What I'm trying to do:
Pull data from a database and insert it into an array
The code I'm using:
sql = "SELECT * FROM `products`, categories WHERE category = cat_ID AND pro_ID = " . $_GET['id'];
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$name = $row['pro_name'];
$cartContents[$name] = array(
"id" => $row['pro_ID'],
"name" => $row['pro_name'],
"price" => $row['price'],
"quantity" => $_GET['q']
);
}
The problem:
This does indeed take the values from the database and insert them into the array, but it replaces everything dat was in the array before this.
What I've tried:
- Replacing array(...) with [...]
- Using the following code:
$cartContents[$name]["id"] = $row['pro_ID'];
$cartContents[$name]["name"] = $row['pro_name'];
$cartContents[$name]["price"] = $row['price'];
$cartContents[$name]["quantity"] = $_GET['q'];
Any help would be greatly appreciated, thank you!
If you don't want the data to be replaced for the $cartContents[$name] just update your code like this;
$cartContents[$name][] = array(
"id" => $row['pro_ID'],
"name" => $row['pro_name'],
"price" => $row['price'],
"quantity" => $_GET['q']
);
Related
I would like to include a php function into the query loop which simply outputs all rows from a table.
This function would return another query counting the rows of individual users and would be encoded together with the first query.
The function works, if I echo the userId variable I get it right, but for a reason the count query returns null.
I could use some help, thanks!
<?php
include_once 'includes/db_connect.php';
$query = "SELECT * FROM UPLOADS";
//Creating resonse json array, with another array inside
$jsonResponse = array( "info" =>array() );
if($result = mysqli_query($mysqli, $query)) {
while($row = mysqli_fetch_assoc($result)){
$jsonRow = array(
'user' => $row['USER'],
'userId' => $row['USERID'],
'filename' => $row['FILENAME'],
'description' => $row['DESCRIPTION'],
'location' => $row['LOCATION'],
'address' => $row['ADDRESS'],
'likes' => $row['LIKES'],
'city' => $row['CITY'],
'lat' => $row['LAT'],
'lng' => $row['LNG'],
'countPost' => countUserPosts($row['USERID'])
);
//adding the $jsonRow array to the end of the "users" array as key/value
array_push($jsonResponse["info"], $jsonRow);
}
}
//encoding to json for the app
echo json_encode($jsonResponse);
function countUserPosts($userId){
$result = mysqli_query($mysqli, "SELECT count(*) FROM UPLOADS WHERE USERID = '$userId' ");
$row = mysqli_fetch_row($result);
$num = $row[0];
return $num;
}
?>
Try to inject the mysqli object inside your function paramater:
function countUserPosts($userId, $mysqli){
// ^ this one so it won't be out of scope.
$result = mysqli_query($mysqli, "SELECT count(*) FROM UPLOADS WHERE USERID = '$userId' ");
$row = mysqli_fetch_row($result);
$num = $row[0];
return $num;
}
I'm building an angular application, so I have a PHP script extracting the database data into a JSON when requested.
This is what I'm using to extract the data into an array:
$values = array();
$query = "SELECT * FROM photos ORDER BY id";
$result = $mysqli->query($query);
while ($row = $result->fetch_array(MYSQL_ASSOC)) {
array_push($values, $row);
}
json_encode($values);
But it gives no result.
After some testing, if I change json_encode($values); to print_r($values); it actually print the table array, here an extract:
Array (
[0] => Array (
[id] => 4
[title] => Feel the Moment
[views] => 6
)
It seems the script is not creating a valid array.
$query = "SELECT * FROM photos ORDER BY id";
if ($result = $this->mysqli->query($query)) {
$json = array();
while ($row = $result->fetch_assoc()) {
$json[] = $row;
}
echo json_encode($json);
}
Your while is not executing, probably because you don't have any returned values from database.
I tested this code and it works well:
$json = array();
$json[] = array(
"id" => 1,
"category" => 'a',
"tags" => 't');
$json[] = array(
"id" => 2,
"category" => 'b',
"tags" => 'tt');
echo json_encode($json);
The result is:
[{"id":1,"category":"a","tags":"t"},{"id":2,"category":"b","tags":"tt"}]
And you'd better use mysqli_fetch_row or mysqli_fetch_assoc.
Try to debug your code. You may use var_dump($result->fetch_assoc()) to see if the query has some results.
Hi I have an error when I call a function.
"Warning: Illegal string offset 'id' in C:\xampp\htdocs\blog\posts.php
on line 28
2"
function:
function get_short_posts() {
$sql = "SELECT * FROM posts ORDER by id DESC LIMIT 0, 5";
$result = mysql_query($sql);
while($row = mysql_fetch_assoc($result)) {
$timestamp = new DateTime($row['date']);
return array (
"id" => $row['id'],
"title" => $row['title'],
"content" => $row['content'],
"author" => $row['author'],
"date" => $timestamp->format('d-m-Y'),
"time" => $timestamp->format('H:i')
);
}
Call:
require_once "functions.php";
$_posts = get_short_posts();
foreach($_posts as $_post) {
echo $_post['id'];
}
You know you return after the first iteration in the get_short_posts function right, so the foreach will not work as expected.
Try:
<?php
function get_short_posts() {
$sql = "SELECT * FROM posts ORDER by id DESC LIMIT 0, 5";
$result = mysql_query($sql);
$return = array();
while($row = mysql_fetch_assoc($result)) {
$timestamp = new DateTime($row['date']);
$return[] = array (
"id" => $row['id'],
"title" => $row['title'],
"content" => $row['content'],
"author" => $row['author'],
"date" => $timestamp->format('d-m-Y'),
"time" => $timestamp->format('H:i')
);
}
return $return;
}
?>
<?php
require_once "functions.php";
foreach(get_short_posts() as $_post) {
echo $_post['id'];
}
?>
Also, Don't use mysql_* functions in new code. They are no longer maintained and are officially deprecated. See the red box? Learn about prepared statements instead, and use PDO, or MySQLi - this article will help you decide which. If you choose PDO, here is a good tutorial.
function get_short_posts() {
$sql = "SELECT * FROM posts ORDER by id DESC LIMIT 0, 5";
$result = mysql_query($sql);
while($row = mysql_fetch_assoc($result)) {
$timestamp = new DateTime($row['date']);
$data [] = array (
"id" => $row['id'],
"title" => $row['title'],
"content" => $row['content'],
"author" => $row['author'],
"date" => $timestamp->format('d-m-Y'),
"time" => $timestamp->format('H:i')
);
}
return $data;
}
you return data, so the loop stops, save your data in a array and return that array like abive code
Your code is wrong it should be as below, assuming the query is returning data as mentioned.
function get_short_posts() {
$sql = "SELECT * FROM posts ORDER by id DESC LIMIT 0, 5";
$result = mysql_query($sql);
$rows = array();
$return_data = array();
while($row = mysql_fetch_assoc($result)) {
$timestamp = new DateTime($row['date']);
$data = array (
"id" => $row['id'],
"title" => $row['title'],
"content" => $row['content'],
"author" => $row['author'],
"date" => $timestamp->format('d-m-Y'),
"time" => $timestamp->format('H:i')
);
$return_data[] = $data;
}
return $return_data ;
}
require_once "functions.php";
$posts = get_short_posts();
foreach($posts as $key=>$val) {
echo $val['id'];
}
I have an php array with presentation as follow:-
<?php
$ads = array();
$ads [] = array(
'name' => 'Apple',
'duration' => '3',
'price' => "$5"
);
$ads [] = array(
'name' => 'Orange',
'duration' => '2',
'price' => "$10"
);
$ads [] = array(
'name' => 'Banana',
'duration' => '5',
'price' => "$6"
);
and then, I would like to replace the static data with dynamic data from database:-
$sql = "SELECT * from tb_fruit order by fruit_id ASC";
$result = mysql_query($sql_approve, $conn_fruit);
while($record = mysql_fetch_array($result))
{
$fruit_id = $record['fruit_id'];
$fruit_name = $record['fruit_name '];
$fruit_price= $record['fruit_price'];
$fruit_duration= $record_approve['fruit_duration'];
}
Actually, how shall I combine the 2 presentations together? Thanks!
If you want to get a similar structure as the one that you have in the first example, you can modify your second to create a new array and append it to an existing $ads array.
$sql = "SELECT * from tb_fruit order by fruit_id ASC";
$result = mysql_query($sql_approve, $conn_fruit);
$ads = array();
while($record = mysql_fetch_array($result))
{
$ads[] = array(
'name' => $record['fruit_name'],
'price' => $record['fruit_price'],
'duration' => $record['fruit_duration']);
}
iteration over result can be modified (provided only the required attributes are fetched in the query)
$fruit = array();
while($record = mysql_fetch_array($result))
{
$fruit[] = $record;
}
may be you could use array_merge
$result = array();
$result = array_merge($ads,$fruit);
So, you want to populate your "ads" array with information from the database? It seems fairly counterintuitive seeing as mysql_fetch_array already returns a perfectly adequate associative array, but here you go:
$sql = "SELECT * from tb_fruit order by fruit_id ASC";
$result = mysql_query($sql_approve, $conn_fruit);
$ads = array();
while($record = mysql_fetch_array($result))
{
$ads[] = array (
'name' => $record['fruit_name'],
'price' => $record['fruit_price'],
'duration' => $record['fruit_duration']
);
}
If
the initial array is not just an example, but default data that you might overwrite with the db data, and
the fruit name is unique (a primary key of sorts)
then you should set the array key of the main array to that of the fruit name, so that if the db has a different value, it will automatically get overwritten but otherwise left alone. Like so:
$ads ['Apple'] = array(
'duration' => '3',
'price' => "$5"
);
$ads ['Orange'] = array(
'duration' => '2',
'price' => "$10"
);
$ads ['Banana'] = array(
'duration' => '5',
'price' => "$6"
);
$sql = "SELECT * from tb_fruit order by fruit_id ASC";
$result = mysql_query($sql_approve, $conn_fruit);
$ads = array();
while($record = mysql_fetch_array($result))
{
$ads[$record['fruit_name']]['price'] = $record['fruit_price'];
$ads[$record['fruit_name']]['duration'] = $record['fruit_duration'];
}
Now, if 'Apple' is in the db, the price and duration get overwritten, but otherwise, it stays where you set it before the query.
You could go a step further and have both the price and duration returned by the query checked for an empty value (Null, "", 0), and only set the value if it is not empty, etc. But that is more a of business logic decision.
$feeds = array();
$query = "SELECT * FROM actions WHERE user_id = '$user_id'";
$result = mysql_query($query);
while ($info = mysql_fetch_array($result)) {
$feeds[][$info['date']] = array("feed" => array($info['ID'] => $user_id));
}
$query = "SELECT * FROM follows WHERE user_id = '$id'";
$result = mysql_query($query);
while ($info = mysql_fetch_array($result)) {
$feeds[][$info['date']] = array("follow" => $info['user_id']);
}
I would like to sort that $feeds array in date format (Y-m-d H:i:s) using [$info['date']] key
How can i do that ?
thanks
EDIT:
example of what i want to see as result is
$feeds = array(
0 => array(
'<date>' => array("feed" => array("feed_id" => "user_id"));
),
1 => array(
'<date>' => array("follow" => "user_id" );
),
);
I want to group/sort them in DATE key and do sth depends on if it is FEED or FOLLOW
The best way is to do it in database (faster)!
But if you want do it in PHP, your need uksort (for sorting) + foreach (for grouping) I think