 'select',
'source' => CHtml::listData($model->availableStreets($data->id), 'id', 'street'),
'url' => $this->createUrl('cities/editable'),
'placement' => 'right',
)
),
),
));
Try to change method "availableStreets" into getter, e.g.:
public function getAvailableStreets()
{
// we don't need to send id as parameter of method,
// we can get it directly from model
// e.g.: $id = $this->id;
//
// put your code here
}
then, in widget, use property
$model->availableStreets
instead of method
$model->availableStreets($id)
Also you can put
CHtml::listData() into your getter and use
'source' => 'availableStreets',
instead of
'source' => CHtml::listData($model->availableStreets($data->id), 'id', 'street'),
you have to consider that $data in 'value' => 'CHtml::value($data, "street")', is referring to a model object which $model->search() is providing, but $data outside of the grid is different(You haven't shared what that is).
I am dealing with the CGridView widget in Yii. I've customized most of it, but can't seem to customize the icons that appear when you click on the column headers to sort the data. (little arrows that point either up or down depending on the sort order) Also, the icons are completely gone after adding in the 'columns' option. A portion of the code in my view is below:
<?php
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$dataProvider,
'pager' => array('cssFile' => '/css/myCss.css'),
'cssFile' => '/css/myCss.css',
'summaryText' => 'Showing {start} - {end} of {count} data rows.',
'htmlOptions' => array('id' => 'grid'),
'columns' => array(
array(
'name' => 'name',
'value' => '$data->name',
),
array(
'name' => 'description',
'value' => '$data->description',
),
array(
'name' => 'date',
'value' => '$data->date',
),
),
));
?>
Yii's documentation isn't clear at all on this and there doesn't seem to be anyone (that I could find) that also has this issue.
->Also, a related question:
How would I make each row an anchor link? I need each row to be a link to view the details about the clicked row. I know that cgridview provides view, edit, and delete links at the end of the row if told to, but is it possible to get the entire row to be a single anchor link? I know how to do this manually in html, but don't know how to do this inside cgridview.
If you want to change the icon in the header of the table, you will need to override styles for classes (.grid-view table.items th a.desc and .grid-view table.items th a.asc). You can also disable visual styles for the table by specifying an option: 'cssFile'=>false and set custom styles for grid.
In order to make the entire string anchor link is likely you will need to insert into each cell of the table with the necessary link url. To do this, add the following description of an array of strings:
'columns'=>array(
...
array(
'name'=>'name',
'value'=>'CHtml::link($data->name, "#myAnchor")',
'type'=>'html'
),
...
)
I am not sure what version of Yii you're working on, but let's try this code
<?php
'columns' => array(
array(
...
'type' => 'html',
'value'=>'CHtml::tag("a",array("class"=>"your-icon-class", "href"=>"#"))',
),
I have a gridview which contains a checkbox column and also uses pagination. When I check some checkboxes in the first page and navigate to the second page and check another one in the second page, the options I checked in the first page is not retained there. Is it posssible to retain the checkbox values during pagination?
Code for Gridview is
$widget = $this->widget('zii.widgets.grid.CGridView', array(
'dataProvider' => $model->search(),
'cssFile' => Yii::app()->baseUrl . '/media/js/admin/css/admingridview.css',
//'filter' => $model,
'ajaxUpdate' => true,
'enablePagination' => true,
'columns' => array(
array(
'name' => 'id',
'header' => '#',
'value' => '$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
),
array(
'class' => 'CCheckBoxColumn',
'selectableRows' => '2',
'header' => 'Selected',
),
array(
'name' => 'fb_user_id',
'header' => 'FaceBook Id',
'value' => 'CHtml::encode($data->fb_user_id)',
),
array(
'name' => 'first_name',
'header' => 'Name',
'value' => 'CHtml::encode($data->first_name)',
),
array(
'name' => 'email_id',
'header' => 'Email',
'value' => 'CHtml::encode($data->email_id)',
),
array(
'name' => 'demo',
'type' => 'raw',
'header' => "Select",
'value' => 'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
),
));
Edit:
Extension for remembering the selected options in gridview,check this link Selgridview
Thanks to bool.dev
You could use sessions/cookies to store the checked values. I'm not very sure how to make cookies work, so i'll tell you how to do it with sessions. Specifically the user session that yii creates.
Now to use sessions we need to pass the checked (and unchecked) ids to the controller, therefore we'll modify the data being sent to the controller on every ajax update(i.e between paginations), to do this we exploit the beforeAjaxUpdate option of CGridView.
I'm also using CCheckBoxColumn instead of the following in your code(of course you can modify the solution to suit your own needs):
array(
'name' => 'demo',
'type'=>'raw',
'header' => "Select",
'value' => 'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
GridView Changes:
<?php $this->widget('zii.widgets.grid.CGridView', array(
// added id of grid-view for use with $.fn.yiiGridView.getChecked(containerID,columnID)
'id'=>'first-grid',
'dataProvider'=>$model->search(),
'cssFile' => Yii::app()->baseUrl . '/media/js/admin/css/admingridview.css',
// added this piece of code
'beforeAjaxUpdate'=>'function(id,options){options.data={checkedIds:$.fn.yiiGridView.getChecked("first-grid","someChecks").toString(),
uncheckedIds:getUncheckeds()};
return true;}',
'ajaxUpdate'=>true,
'enablePagination' => true,
'columns' => array(
array(
'name' => 'id',
'header' => '#',
'value' => '$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
),
array(
'name' => 'fb_user_id',
'header' => 'FaceBook Id',
'value' => 'CHtml::encode($data->fb_user_id)',
),
array(
'name' => 'first_name',
'header' => 'Name',
'value' => 'CHtml::encode($data->first_name)',
),
array(
'name' => 'email_id',
'header' => 'Email',
'value' => 'CHtml::encode($data->email_id)',
),
/* replaced the following with CCheckBoxColumn
array(
'name' => 'demo',
'type'=>'raw',
'header' => "Select",
'value' =>'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
*/
array(
'class' => 'CCheckBoxColumn',
'selectableRows' => '2',
'header'=>'Selected',
'id'=>'someChecks', // need this id for use with $.fn.yiiGridView.getChecked(containerID,columnID)
'checked'=>'Yii::app()->user->getState($data->email_id)', // we are using the user session variable to store the checked row values, also considering here that email_ids are unique for your app, it would be best to use any field that is unique in the table
),
),
));
?>
Pay special attention to the code for beforeAjaxUpdate and CCheckBoxColumn, in beforeAjaxUpdate we are passing checkedIds as a csv string of all the ids(in this case email_ids) that have been checked and uncheckedIds as a csv string of all the unchecked ids, we get the unchecked boxes by calling a function getUncheckeds(), which follows shortly. Please take note here, that when i was testing i had used an integer id field (of my table) as the unique field, and not an email field.
The getUncheckeds() function can be registered like this anywhere in the view file for gridview:
Yii::app()->clientScript->registerScript('getUnchecked', "
function getUncheckeds(){
var unch = [];
/*corrected typo: $('[name^=someChec]') => $('[name^=someChecks]') */
$('[name^=someChecks]').not(':checked,[name$=all]').each(function(){unch.push($(this).val());});
return unch.toString();
}
"
);
In the above function pay attention to the selectors and each and push function.
With that done, we need to modify the controller/action for this view.
public function actionShowGrid(){
// some code already existing
// additional code follows
if(isset($_GET['checkedIds'])){
$chkArray=explode(",", $_GET['checkedIds']);
foreach ($chkArray as $arow){
Yii::app()->user->setState($arow,1);
}
}
if(isset($_GET['uncheckedIds'])){
$unchkArray=explode(",", $_GET['uncheckedIds']);
foreach ($unchkArray as $arownon){
Yii::app()->user->setState($arownon,0);
}
}
// rest of the code namely render()
}
That's it, it should work now.
For developing that scheme you would need to know working of what happens when you navigate.
When ever you navigate to a pagination page ajax calls are made and new data is received and it is fetched from CActive Record or what ever the data source. New data is in accordance of database records or source records. when you come back to previous page again Ajax call is made and content is updated so same comes as it is in database.
what i feel is you should save data of checked items temporary and make it permanent if action is made.
You can do something like this
<script type="text/javascript">
$("input:checkbox").click(function () {
var thisCheck = $(this);
if (thisCheck.is (':checked')){
// do what you want here, the way to access the text is using the
// $(this) selector. The following code would output pop up message with
// the selected checkbox text
$(this).val());
}
});
</script>
you can save temporary storage somewhere
Also make this work on normal form submit:
I wanted to add this as a comment on bool.dev's answer, but I do not have enough reputation to do that yet. So I had to put it in a separate answer.
bool.dev, your answer is great and it works well, thanx.
However, as intended, it only works when ajax calls update the gridview. I have the gridview forming part of a form, so I wanted it to also work on normal submission of the form, otherwise the checkboxes are not loaded again when there are other validation errors on the form.
So, in ADDITION to what you did, I added hidden fields on my form e.g.:
<input type="hidden" name='checkedBox1' id='checkedBox1' value=''>
<input type="hidden" name='uncheckedBox1' id='uncheckedBox1' value=''>
Then, before submitting the form, my sumbit button runs your getChecked() and getUncheckeds() functions and store their results in the hidden fields:
if ($('#checkedBox1').length >0) {$('[name=checkedBox1]').val(getChecked());}
if ($('#uncheckedBox1').length >0) {$('[name=uncheckedBox1]').val(getUncheckeds());}
In the controller, besides from checking for $_GET['checkedIds'], you also check for $_POST['checkedBox1'] and store its values to session in the same way you do for $_GET['checkedIds'], using the same session variable.
Do the same with $_POST['uncheckedBox1'].
That should work.