Im having this issue with this filter of a site that im developing, basically i need to put all the categories together:
enter image description here
I need to put all the categories together, that means that all the "sistema operativo" and "disco duro" options should be together, not at the end of the list (pictured). I tried to achieve this with an array_push() and the in_array function, but at the end it just displays again these last options.
Here is my code:
<?php
$filterTitle = array();
foreach($resultFiltro as $filtros){ // titulo de categoria
if (!empty($_SESSION['filterId'])){
$resultDatos = filtroCategoriasDatos($filtros['id_padre']);
$resultFiltroDos = filtroDatosEspecificosFiltros($filtros['id'], $in[0]);
}else{
$resultDatos = filtroCategoriasDatos($filtros['id_caracteristica']);
$resultFiltroDos = filtroDatosEspecificos($filtros['id_caracteristica'], $in[0]);
}
<div class="grupo_filtro">
<?php
//if(!in_array($resultDatos[0]['titulo'], $filterTitle)){ ?>
<div class="titulo_filtro">
<?php echo $resultDatos[0]['titulo'];?>
</div>
<?php array_push($filterTitle, $resultDatos[0]['titulo']);?>
<?php //} ?>
<div class="con_filtros_filtro">
<?php foreach($resultFiltroDos as $select){ ?>
<div class="filtro atributo <?php echo $class;?>" titulopadre="<?php echo $resultDatos[0]['titulo'];?>" id="<?php echo $select['id'];?>">
<?php echo $select['titulo'];?>
</div>
<?php } ?>
</div>
</div>
<?php
} ?>
i dont know if this can be fixed sorting the recordset in some way or if there is other trick that can help me with this.
thanks in advance.
I think it could be your solution
<?php
$filterTitle = array();
foreach($resultFiltro as $filtros){ // titulo de categoria
?> <div class="grupo_filtro"> <?php
if (!empty($_SESSION['filterId'])){
$resultDatos = filtroCategoriasDatos($filtros['id_padre']);
$resultFiltroDos = filtroDatosEspecificosFiltros($filtros['id'], $in[0]);
?>
<div class="titulo_filtro">
<?php echo $resultDatos[0]['titulo'];?>
</div>
<?php array_push($filterTitle, $resultDatos[0]['titulo']);
}else{
$resultDatos = filtroCategoriasDatos($filtros['id_caracteristica']);
$resultFiltroDos = filtroDatosEspecificos($filtros['id_caracteristica'], $in[0]);
?>
<div class="con_filtros_filtro">
<?php foreach($resultFiltroDos as $select){ ?>
<div class="filtro atributo <?php echo $class;?>" titulopadre="<?php echo $resultDatos[0]['titulo'];?>" id="<?php echo $select['id'];?>">
<?php echo $select['titulo'];?>
</div>
<?php } ?>
</div>
</div>
<?php
}} ?>
The problem was in the function. I added an order by and it was fixed. Thank guys for your help.
here i attach the function
function filtroDatosEspecificosFiltros($datoPadre, $in=""){
global $db;
if($in != ""){
$filtroCategoriaDos = "SELECT p.titulo, pc.id_atributo, pc.id_caracteristica, p.id, pc.id_producto FROM principal p INNER JOIN producto_caracteristica pc WHERE p.id=".$datoPadre." AND p.id=pc.id_atributo AND visible=1 AND pc.id_producto IN (".$in.") group by pc.id_atributo";
}else{
$filtroCategoriaDos = "SELECT p.titulo, pc.id_atributo, pc.id_caracteristica, p.id, pc.id_producto FROM principal p INNER JOIN producto_caracteristica pc WHERE p.id=".$datoPadre." AND p.id=pc.id_atributo AND visible=1 group by pc.id_atributo";
}
$resultDatos = $db->getAll($filtroCategoriaDos);
usort($resultDatos, function ($elem1, $elem2) {
return strcmp($elem1['titulo'], $elem2['titulo']);
});
return $resultDatos;
}
thanks for all the help.
Related
I have search webpage, but when the search is run, there is a blank first result.
<?php include "headnav.php";
$count = 0;
$sql = "SELECT * FROM lost_property";
if (!empty($_POST)) {
$name = mysqli_real_escape_string($dbconnect, htmlspecialchars($_POST['name']));
$item = mysqli_real_escape_string($dbconnect, htmlspecialchars($_POST['item']));
$area = mysqli_real_escape_string($dbconnect, htmlspecialchars($_POST['area']));
$sql = "
SELECT *
FROM lost_property
JOIN item
ON lost_property.itemID = item.itemID
JOIN area
ON lost_property.areaID = area.areaID
WHERE name LIKE '%$name%'
AND item LIKE '%$item%'
AND area LIKE '%$area%'
ORDER
BY lost_property.name ASC
";
$search_query = mysqli_query($dbconnect, $sql);
$count = mysqli_num_rows($search_query);
}
$result = $dbconnect->query($sql);
?>
<body>
<div class="form">
<h1>Search for lost property here:</h1>
<form action="" method="POST">
Name:
<input type="text" placeholder="Name" name="name">
Item type:
<select name="item" class="dropdown">
<option value="" disabled selected>Item</option>
<?php
$item_sql = "SELECT DISTINCT item FROM `lost_property`
JOIN item ON (lost_property.itemID = item.itemID)
ORDER BY item ASC
";
$item_query = mysqli_query($dbconnect, $item_sql);
$item_rs = mysqli_fetch_assoc($item_query);
do {
?>
<option value="<?php echo $item_rs['item']; ?>"><?php echo $item_rs['item']; ?></option>
<?php
} while ($item_rs = mysqli_fetch_assoc($item_query));
?>
</select>
Area (where it was found):
<select name="area" class="dropdown">
<option value="" disabled selected>Area</option>
<?php
$area_sql = "SELECT DISTINCT area FROM `lost_property`
JOIN area ON (lost_property.areaID = area.areaID)
ORDER BY area ASC
";
$area_query = mysqli_query($dbconnect, $area_sql);
$area_rs = mysqli_fetch_assoc($area_query);
do {
?>
<option value="<?php echo $area_rs['area']; ?>"><?php echo $area_rs['area']; ?></option>
<?php
} while ($area_rs = mysqli_fetch_assoc($area_query));
?>
</select>
<input type="submit" value="Search" name="btn">
</form>
</div>
<div class="gallery">
<h2>Search results:</h2>
<?php
//check for results. If there are none display error
if ($count < 1) {
?>
<div class="error">
<h1>No results were found.</h1>
</div>
<?php
} //end if
else {
do {
?>
<!-- display image and information from database and show in gallery -->
<div class="results">
<h3><?php echo $search_rs['name']; ?></h3>
<h3><?php echo $search_rs['item']; ?></h3>
<p><?php echo $search_rs['area']; ?></p>
</div>
<?php
} // end of do
while ($search_rs = mysqli_fetch_assoc($search_query));
} //end else
//if there are any display
?>
</div>
</table>
</body>
</html>
It's hard to see without any CSS, but no matter what is searched, there is always one result, but the h3 and p fields don't have any content. If there wasn't the no results error message it would pop up there too. What is causing this first result?
Use while (){}, if you use do instead it will run once first (credit to Magnus Eriksson).
It ends up like
else {
while ($search_rs = mysqli_fetch_assoc($search_query)) {
?>
<!-- display image and information from database and show in gallery -->
<div class="results">
<h3><?php echo $search_rs['name']; ?></h3>
<h3><?php echo $search_rs['item']; ?></h3>
<p><?php echo $search_rs['area']; ?></p>
</div>
<?php
} // end of do
} //end else
//if there are any display
?>
instead of
else {
do {
?>
<!-- display image and information from database and show in gallery -->
<div class="results">
<h3><?php echo $search_rs['name']; ?></h3>
<h3><?php echo $search_rs['item']; ?></h3>
<p><?php echo $search_rs['area']; ?></p>
</div>
<?php
} // end of do
while ($search_rs = mysqli_fetch_assoc($search_query));
} //end else
//if there are any display
?>
I'm trying to give structure to my code and i am facing a problem.
I'm looping through a sql query response and for each element i'm trying to retrieve other related elements. It works in my controller without problem but when i'm trying to repeat in the view I always get the same value for the related element
My controller:
<?php
include_once('class/guide.class.php');
$bdd = new DBHandler();
$req = guide::getGuides($bdd,0,5);
foreach ($req as $results => $poi)
{
$req[$results]['id'] = htmlspecialchars($poi['id']);;
$req[$results]['name'] = nl2br(htmlspecialchars($poi['name']));
$guide = new guide($results['name'],$bdd);
$guidePois = $guide->getGuidePois($poi['id']);
foreach ($guidePois as $res => $re)
{
echo $guidePois[$res]['id'];
echo $guidePois[$res]['name'];
$guidePois[$res]['id'] = htmlspecialchars($re['id']);
$guidePois[$res]['name'] = nl2br(htmlspecialchars($re['name']));
}
}
include_once('listing.php');
here, you see that I echo the ids/names of the related list of element and it works well, the output is correct for each element of the first list.
When i do it in my view:
<?php
foreach($req as $poi)
{
?>
<div class="news">
<h3>
<?php echo $poi['id']; ?>
<em>: <?php echo $poi['name']; ?></em>
</h3>
<?php foreach($guidePois as $re)
{
?>
<h4>
<?php echo $re['id']; ?>:
<?php echo $re['name']; ?>
</h4>
<?php
}
?>
</div>
<?php
}
?>
Somehow the first list output are the good elements, but for the 2nd list, i always get the related elements of the first item.
Do you have an idea ?
Thanks a lot for your help
This is because you only set:
$guidePois = $guide->getGuidePois($poi['id']);
once in the controller.
If you want it to work in the view, you need to insert this code right after the closing </h3>
<?php $guidePois = $guide->getGuidePois($poi['id']); ?>
So that $guidePois gets a new value in each iteration.
Complete view code:
<?php
foreach($req as $poi)
{
?>
<div class="news">
<h3>
<?php echo $poi['id']; ?>
<em>: <?php echo $poi['name']; ?></em>
</h3>
<?php
$guidePois = $guide->getGuidePois($poi['id']);
foreach($guidePois as $re)
{
?>
<h4>
<?php echo $re['id']; ?>:
<?php echo $re['name']; ?>
</h4>
<?php
}
?>
</div>
<?php
}
?>
Lets say I have a persons table :
forename surname age gender
--------------------------------------------
adam example 90 male
john example 90 male
If I wanted to display this information in separate divs, how could this be done? Say for example the following HTML.
<div class = "container">
<div class="wrapper">
<div class = "jumbotron">
<!-- adams data here -->
</div>
<div class = "jumbotron">
<!-- johns data here -->
</div>
</div>
</div>
I'm aware on how to query the DB to get the information into PHP variables, I'm just not sure how to dynamically display the data in separate divs.
Below is how I am getting the data
<?php
if($result = $db->query("SELECT forename,surname FROM users ")){
if($count = $result->num_rows){
while($row = $result->fetch_object()){
echo $row->forename, '<br><br>';
echo $row->surname, '<br><br>';
}
$result->free();
}
}
?>
Just wrap the div inside a loop so you'll print a div for each result row
<?php foreach($result as $r): ?>
<div class = "jumbotron">
<?php echo $r['name'] // Print fields you need ?>
</div>
<?php endforeach; ?>
EDIT: Now I can see your query. Try this:
<?php
if($result = $db->query("SELECT forename,surname FROM users ")){
if($count = $result->num_rows){
while($row = $result->fetch_object()){
?>
<div class = "jumbotron">
<?php echo $row->forename; ?><br><br>
<?php echo $row->surname; ?><br><br>
</div>
<?php
}
$result->free();
}
}
?>
Well Joe, This is a fairly simple problem that has probably been answered before.
I'll use the mysqli class of php
first create a mysqli connection object in a file for best practice then include it in your main script.
<?php
$connection = new mysqli($host_address, $username, $password, $database);
?>
include this in your main script
<?php require "path\to\connection\script"; ?>
<?php
$sql_adam = "SELECT * FROM persons WHERE forename = 'adam'";
$sql_john = "SELECT * FROM persons WHERE forename = 'john'";
$qry1 = $connection->query($sql_adam);
$qry2 = $connection->query($sql_john);
?>
<div class = "container">
<div class="wrapper">
<div class = "jumbotron">
<?php if ($qry1->num_rows >= 1){
while($adam = $qry1->fetch_assoc()){
foreach ($adam as $column => $data) {
echo "<p>$column : $data </p>";
}
}
}
</div>
<div class = "jumbotron">
<?php if ($qry2->num_rows >= 1){
while($john = $qry2->fetch_assoc()){
foreach ($john as $column => $data) {
echo "<p>$column : $data </p>";
}
}
}
</div>
</div>
</div>
Your Result should be something like
<div class = "container">
<div class="wrapper">
<div class = "jumbotron">
<p>forename : adam</p>
<p>surname : example</p>
<p>age : 90</p>
<p>gender : male</p>
</div>
<div class = "jumbotron">
<p>forename : john</p>
<p>surname : example</p>
<p>age : 90</p>
<p>gender : male</p>
</div>
</div>
</div>
I have a problem with my search.php file to render me results...
I dont get any strings of error, but when I type an existing keyword I get no results...
The format of the results are the same as viewed in my main content on the website (grid view)...
The code:
<body>
<?php include_once("analyticstracking.php") ?>
<div class='container'> <!--Start of the container-->
<div><?php include("includes/header.php"); ?></div>
<div><?php include("includes/navbar.php"); ?></div>
<div><?php include("includes/left_col.php"); ?></div>
<div class='main_col'>
<div class='main_content'>
<?php
include("includes/connect.php");
if(isset($_GET['search'])){
$search_id = $_GET['q'];
$search_query = "SELECT * FROM games WHERE game_keywords LIKE '%$search_id%'";
$run_query = mysql_query($search_query);
echo '<table>';
$games = 0;
while($search_row = mysql_fetch_array($run_query)){
// make a new row after 9 games
if($games%9 == 0) {
if($games > 0) {
// and close the previous row only if it's not the first
echo '</tr>';
}
echo '<tr>';
}
// make a new column after 3 games
if($games%3 == 0) {
if($games > 0) {
// and only close it if it's not the first game
echo '</td>';
}
echo '<td>';
}
$game_id = $search_row['game_id'];
$game_name = $search_row['game_name'];
$game_category = $search_row['game_name'];
$game_keywords = $search_row['game_name'];
$game_image = $search_row['game_image'];
?>
<div class="game_grid">
<a href="game_page.php?id=<?php echo $game_id; ?>"><img src="images/games_images/<?php echo $game_image; ?>" width="120" height="120" />
<span><?php echo $game_name; ?></span>
</div>
<?php
$games++;
}
}
?>
</table>
</div>
</div>
<div><?php include("includes/footer.php"); ?></div>
</div> <!--End of the container-->
</body>
Any idea?
EDIT:
I solved my problem, its a small mistake I made,
In the HTML form of the search I forgot to give the submit button: "name="search", I removed it accidently... now everything works perfectly :)
You have a typo in code
change code as below
if(isset($_GET['search'])){
$search_id = $_GET['search']; //$_GET['q'];
.
.
.
}
I solved my problem, its a small mistake I made, In the HTML form of the search I forgot to give the submit button: "name="search", I removed it accidentally... now everything works perfectly :)
How could I find the last post and NOT put <hr> below it?
<?php foreach($db->query("SELECT * FROM news") as $row): ?>
<div class="NewsHeadline">
<div class="NewsDate"><?php echo $date; ?> - </div>
<div class="NewsTitle"><?php echo $title; ?></div>
</div>
<div class="NewsBody">
<?php echo $body; ?>
</div>
<hr>
<?php endforeach ?>
Set a counter equal to 1 which increments each round, and check if it is equal to the count() of the $query array returned. If it is, you are on the last round!
<?php
$counter = 1;
$total = count($db->query("SELECT * FROM news"));
?>
<?php foreach($db->query("SELECT * FROM news") as $row): ?>
<div class="NewsHeadline">
<div class="NewsDate"><?php echo $date; ?> - </div>
<div class="NewsTitle"><?php echo $title; ?></div>
</div>
<div class="NewsBody">
<?php echo $body; ?>
</div>
<?php if($counter != $total){
?>
<hr>
<?php
}
?>
<?php $counter++; ?>
<?php endforeach ?>
A solution would be to build an array and then use join :
<?php
$arr=array();
foreach($db->query("SELECT * FROM news") as $row):
$arr[] = '<div class="NewsHeadline"><div class="NewsDate">'.$date
.' - </div><div class="NewsTitle">'.$title'
.</div></div><div class="NewsBody">'.$body.'</div>';
endforeach
echo join("<hr>",$arr);
?>
You can convert to regular for loop and then compare $i to the size of your query result:
<?php
$news = $db->query("SELECT * FROM news");
for($i=0; $i<sizeof($news);$i++){ ?>
<div class="NewsHeadline">
<div class="NewsDate"><?php echo $date; ?> - </div>
<div class="NewsTitle"><?php echo $title; ?></div>
</div>
<div class="NewsBody">
<?php echo $body; ?>
</div>
<?php if(($i+1) < sizeof($news)) echo '<hr>'; ?>
<?php } ?>
If you get a count of the rows prior to the loop, you can check the count and avoid adding the HR.
$rows = $db->query("SELECT * FROM news");
$row_count = $rows.count();
$iter = 0;
foreach($rows as $row)
{
//...
if ($iter < $row_count)
{
// render hr
}
$iter++;
}
You could also go with a pure CSS approach:
div.containerClass:last-child hr { display:none; }
where "containerClass" would be whatever element your posted code sits inside of.